結果

問題 No.2574 Defect-free Rectangles
ユーザー 👑 AngrySadEight
提出日時 2023-12-01 08:36:41
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 917 ms / 2,000 ms
コード長 1,164 bytes
コンパイル時間 355 ms
コンパイル使用メモリ 82,500 KB
実行使用メモリ 222,332 KB
最終ジャッジ日時 2024-09-26 15:11:42
合計ジャッジ時間 6,684 ms
ジャッジサーバーID
(参考情報)
judge3 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
other AC * 17
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

from collections import deque
H, W, N = map(int, input().split())
A = []
B = []
for i in range(N):
a, b = map(int, input().split())
A.append(a - 1)
B.append(b - 1)
c = [[0 for _ in range(W)] for _ in range(H)]
for i in range(N):
c[A[i]][B[i]] = 1
length = [[0 for _ in range(W)] for _ in range(H)]
for j in range(W):
if c[H - 1][j] == 0:
length[H - 1][j] = 1
else:
length[H - 1][j] = 0
for i in reversed(range(H - 1)):
for j in range(W):
if c[i][j] == 0:
length[i][j] = length[i + 1][j] + 1
else:
length[i][j] = 0
# print(length)
ans = 0
dq = deque()
dq.append([-1, -1])
now = 0
for i in range(H):
for j in range(W):
idx = j
while True:
if len(dq) == 0:
break
height, width = dq.pop()
if height < length[i][j]:
dq.append([height, width])
break
now -= height * width
idx -= width
now += length[i][j] * (j - idx + 1)
ans += now
dq.append([length[i][j], j - idx + 1])
while len(dq):
dq.pop()
now = 0
print(ans)
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0