結果

問題 No.2562 数字探しゲーム（緑以下コンver.）
ユーザー 👑 AngrySadEight
提出日時 2023-12-01 15:12:22
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
RE  
(最新)
AC  
(最初)
実行時間 -
コード長 4,249 bytes
コンパイル時間 19,240 ms
コンパイル使用メモリ 262,056 KB
最終ジャッジ日時 2025-02-18 02:56:50
ジャッジサーバーID
（参考情報） 		judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 9 RE * 1
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <algorithm>
#include <atcoder/all>
#include <bitset>
#include <cassert>
#include <cmath>
#include <ctime>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using namespace atcoder;
typedef long long ll;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repr(i, n) for (int i = (int)(n)-1; i >= 0; i--)
#define repk(i, k, n) for (int i = k; i < (int)(n); i++)
#define all(v) v.begin(), v.end()
#define mod1 1000000007
#define mod2 998244353
#define mod3 100000007
#define vi vector<int>
#define vs vector<string>
#define vc vector<char>
#define vl vector<ll>
#define vb vector<bool>
#define vvi vector<vector<int>>
#define vvc vector<vector<char>>
#define vvl vector<vector<ll>>
#define vvb vector<vector<bool>>
#define vvvi vector<vector<vector<int>>>
#define vvvl vector<vector<vector<ll>>>
#define pii pair<int, int>
#define pil pair<int, ll>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define vpii vector<pair<int, int>>
#define vpll vector<pair<ll, ll>>
#define vvpii vector<vector<pair<int, int>>>
#define vvpll vector<vector<pair<ll, ll>>>
using mint = modint998244353;
template <typename T>
void debug(T e) {
    cerr << e << endl;
}
template <typename T>
void debug(vector<T> &v) {
    rep(i, v.size()) { cerr << v[i] << " "; }
    cerr << endl;
}
template <typename T>
void debug(vector<vector<T>> &v) {
    rep(i, v.size()) {
        rep(j, v[i].size()) { cerr << v[i][j] << " "; }
        cerr << endl;
    }
}
template <typename T>
void debug(vector<pair<T, T>> &v) {
    rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; }
}
template <typename T>
void debug(set<T> &st) {
    for (auto itr = st.begin(); itr != st.end(); itr++) {
        cerr << *itr << " ";
    }
    cerr << endl;
}
template <typename T>
void debug(multiset<T> &ms) {
    for (auto itr = ms.begin(); itr != ms.end(); itr++) {
        cerr << *itr << " ";
    }
    cerr << endl;
}
template <typename T>
void debug(map<T, T> &mp) {
    for (auto itr = mp.begin(); itr != mp.end(); itr++) {
        cerr << itr->first << " " << itr->second << endl;
    }
}
void debug_out() { cerr << endl; }
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
    cerr << H << " ";
    debug_out(T...);
}
ll my_pow(ll x, ll n, ll mod) {
    // 　繰り返し二乗法．x^nをmodで割った余り．
    ll ret;
    if (n == 0) {
        ret = 1;
    } else if (n % 2 == 1) {
        ret = (x * my_pow((x * x) % mod, n / 2, mod)) % mod;
    } else {
        ret = my_pow((x * x) % mod, n / 2, mod);
    }
    return ret;
}
ll inv(ll x, ll mod) { return my_pow(x, mod - 2, mod); }
void dfs(vector<ll> &A, ll N, ll K, ll &now, ll &now_sum, ll &ans,
         vector<ll> &vec) {
    if (now == K) {
        // debug_out(now_sum);
        // debug(vec);
        if (now_sum % 998244353 <= now_sum % 998) {
            ans++;
        }
    } else {
        ll len = vec.size();
        for (ll i = vec[len - 1] + 1; i < N; i++) {
            now_sum += A[i];
            vec.push_back(i);
            now++;
            dfs(A, N, K, now, now_sum, ans, vec);
            now--;
            now_sum -= A[i];
            vec.pop_back();
        }
    }
}
int main() {
    int T;
    cin >> T;
    assert(1 <= T && T <= 10000);
    while (T--) {
        ll M;
        cin >> M;
        assert(1 <= M && M <= 1000000000);
        vector<ll> d(9);
        ll d_sum = 0;
        for (ll i = 0; i < 9; i++) {
            cin >> d[i];
            d_sum += d[i];
            assert(d[i] >= 0);
        }
        assert(d_sum <= 9);
        string Y = "";
        for (ll i = 0; i < 9; i++) {
            for (ll j = 0; j < d[i]; j++) {
                Y += (char)(i + 1 + '0');
            }
        }
        ll X = (stoll(Y)) * 1000000000LL;
        ll rem = X % M;
        if (rem == 0) {
            rem = M;
        }
        X += (M - rem);
        cout << X << endl;
    }
}
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