結果
問題 | No.2565 はじめてのおつかい |
ユーザー |
👑 ![]() |
提出日時 | 2023-12-01 15:35:35 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 183 ms / 2,000 ms |
コード長 | 4,648 bytes |
コンパイル時間 | 19,898 ms |
コンパイル使用メモリ | 270,976 KB |
最終ジャッジ日時 | 2025-02-18 02:58:19 |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 50 |
ソースコード
#pragma GCC target("avx2")#pragma GCC optimize("O3")#pragma GCC optimize("unroll-loops")#include <algorithm>#include <atcoder/all>#include <bitset>#include <cassert>#include <cmath>#include <ctime>#include <functional>#include <iomanip>#include <iostream>#include <map>#include <queue>#include <random>#include <set>#include <stack>#include <string>#include <tuple>#include <unordered_map>#include <unordered_set>#include <utility>#include <vector>using namespace std;using namespace atcoder;typedef long long ll;#define rep(i, n) for (int i = 0; i < (int)(n); i++)#define repr(i, n) for (int i = (int)(n)-1; i >= 0; i--)#define repk(i, k, n) for (int i = k; i < (int)(n); i++)#define all(v) v.begin(), v.end()#define mod1 1000000007#define mod2 998244353#define mod3 100000007#define vi vector<int>#define vs vector<string>#define vc vector<char>#define vl vector<ll>#define vb vector<bool>#define vvi vector<vector<int>>#define vvc vector<vector<char>>#define vvl vector<vector<ll>>#define vvb vector<vector<bool>>#define vvvi vector<vector<vector<int>>>#define vvvl vector<vector<vector<ll>>>#define pii pair<int, int>#define pil pair<int, ll>#define pli pair<ll, int>#define pll pair<ll, ll>#define vpii vector<pair<int, int>>#define vpll vector<pair<ll, ll>>#define vvpii vector<vector<pair<int, int>>>#define vvpll vector<vector<pair<ll, ll>>>using mint = modint998244353;template <typename T>void debug(T e) {cerr << e << endl;}template <typename T>void debug(vector<T> &v) {rep(i, v.size()) { cerr << v[i] << " "; }cerr << endl;}template <typename T>void debug(vector<vector<T>> &v) {rep(i, v.size()) {rep(j, v[i].size()) { cerr << v[i][j] << " "; }cerr << endl;}}template <typename T>void debug(vector<pair<T, T>> &v) {rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; }}template <typename T>void debug(set<T> &st) {for (auto itr = st.begin(); itr != st.end(); itr++) {cerr << *itr << " ";}cerr << endl;}template <typename T>void debug(multiset<T> &ms) {for (auto itr = ms.begin(); itr != ms.end(); itr++) {cerr << *itr << " ";}cerr << endl;}template <typename T>void debug(map<T, T> &mp) {for (auto itr = mp.begin(); itr != mp.end(); itr++) {cerr << itr->first << " " << itr->second << endl;}}void debug_out() { cerr << endl; }template <typename Head, typename... Tail>void debug_out(Head H, Tail... T) {cerr << H << " ";debug_out(T...);}ll my_pow(ll x, ll n, ll mod) {// 繰り返し二乗法.x^nをmodで割った余り.ll ret;if (n == 0) {ret = 1;} else if (n % 2 == 1) {ret = (x * my_pow((x * x) % mod, n / 2, mod)) % mod;} else {ret = my_pow((x * x) % mod, n / 2, mod);}return ret;}ll inv(ll x, ll mod) { return my_pow(x, mod - 2, mod); }vector<int> bfs(vector<vector<int>> &graph, int v, int N) {int INF = 4 * N + 3;vector<int> dis(N, INF);queue<int> que;vector<int> isvisited(N, false);dis[v] = 0;isvisited[v] = true;que.push(v);while (que.size()) {int p = que.front();que.pop();for (int x : graph[p]) {if (isvisited[x]) {continue;}isvisited[x] = true;dis[x] = dis[p] + 1;que.push(x);}}return dis;}int main() {int N, M;cin >> N >> M;assert(3 <= N && N <= 100000);int min_m;if (N >= 1000) {min_m = 100000;} else {min_m = min(100000, N * (N - 1));}assert(0 <= M && M <= min_m);vector<vector<int>> graph(N, vector<int>(0));vector<int> u(M);vector<int> v(M);map<pii, int> mp;for (int i = 0; i < M; i++) {cin >> u[i] >> v[i];assert(1 <= u[i] && u[i] <= N);assert(1 <= v[i] && v[i] <= N);u[i]--;v[i]--;graph[u[i]].push_back(v[i]);assert(u[i] != v[i]);assert(mp[pii(u[i], v[i])] == 0);mp[pii(u[i], v[i])]++;}int INF = 4 * N + 2;vector<int> dist1 = bfs(graph, 0, N);vector<int> distn1 = bfs(graph, N - 2, N);vector<int> distn = bfs(graph, N - 1, N);// debug(dist1);// 1 -> n - 1 -> n -> 1int ans1 = dist1[N - 2] + distn1[N - 1] + distn[0];// 1 -> n -> n - 1 -> 1int ans2 = dist1[N - 1] + distn[N - 2] + distn1[0];int ans = min(ans1, ans2);if (ans >= INF) {cout << -1 << endl;} else {cout << ans << endl;}}