結果
問題 | No.2558 中国剰余定理 |
ユーザー | cumene_rx |
提出日時 | 2023-12-02 14:33:28 |
言語 | C++23 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 32 ms / 2,000 ms |
コード長 | 3,486 bytes |
コンパイル時間 | 5,211 ms |
コンパイル使用メモリ | 315,804 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-09-26 16:49:59 |
合計ジャッジ時間 | 6,236 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 10 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 32 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 8 ms
5,376 KB |
testcase_09 | AC | 2 ms
5,376 KB |
testcase_10 | AC | 5 ms
5,376 KB |
testcase_11 | AC | 6 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 3 ms
5,376 KB |
testcase_16 | AC | 10 ms
5,376 KB |
testcase_17 | AC | 2 ms
5,376 KB |
testcase_18 | AC | 11 ms
5,376 KB |
testcase_19 | AC | 14 ms
5,376 KB |
testcase_20 | AC | 4 ms
5,376 KB |
testcase_21 | AC | 7 ms
5,376 KB |
testcase_22 | AC | 2 ms
5,376 KB |
testcase_23 | AC | 2 ms
5,376 KB |
testcase_24 | AC | 11 ms
5,376 KB |
testcase_25 | AC | 11 ms
5,376 KB |
testcase_26 | AC | 3 ms
5,376 KB |
testcase_27 | AC | 2 ms
5,376 KB |
testcase_28 | AC | 7 ms
5,376 KB |
testcase_29 | AC | 2 ms
5,376 KB |
testcase_30 | AC | 4 ms
5,376 KB |
testcase_31 | AC | 3 ms
5,376 KB |
ソースコード
#include <bits/stdc++.h> #include <atcoder/all> #include <random> using namespace std; using namespace atcoder; typedef long long ll; typedef unsigned long long ull; using mint9 = modint998244353; using mint1 = modint1000000007; //using mint = modint; const ll INF = 1000000007; const ll LINF = INF * INF; //const long long LLMAX = 9223372036854775807; const long long LLMAX = 100000000000000000; const double TIME_1 = 1.5; //const ll MOD = 998244353; std::mt19937 get_rand_mt; #define PA pair<int,int> #define PAL pair<ll,ll> #define TP tuple<int,int,int> #define TPL tuple<ll, ll, ll> #define rep(i, z, n) for(int i = z; i < n; i++) #define repl(i, z, n) for(ll i = z; i < n; i++) #define revrep(i, z, n) for(int i = n - 1; i >= z; i--) #define revrepl(i, z, n) for(ll i = n - 1; i >= z; i--) #define all(v) v.begin(), v.end() #define rall(v) v.rbegin(), v.rend() #define SZ(x) ((int)(x).size()) #define PB push_back #define YN(T) if(T){cout<<"Yes"<<endl;}else{cout<<"No"<<endl;} #define YN2(T) if(T){cout<<"YES"<<endl;}else{cout<<"NO"<<endl;} #define OK cout << "OK" << endl; #define FX(x) cout << fixed << setprecision(10) << x << endl; #define shuffle(x) shuffle(all(x), get_rand_mt) #define PQ priority_queue<int,vector<int>,greater<int>> #define PQL priority_queue<ll,vector<ll>,greater<ll>> #define PQPA priority_queue<PA,vector<PA>,greater<PA>> template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; } template<class T>T ceilX(T a, T b) {return (a + b - 1)/b; } ll lmax(ll a, ll b){if(a>b) return a; return b;} ll lmin(ll a, ll b){if(a>b) return b; return a;} ll comb(ll X, ll Y){ll res = 1LL;ll R = X;repl(i, 1LL, lmin(Y + 1LL, X - Y + 1LL)){res *= (R - i + 1LL);res /= i;}return res;} template<class T>void Rekkyo(vector<T> X){cout<<"Rekkyo"<<endl;for(auto Y:X){cout<<Y<<" ";}cout<<endl<<"end"<<endl;} template<class T>void Rekkyo1(vector<T> X){cout<<"Rekkyo1"<<endl;int cnt=0;for(auto Y:X){cout<<cnt<<" "<<Y<<endl;cnt++;}cout<<"end"<<endl;} template<class T>void Rekkyo2(vector<vector<T>> X){cout<<"Rekkyo2"<<endl;for(auto Y:X){for(auto Z:Y){cout <<Z<<" ";}cout<<endl;}cout<<"end"<<endl;} vector<int> Eratosthenes(const int N){ vector<bool> is_prime(N + 1); rep(i, 0, N + 1) is_prime[i] = true; vector<int> P; rep(i, 2, N + 1){ if(is_prime[i]){ for( int j = 2 * i; j <= N; j += i ) is_prime[ j ] = false; P.emplace_back(i); } } return P; } vector<vector<int>> make_edge(vector<int> u, vector<int> v, bool angle){ int N = u.size(); vector<vector<int>> res; rep(i, 0, N){res[u[i]].PB(v[i]);if(!angle) res[v[i]].PB(u[i]);} return res; } vector<vector<PA>> make_edge(vector<int> u, vector<int> v, vector<int> w, bool angle){ int N = u.size(); vector<vector<PA>> res; rep(i, 0, N){res[u[i]].PB(PA(v[i], w[i]));if(!angle) res[v[i]].PB(PA(u[i], w[i]));} return res; } vector<vector<PAL>> make_edgeL(vector<int> u, vector<int> v, vector<ll> w, bool angle){ int N = u.size(); vector<vector<PAL>> res; rep(i, 0, N){res[u[i]].PB(PAL(v[i], w[i]));if(!angle) res[v[i]].PB(PAL(u[i], w[i]));} return res; } int main(){ int A, B, a, b; cin >> A >> B >> a >> b; rep(i, 0, 10000000){ int aa = i % A; int bb = i % B; if((aa == a)&&(bb == b)){ cout << i << endl; return 0; } } }