結果

問題 No.2566 美しい整数列
ユーザー evima
提出日時 2023-12-02 15:08:58
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 344 ms / 2,000 ms
コード長 6,029 bytes
コンパイル時間 3,328 ms
コンパイル使用メモリ 222,660 KB
最終ジャッジ日時 2025-02-18 04:17:30
ジャッジサーバーID
（参考情報） 		judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 21
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

// Enjoy your stay. Code by evima
#include <atcoder/modint>
#include <atcoder/segtree>
using namespace atcoder;
using mint = modint998244353;  // modint;
#include <bits/stdc++.h>
using namespace std;
using ld = long double;
using ll = long long;
using lll = __int128;
using pl = pair<ll, ll>;
using vl = vector<ll>;
using vm = vector<mint>;
using vp = vector<pl>;
using vs = vector<string>;
using vvl = vector<vl>;
using LOOPVAR_TYPE = ll;
#define all(x) (x).begin(), (x).end()
#define mset(a, v) memset(a, v, sizeof(a))
#define sq(x) ((x) * (x))
#define sz(x) ll((x).size())
#define GET_MACRO(_1, _2, _3, _4, NAME, ...) NAME
#define rep1(i, n) rep2(i, 0, n)
#define rep2(i, a, b) \
    for (LOOPVAR_TYPE i = LOOPVAR_TYPE(a); i < LOOPVAR_TYPE(b); i++)
#define rep3(i, a, b, c)                   \
    for (LOOPVAR_TYPE i = LOOPVAR_TYPE(a); \
         (c) > 0 ? i < LOOPVAR_TYPE(b) : i > LOOPVAR_TYPE(b); i += (c))
#define rep(...) GET_MACRO(__VA_ARGS__, rep3, rep2, rep1)(__VA_ARGS__)
#define eb emplace_back
#define fir first
#define sec second
#define mp make_pair
#define mt make_tuple
const int PREC = 20;
const ld EPS = 1e-9;
const ld PI = 3.14159265358979323846L;
const ll INF = 1070000000LL;
const ll MOD = 998244353LL;  // 1000000007LL;
const ll inf = 4.07e18;
const string IMPOSSIBLE = "IMPOSSIBLE";
const string POSSIBLE = "POSSIBLE";
void fast_io() {
    cin.tie(NULL);
    ios_base::sync_with_stdio(false);
}
ll lin() {
    ll x;
    cin >> x;
    return x;
}
string input() {
    string s;
    cin >> s;
    return s;
}
vl vin(int n) {
    vl v(n);
    rep(i, n) cin >> v[i];
    return v;
}
vs vsin(int n) {
    vs v(n);
    rep(i, n) cin >> v[i];
    return v;
}
vvl vvin(int n, int m) {
    vvl w(n, vl(m));
    rep(i, n) rep(j, m) cin >> w[i][j];
    return w;
}
vvl vvin(int n) { return vvin(n, n); }
template <typename T>
vector<T> cat(vector<T> v, const vector<T>& w) {
    for (T x : w) v.eb(x);
    return v;
}
template <typename T>
bool chmin(T& a, const T& b) {
    return (b < a) ? (a = b, true) : false;
}
template <typename T>
bool chmax(T& a, const T& b) {
    return (a < b) ? (a = b, true) : false;
}
template <typename T>
map<T, ll> freq(const vector<T>& v) {
    map<T, ll> ret;
    for (T x : v) ++ret[x];
    return ret;
}
template <typename T>
vector<T> reversed(vector<T> v) {
    reverse(all(v));
    return v;
}
template <typename T>
vector<T> sorted(vector<T> v) {
    sort(all(v));
    return v;
}
template <typename T>
vector<T> sub(const vector<T>& v, int from, int to) {
    vector<T> ret;
    copy(&v[from], &v[to], back_inserter(ret));
    return ret;
}
template <typename T>
string str(const T& x) {
    stringstream ss;
    ss << setprecision(PREC);
    ss << x;
    return ss.str();
}
string str(const mint& x) { return str(x.val()); }
template <typename Tuple, size_t... I>
array<int, sizeof...(I)> str_tuple_impl(stringstream& ss, Tuple&& t,
                                        index_sequence<I...>) {
    return {{(void(ss << str(get<I>(t)) << " "), 0)...}};
}
template <typename Tuple>
string str_tuple(Tuple&& t) {
    stringstream ss;
    ss << setprecision(PREC);
    str_tuple_impl(ss, forward<Tuple>(t),
                   make_index_sequence<tuple_size<decay_t<Tuple>>::value>{});
    string s = ss.str();
    if (s.size() > 0) s.pop_back();
    return s;
}
template <typename T, typename U>
string str(const pair<T, U>& p) {
    return str_tuple(p);
}
template <typename... T>
string str(const tuple<T...>& t) {
    return str_tuple(t);
}
template <typename T>
string str(const vector<T>& v) {
    stringstream ss;
    ss << setprecision(PREC);
    rep(i, sz(v)) ss << str(v[i]) << (i < sz(v) - 1 ? " " : "");
    return ss.str();
}
template <typename T>
T sum(const vector<T>& v) {
    return accumulate(all(v), 0LL);
}
template <typename T>
vector<vector<T>> trans(const vector<vector<T>>& w) {
    int n = sz(w), m = sz(w[0]);
    vector<vector<T>> ret(m, vector<T>(n));
    rep(i, m) rep(j, n) ret[i][j] = w[j][i];
    return ret;
}
vector<string> trans(const vector<string>& w) {
    int n = sz(w), m = sz(w[0]);
    vector<string> ret(m, string(n, ' '));
    rep(i, m) rep(j, n) ret[i][j] = w[j][i];
    return ret;
}
template <typename T>
void print1(T&& x, const string& end) {
    cout << str(x) << end;
}
void pr() { print1("", ""); }
template <typename T, typename... U>
void pr(T&& head, U&&... tail) {
    print1(head, "");
    pr(forward<U>(tail)...);
}
void print() { print1("", "\n"); }
template <typename T, typename... U>
void print(T&& head, U&&... tail) {
    print1(head, " ");
    print(forward<U>(tail)...);
}
template <typename T>
void eprint1(T&& x, const string& end) {
    cerr << str(x) << end;
}
void eprint() { eprint1("", "\n"); }
template <typename T, typename... U>
void eprint(T&& head, U&&... tail) {
    eprint1(head, " ");
    eprint(forward<U>(tail)...);
}
template <typename... T>
void quit(T&&... x) {
    print(forward<T>(x)...);
    exit(0);
}
void yn(bool cnd) {
    if (cnd)
        print("Yes");
    else
        print("No");
}
template <typename T, typename U>
void yn(bool cnd, T&& yes, U&& no) {
    if (cnd)
        print(yes);
    else
        print(no);
}
void zip(vl& v) {
    vl w = v;
    sort(all(w));
    int n = unique(all(w)) - w.begin();
    for (ll& x : v) x = lower_bound(&w[0], &w[n], x) - &w[0];
}
vl zipped(vl v) {
    zip(v);
    return v;
}
map<ll, ll> zipmap(vl v) {
    map<ll, ll> ret;
    sort(all(v));
    v.erase(unique(all(v)), v.end());
    rep(i, sz(v)) ret[v[i]] = i;
    return ret;
}
void init(){};
void solveOne() {
    ll N, M;
    cin >> N >> M;
    vl A = vin(N);
    vl B = vin(M);
    vl C = vin(N);
    vl sum(N);
    rep(i, N - 1) sum[i + 1] = sum[i] + B[i % M];
    ll total = accumulate(all(C), 0LL);
    unordered_map<ll, ll> m;
    ll mx = 0;
    rep(i, N) chmax(mx, m[A[i] - sum[i]] += C[i]);
    print(total - mx);
}
int main() {
    int T=1;
    //cin >> T;
    init();
    rep(i, 1, T + 1) {
        //cout << "Case #" << i << ": ";
        solveOne();
    }
}
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