結果

問題 No.2564 衝突予測
ユーザー 👑 binap
提出日時 2023-12-02 15:29:04
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 2,134 bytes
コンパイル時間 4,214 ms
コンパイル使用メモリ 250,472 KB
最終ジャッジ日時 2025-02-18 04:38:38
ジャッジサーバーID
（参考情報） 		judge2 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 4 WA * 5
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘void solve()’:
main.cpp:36:9: warning: ‘z1’ may be used uninitialized [-Wmaybe-uninitialized]
   36 |         if(z1 == z2){
      |         ^~
main.cpp:29:13: note: ‘z1’ was declared here
   29 |         int z1, z2;
      |             ^~
main.cpp:36:9: warning: ‘z2’ may be used uninitialized [-Wmaybe-uninitialized]
   36 |         if(z1 == z2){
      |         ^~
main.cpp:29:17: note: ‘z2’ was declared here
   29 |         int z1, z2;
      |                 ^~

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return 
    os;}
template <typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); 
    return os;}
string t = "RLUD";
void solve(){
    pair<long long, long long> p1, p2;
    long long x1, y1, x2, y2;
    char c1, c2;
    cin >> p1.first >> p1.second >> c1;
    cin >> p2.first >> p2.second >> c2;
    int z1, z2;
    rep(i, 4){
        if(c1 == t[i]) z1 = i;
    }
    rep(i, 4){
        if(c2 == t[i]) z2 = i;
    }
    if(z1 == z2){
        cout << "No\n";
        return;
    }
    if(z1 + z2 == 1){
        if(z2 == 0){
            swap(p1, p2);
            swap(z1, z2);
        }
        if(p1.second == p2.second) cout << "Yes\n";
        else cout << "No\n";
        return;
    }
    if(z1 + z2 == 5){
        if(z2 == 2){
            swap(p1, p2);
            swap(z1, z2);
        }
        if(p1.first == p2.first) cout << "Yes\n";
        else cout << "No\n";
        return;
    }
    if(z1 == 2 or z1 == 3){
        swap(p1, p2);
        swap(z1, z2);
    }
    if(z1 == 1){
        p1.first *= -1;
        p2.first *= -1;
        z1 = 0;
    }
    if(z2 == 3){
        p1.second *= -1;
        p2.second *= -1;
        z2 = 2;
    }
    if(p1.first + p1.second == p2.first + p2.second){
        if(p1.first < p2.first) cout << "Yes\n";
        else cout << "No\n";
    }else cout << "No\n";
    return;
}
int main(){
    int t;
    cin >> t;
    rep(_, t) solve();
    
    return 0;
}
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