結果
問題 | No.2567 A_1 > A_2 > ... > A_N |
ユーザー | hibit_at |
提出日時 | 2023-12-02 15:45:17 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,390 bytes |
コンパイル時間 | 1,200 ms |
コンパイル使用メモリ | 111,044 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-09-26 19:12:53 |
合計ジャッジ時間 | 3,341 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
5,248 KB |
testcase_01 | WA | - |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | AC | 161 ms
5,376 KB |
testcase_07 | AC | 156 ms
5,376 KB |
testcase_08 | AC | 151 ms
5,376 KB |
testcase_09 | AC | 153 ms
5,376 KB |
testcase_10 | AC | 157 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 2 ms
5,376 KB |
testcase_16 | AC | 2 ms
5,376 KB |
ソースコード
#include <algorithm> #include <iostream> #include <iomanip> #include <limits.h> #include <map> #include <math.h> #include <numeric> #include <queue> #include <set> #include <sstream> #include <string> #include <utility> #include <vector> #include <stack> #include <complex> using namespace std; #define rep(i, n) for (int i = 0; i < n; i++) #define rep1(i, n) for (int i = 1; i < n + 1; i++) #define rev(i, n) for (int i = n - 1; i >= 0; i--) #define all(A) A.begin(), A.end() #define itr(A, l, r) A.begin() + l, A.begin() + r #define debug(var) cout << #var << " = " << var << endl; typedef long long ll; template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << "(" << p.first << "," << p.second << ")"; return os; } template <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; } template <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { for (int i = 0; i < (int)v.size(); i++) { os << v[i] << (i + 1 != (int)v.size() ? " " : ""); } return os; } template <typename T> ostream &operator<<(ostream &os, const vector<vector<T>> &v) { for (int i = 0; i < (int)v.size(); i++) { os << v[i] << endl; } return os; } template <typename T> ostream &operator<<(ostream &os, const vector<vector<vector<T>>> &v) { int n = v.size(); int m = v[0].size(); int p = v[0][0].size(); rep(k, p) { os << "k = " << k << endl; rep(i, n) { rep(j, m) { os << v[i][j][k]; if (j < m - 1) { os << " "; } else { os << endl; } } } } return os; } template <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; } template <typename T, typename S> ostream &operator<<(ostream &os, map<T, S> &mp) { for (auto &[key, val] : mp) { os << key << ":" << val << " "; } cout << endl; return os; } template <typename T> ostream &operator<<(ostream &os, set<T> st) { auto itr = st.begin(); for (int i = 0; i < (int)st.size(); i++) { os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; } template <typename T> ostream &operator<<(ostream &os, multiset<T> st) { auto itr = st.begin(); for (int i = 0; i < (int)st.size(); i++) { os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; } template <typename T> ostream &operator<<(ostream &os, queue<T> q) { while (q.size()) { os << q.front() << " "; q.pop(); } return os; } template <typename T> ostream &operator<<(ostream &os, deque<T> q) { while (q.size()) { os << q.front() << " "; q.pop_front(); } return os; } template <typename T> ostream &operator<<(ostream &os, stack<T> st) { while (st.size()) { os << st.top() << " "; st.pop(); } return os; } template <typename T> ostream &operator<<(ostream &os, priority_queue<T> pq) { while (pq.size()) { os << pq.top() << " "; pq.pop(); } return os; } template <typename T> ostream &operator<<(ostream &os, priority_queue<T, vector<T>, greater<T>> mpq) { while (mpq.size()) { os << mpq.top() << " "; mpq.pop(); } return os; } vector<ll> solve() { ll n, x; cin >> n >> x; if (x < n * (n + 1) / 2) { return {-1}; } ll ng = 0; ll ok = 1e9; while (abs(ng - ok) > 1) { ll mid = ng + ok; mid /= 2; ll criteria = (2 * mid + n - 1) * n / 2; if (criteria > x) { ok = mid; } else { ng = mid; } } vector<ll> ans; rep(i, n) { ans.push_back(ok + i); } // debug(ans); // debug(ok); ll possible = (2 * ok + n - 1) * n / 2; // debug(possible); rep(i, possible - x) { ans[i]--; } // debug(ans); reverse(all(ans)); return ans; } int main() { int t; cin >> t; while (t--) { cout << solve() << endl; } }