#934721 (PyPy3) No.2564 衝突予測

• 問題: No.2564 衝突予測
• ユーザー: mymelochan
• 提出日時: 2023-12-02 15:46:24
• 言語: PyPy3 (7.3.15)
• 結果: AC
• 実行時間: 395 ms / 2,000 ms
• コード長: 2,046 bytes
• コンパイル時間: 341 ms
• コンパイル使用メモリ: 82,360 KB
• 実行使用メモリ: 78,332 KB
• 最終ジャッジ日時: 2024-09-26 19:15:31
• 合計ジャッジ時間: 5,059 ms
• ジャッジサーバーID （参考情報）: judge3 / judge5

ファイルパターン	結果
sample	AC * 3
other	AC * 9

ソースコード

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#############################################################
import sys
sys.setrecursionlimit(10**7)
from heapq import heappop,heappush
from collections import deque,defaultdict,Counter
from bisect import bisect_left, bisect_right
from itertools import product,combinations,permutations
from math import sin,cos
#from math import isqrt #DO NOT USE PyPy
ipt = sys.stdin.readline
iin = lambda :int(ipt())
lmin = lambda :list(map(int,ipt().split()))
#############################################################
direc = {"U":0,"D":2,"R":1,"L":3}
for _ in range(iin()):
    i1 = input().split()
    i2 = input().split()
    x1,y1,d1 = int(i1[0]),int(i1[1]),direc[i1[2]]
    x2,y2,d2 = int(i2[0]),int(i2[1]),direc[i2[2]]
    if d1 == d2:
        print("No")
        continue
    if d1%2 == 0 and d2%2 == 0:
        if x1 == x2:
            if d1 == 0:
                if y1 < y2:
                    print("Yes")
                else:
                    print("No")
            else:
                if y1 > y2:
                    print("Yes")
                else:
                    print("No")
        else:
            print("No")
    
    elif d1%2 == 1 and d2%2 == 1:
        if y1 == y2:
            if d1 == 1:
                if x1 < x2:
                    print("Yes")
                else:
                    print("No")
            else:
                if x1 > x2:
                    print("Yes")
                else:
                    print("No")
        else:
            print("No")
    
    else:
        dx = x1-x2
        dy = y1-y2
        if dx == dy:
            if x1 < x2:
                d1,d2 = d2,d1
            if (d1 == 2 and d2 == 1) or (d1 == 3 and d2 == 0):
                print("Yes")
            else:
                print("No")
        elif dx == -dy:
            if x1 < x2:
                d1,d2 = d2,d1
            
            if (d1 == 0 and d2 == 1) or (d1 == 3 and d2 == 2):
                print("Yes")
            else:
                print("No")
        else:
            print("No")
 
 
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