結果
問題 | No.2565 はじめてのおつかい |
ユーザー |
![]() |
提出日時 | 2023-12-02 16:04:00 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 438 ms / 2,000 ms |
コード長 | 1,435 bytes |
コンパイル時間 | 331 ms |
コンパイル使用メモリ | 81,972 KB |
実行使用メモリ | 99,784 KB |
最終ジャッジ日時 | 2024-09-26 19:46:49 |
合計ジャッジ時間 | 16,591 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 50 |
ソースコード
import heapqdef dijkstra2(adjList, s, g):# Initialize the distance from the start node s to all other nodes as infinitydistance = [float('inf')] * len(adjList)distance[s] = 0# Initialize the priority queue with the start nodequeue = [(0, s)] # (distance, node)while queue:# Get the node with the smallest distancedist, node = heapq.heappop(queue)# If this node has already been processed, then ignore itif dist > distance[node]:continue# Update the distances to the neighboring nodesfor neighbor, cost in adjList[node]:new_dist = dist + costif new_dist < distance[neighbor]:distance[neighbor] = new_distheapq.heappush(queue, (new_dist, neighbor))# If the distance to the goal node g is infinity, it means there is no path.if distance[g] == float('inf'):return 1e10else:return distance[g]N, M = map(int, input().split())adj_list = [[] for _ in range(N)]for i in range(M):u, v = map(int, input().split())u -= 1v -= 1adj_list[u].append((v, 1))ans1 = dijkstra2(adj_list, 0, N-2) + dijkstra2(adj_list, N-2, N-1) + dijkstra2(adj_list, N-1, 0)ans2 = dijkstra2(adj_list, 0, N-1) + dijkstra2(adj_list, N-1, N-2) + dijkstra2(adj_list, N-2, 0)ans = min(ans1, ans2)if (ans >= 1e10):print(-1)else:print(ans)