結果
| 問題 |
No.2569 はじめてのおつかいHard
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2023-12-02 16:35:07 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 391 ms / 2,000 ms |
| コード長 | 3,473 bytes |
| コンパイル時間 | 4,593 ms |
| コンパイル使用メモリ | 272,236 KB |
| 実行使用メモリ | 31,496 KB |
| 最終ジャッジ日時 | 2025-06-20 01:55:50 |
| 合計ジャッジ時間 | 8,795 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 12 |
ソースコード
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template <typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T>
struct Edge_Dijkstra{
int from, to;
T cost;
Edge_Dijkstra(int from, int to, T cost) : from(from), to(to), cost(cost) {};
};
const long long INF = 1001001001001001;
template<typename T>
struct Dijkstra{
int n, m;
vector<bool> initialized;
vector<Edge_Dijkstra<T>> E;
vector<vector<int>> G;
map<int, vector<T>> dist;
map<int, vector<int>> idx;
Dijkstra(int _n) : n(_n), m(0), initialized(n, false), G(n){}
void add_edge(int from, int to, T cost){
Edge_Dijkstra e(from, to, cost);
E.push_back(e);
G[from].emplace_back(m);
m++;
}
void calc(int s){
initialized[s] = true;
dist[s] = vector<T>(n, INF);
idx[s] = vector<int>(n, -1);
priority_queue<tuple<T, int, int>, vector<tuple<T, int, int>>, greater<tuple<T, int, int>>> pq;
pq.emplace(0, s, -1);
while(pq.size()){
auto [cost, from, index] = pq.top(); pq.pop();
if(dist[s][from] <= cost) continue;
dist[s][from] = cost;
idx[s][from] = index;
for(int index : G[from]){
int to = E[index].to;
T cost_plus = E[index].cost;
if(dist[s][to] <= cost + cost_plus) continue;
pq.emplace(cost + cost_plus, to, index);
}
}
}
int farthest(int s){
if(!initialized[s]) calc(s);
int idx = 0;
rep(i, n) if(dist[s][i] > dist[s][idx]) idx = i;
return idx;
}
T get_dist(int s, int t){
if(!initialized[s]) calc(s);
return dist[s][t];
}
vi restore(int s, int t){
if(!initialized[s]) calc(s);
if(dist[s][t] == INF) return vi(0);
vi res;
while(idx[s][t] != -1){
auto e = E[idx[s][t]];
res.push_back(idx[s][t]);
t = e.from;
}
reverse(res.begin(), res.end());
return res;
}
};
void chmin(long long& a, long long b){
a = min(a, b);
}
int main(){
int n, m;
cin >> n >> m;
Dijkstra<long long> graph1(n), graph2(n);
rep(i, m){
int u, v;
long long t;
cin >> u >> v >> t;
u--; v--;
graph1.add_edge(u, v, t);
graph2.add_edge(v, u, t);
}
long long alpha = graph1.get_dist(n - 2, n - 1);
long long beta = graph1.get_dist(n - 1, n - 2);
rep(from, n - 2){
long long ans = INF;
chmin(ans, graph2.get_dist(n - 2, from) + alpha + graph1.get_dist(n - 1, from));
chmin(ans, graph2.get_dist(n - 1, from) + beta + graph1.get_dist(n - 2, from));
if(ans >= INF) cout << -1 << "\n";
else cout << ans <<"\n";
}
return 0;
}