結果

問題 No.2559 眩しい数直線
ユーザー PNJPNJ
提出日時 2023-12-06 00:10:49
言語 Python3
(3.12.2 + numpy 1.26.4 + scipy 1.12.0)
結果
AC  
実行時間 46 ms / 2,000 ms
コード長 5,066 bytes
コンパイル時間 177 ms
コンパイル使用メモリ 13,184 KB
実行使用メモリ 12,276 KB
最終ジャッジ日時 2024-09-27 00:39:21
合計ジャッジ時間 1,885 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
このコードへのチャレンジ
（要ログイン）

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 38 ms
11,892 KB
testcase_01 AC 37 ms
12,020 KB
testcase_02 AC 37 ms
12,020 KB
testcase_03 AC 39 ms
12,024 KB
testcase_04 AC 38 ms
12,020 KB
testcase_05 AC 40 ms
12,152 KB
testcase_06 AC 45 ms
12,148 KB
testcase_07 AC 43 ms
12,160 KB
testcase_08 AC 46 ms
12,148 KB
testcase_09 AC 42 ms
12,276 KB
testcase_10 AC 41 ms
12,032 KB
testcase_11 AC 37 ms
12,148 KB
testcase_12 AC 38 ms
12,148 KB
testcase_13 AC 44 ms
12,276 KB
testcase_14 AC 43 ms
12,276 KB
testcase_15 AC 45 ms
12,148 KB
testcase_16 AC 38 ms
12,024 KB
testcase_17 AC 42 ms
12,152 KB
testcase_18 AC 38 ms
12,148 KB
testcase_19 AC 43 ms
12,148 KB
testcase_20 AC 39 ms
12,024 KB
testcase_21 AC 38 ms
12,152 KB
testcase_22 AC 41 ms
12,148 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

import math
from bisect import bisect_left, bisect_right
from typing import Generic, Iterable, Iterator, List, Tuple, TypeVar, Optional
T = TypeVar('T')

class SortedMultiset(Generic[T]):
    BUCKET_RATIO = 16
    SPLIT_RATIO = 24
    
    def __init__(self, a: Iterable[T] = []) -> None:
        "Make a new SortedMultiset from iterable. / O(N) if sorted / O(N log N)"
        a = list(a)
        n = self.size = len(a)
        if any(a[i] > a[i + 1] for i in range(n - 1)):
            a.sort()
        bucket_size = int(math.ceil(math.sqrt(n / self.BUCKET_RATIO)))
        self.a = [a[n * i // bucket_size : n * (i + 1) // bucket_size] for i in range(bucket_size)]

    def __iter__(self) -> Iterator[T]:
        for i in self.a:
            for j in i: yield j

    def __reversed__(self) -> Iterator[T]:
        for i in reversed(self.a):
            for j in reversed(i): yield j
    
    def __eq__(self, other) -> bool:
        return list(self) == list(other)
    
    def __len__(self) -> int:
        return self.size
    
    def __repr__(self) -> str:
        return "SortedMultiset" + str(self.a)
    
    def __str__(self) -> str:
        s = str(list(self))
        return "{" + s[1 : len(s) - 1] + "}"

    def _position(self, x: T) -> Tuple[List[T], int, int]:
        "return the bucket, index of the bucket and position in which x should be. self must not be empty."
        for i, a in enumerate(self.a):
            if x <= a[-1]: break
        return (a, i, bisect_left(a, x))

    def __contains__(self, x: T) -> bool:
        if self.size == 0: return False
        a, _, i = self._position(x)
        return i != len(a) and a[i] == x

    def count(self, x: T) -> int:
        "Count the number of x."
        return self.index_right(x) - self.index(x)

    def add(self, x: T) -> None:
        "Add an element. / O(√N)"
        if self.size == 0:
            self.a = [[x]]
            self.size = 1
            return
        a, b, i = self._position(x)
        a.insert(i, x)
        self.size += 1
        if len(a) > len(self.a) * self.SPLIT_RATIO:
            mid = len(a) >> 1
            self.a[b:b+1] = [a[:mid], a[mid:]]
    
    def _pop(self, a: List[T], b: int, i: int) -> T:
        ans = a.pop(i)
        self.size -= 1
        if not a: del self.a[b]
        return ans

    def discard(self, x: T) -> bool:
        "Remove an element and return True if removed. / O(√N)"
        if self.size == 0: return False
        a, b, i = self._position(x)
        if i == len(a) or a[i] != x: return False
        self._pop(a, b, i)
        return True

    def lt(self, x: T) -> Optional[T]:
        "Find the largest element < x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] < x:
                return a[bisect_left(a, x) - 1]

    def le(self, x: T) -> Optional[T]:
        "Find the largest element <= x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] <= x:
                return a[bisect_right(a, x) - 1]

    def gt(self, x: T) -> Optional[T]:
        "Find the smallest element > x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] > x:
                return a[bisect_right(a, x)]

    def ge(self, x: T) -> Optional[T]:
        "Find the smallest element >= x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] >= x:
                return a[bisect_left(a, x)]
    
    def __getitem__(self, i: int) -> T:
        "Return the i-th element."
        if i < 0:
            for a in reversed(self.a):
                i += len(a)
                if i >= 0: return a[i]
        else:
            for a in self.a:
                if i < len(a): return a[i]
                i -= len(a)
        raise IndexError
    
    def pop(self, i: int = -1) -> T:
        "Pop and return the i-th element."
        if i < 0:
            for b, a in enumerate(reversed(self.a)):
                i += len(a)
                if i >= 0: return self._pop(a, ~b, i)
        else:
            for b, a in enumerate(self.a):
                if i < len(a): return self._pop(a, b, i)
                i -= len(a)
        raise IndexError

    def bisect(self, x: T) -> int:
        "Count the number of elements < x."
        ans = 0
        for a in self.a:
            if a[-1] >= x:
                return ans + bisect_left(a, x)
            ans += len(a)
        return ans

    def index_right(self, x: T) -> int:
        "Count the number of elements <= x."
        ans = 0
        for a in self.a:
            if a[-1] > x:
                return ans + bisect_right(a, x)
            ans += len(a)
        return ans

N,X = map(int,input().split())
G = [[] for i in range(X+1)]
P = SortedMultiset([-10**18])
Q = SortedMultiset([-10**18])
for i in range(N):
  a,b = map(int,input().split())
  G[a].append(b)
  P.add(b-a)

L = []
for x in range(1,X+1):
  res = 0
  b = P[-1]
  res = max(res,x + b)
  b = Q[-1]
  res = max(res,-x + b)
  L.append(res)
  for b in G[x]:
    P.discard(b-x)
    Q.add(b+x)
print(*L)
0