結果

問題 No.2520 L1 Explosion
コンテスト
ユーザー apricity
提出日時 2023-12-11 05:26:43
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 232 ms / 2,000 ms
コード長 5,852 bytes
コンパイル時間 1,456 ms
コンパイル使用メモリ 138,364 KB
最終ジャッジ日時 2025-02-18 10:19:09
ジャッジサーバーID
（参考情報） 		judge1 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 22
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<iostream>
#include<string>
#include<vector>
#include<algorithm>
#include<numeric>
#include<cmath>
#include<utility>
#include<tuple>
#include<cstdint>
#include<cstdio>
#include<iomanip>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<deque>
#include<unordered_map>
#include<unordered_set>
#include<bitset>
#include<cctype>
#include<chrono>
#include<random>
#include<cassert>
#include<cstddef>
#include<iterator>
#include<string_view>
#include<type_traits>

#ifdef LOCAL
#  include "debug_print.hpp"
#  define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)
#else
#  define debug(...) (static_cast<void>(0))
#endif

using namespace std;
#define rep(i,n) for(int i=0; i<(n); i++)
#define rrep(i,n) for(int i=(n)-1; i>=0; i--)
#define FOR(i,a,b) for(int i=(a); i<(b); i++)
#define RFOR(i,a,b) for(int i=(b-1); i>=(a); i--)
#define ALL(v) v.begin(), v.end()
#define RALL(v) v.rbegin(), v.rend()
#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );
#define pb push_back
using ll = long long;
using D = double;
using LD = long double;
using P = pair<int, int>;
template<typename T> using PQ = priority_queue<T,vector<T>>;
template<typename T> using minPQ = priority_queue<T, vector<T>, greater<T>>;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
void yesno(bool flag) {cout << (flag?"Yes":"No") << "\n";}

template<typename T, typename U>
ostream &operator<<(ostream &os, const pair<T, U> &p) {
    os << p.first << " " << p.second;
    return os;
}
template<typename T, typename U>
istream &operator>>(istream &is, pair<T, U> &p) {
    is >> p.first >> p.second;
    return is;
}

template<typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
    int s = (int)v.size();
    for (int i = 0; i < s; i++) os << (i ? " " : "") << v[i];
    return os;
}
template<typename T>
istream &operator>>(istream &is, vector<T> &v) {
    for (auto &x : v) is >> x;
    return is;
}
void in() {}
template<typename T, class... U>
void in(T &t, U &...u) {
    cin >> t;
    in(u...);
}
void out() { cout << "\n"; }
template<typename T, class... U, char sep = ' '>
void out(const T &t, const U &...u) {
    cout << t;
    if (sizeof...(u)) cout << sep;
    out(u...);
}
void outr() {}
template<typename T, class... U, char sep = ' '>
void outr(const T &t, const U &...u) {
    cout << t;
    outr(u...);
}

template<int mod> struct Fp {
    long long val;
    constexpr Fp(long long v = 0) noexcept : val(v % mod) {
        if (val < 0) val += mod;
    }
    constexpr int getmod() { return mod; }
    constexpr Fp operator - () const noexcept {
        return val ? mod - val : 0;
    }
    constexpr Fp operator + (const Fp& r) const noexcept { return Fp(*this) += r; }
    constexpr Fp operator - (const Fp& r) const noexcept { return Fp(*this) -= r; }
    constexpr Fp operator * (const Fp& r) const noexcept { return Fp(*this) *= r; }
    constexpr Fp operator / (const Fp& r) const noexcept { return Fp(*this) /= r; }
    constexpr Fp& operator += (const Fp& r) noexcept {
        val += r.val;
        if (val >= mod) val -= mod;
        return *this;
    }
    constexpr Fp& operator -= (const Fp& r) noexcept {
        val -= r.val;
        if (val < 0) val += mod;
        return *this;
    }
    constexpr Fp& operator *= (const Fp& r) noexcept {
        val = val * r.val % mod;
        return *this;
    }
    constexpr Fp& operator /= (const Fp& r) noexcept {
        long long a = r.val, b = mod, u = 1, v = 0;
        while (b) {
            long long t = a / b;
            a -= t * b; swap(a, b);
            u -= t * v; swap(u, v);
        }
        val = val * u % mod;
        if (val < 0) val += mod;
        return *this;
    }
    constexpr bool operator == (const Fp& r) const noexcept {
        return this->val == r.val;
    }
    constexpr bool operator != (const Fp& r) const noexcept {
        return this->val != r.val;
    }
    friend constexpr istream& operator >> (istream &is, const Fp<mod>& x) noexcept {
        int val; is >> val;
        x = Fp<mod>(val);
        return is;
    }
    friend constexpr ostream& operator << (ostream &os, const Fp<mod>& x) noexcept {
        return os << x.val;
    }
    friend constexpr Fp<mod> modpow(const Fp<mod> &a, long long n) noexcept {
        if (n == 0) return 1;
        auto t = modpow(a, n / 2);
        t = t * t;
        if (n & 1) t = t * a;
        return t;
    }
};

//const int mod = 1e9+7;
const int mod = 998244353;
using mint = Fp<mod>;

int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    ll n,m; in(n,m);
    vector<ll> z1(n),z2(n), w1(n),w2(n);
    vector<ll> zb,wb;
    rep(i,n){
        ll x,y,h; in(x,y,h);
        ll zmin = x+y-m+h, zmax = x+y+m-h;
        ll wmin = y-x-m+h, wmax = y-x+m-h;
        z1[i] = zmin; z2[i] = zmax;
        w1[i] = wmin; w2[i] = wmax;
        zb.pb(zmin), zb.pb(zmax);
        wb.pb(wmin), wb.pb(wmax);
    }
    sort(ALL(zb)); sort(ALL(wb));
    UNIQUE(zb); UNIQUE(wb);
    int sz = zb.size(), sw = wb.size();

    vector<vector<int>> sum(sz, vector<int> (sw));
    rep(i,n){
        int zi1 = lower_bound(ALL(zb), z1[i]) - zb.begin();
        int zi2 = lower_bound(ALL(zb), z2[i]) - zb.begin();
        int wi1 = lower_bound(ALL(wb), w1[i]) - wb.begin();
        int wi2 = lower_bound(ALL(wb), w2[i]) - wb.begin();
        sum[zi1][wi1]++;
        sum[zi2][wi2]++;
        sum[zi2][wi1]--;
        sum[zi1][wi2]--;
    }

    rep(i,sz){
        rep(j,sw-1) sum[i][j+1] += sum[i][j];
    }
    rep(j,sw){
        rep(i,sz-1) sum[i+1][j] += sum[i][j];
    }

    vector<mint> ans(n+1);
    rep(i,sz-1)rep(j,sw-1){
        ans[sum[i][j]] += (mint)(zb[i+1]-zb[i])*(wb[j+1]-wb[j]);
    }
    FOR(i,1,n+1) out(ans[i]/2);
}
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