#944910 (C++17) No.2609 Decreasing GCDs

• 問題: No.2609 Decreasing GCDs
• ユーザー: 👑 binap
• 提出日時: 2024-01-19 21:45:51
• 言語: C++17 (gcc 12.3.0 + boost 1.83.0)
• 結果: AC
• 実行時間: 2 ms / 1,000 ms
• コード長: 1,719 bytes
• コンパイル時間: 4,469 ms
• コンパイル使用メモリ: 262,740 KB
• 実行使用メモリ: 5,376 KB
• 最終ジャッジ日時: 2024-09-28 04:16:08
• 合計ジャッジ時間: 5,001 ms
• ジャッジサーバーID （参考情報）: judge4 / judge3

入力	結果	実行時間; 実行使用メモリ
testcase_00	AC	2 ms; 5,248 KB
testcase_01	AC	2 ms; 5,376 KB
testcase_02	AC	2 ms; 5,376 KB
testcase_03	AC	2 ms; 5,376 KB
testcase_04	AC	2 ms; 5,376 KB
testcase_05	AC	2 ms; 5,376 KB
testcase_06	AC	2 ms; 5,376 KB
testcase_07	AC	2 ms; 5,376 KB
testcase_08	AC	2 ms; 5,376 KB
testcase_09	AC	2 ms; 5,376 KB
testcase_10	AC	2 ms; 5,376 KB
testcase_11	AC	1 ms; 5,376 KB
testcase_12	AC	1 ms; 5,376 KB
testcase_13	AC	2 ms; 5,376 KB
testcase_14	AC	2 ms; 5,376 KB
testcase_15	AC	2 ms; 5,376 KB
testcase_16	AC	2 ms; 5,376 KB
testcase_17	AC	2 ms; 5,376 KB
testcase_18	AC	2 ms; 5,376 KB
testcase_19	AC	2 ms; 5,376 KB
testcase_20	AC	2 ms; 5,376 KB
testcase_21	AC	1 ms; 5,376 KB
testcase_22	AC	2 ms; 5,376 KB

ソースコード

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template <typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}

int main(){
	int n;
	cin >> n;
	vector<int> p = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97};
	vector<int> ans(n);
	rep(i, n){
		if(i == 0){
			ans[0] = p[n - 2];
			continue;
		}
		if(i == n - 1){
			int x = p[0];
			ans[i] = (ans[i - 1] + x) / x * x;
			continue;
		}
		int x = p[n - 1 - i] * p[n - 2 - i];
		ans[i] = (ans[i - 1] + x) / x * x;
		if(i < n - 2){
			while(ans[i] % p[n - 3 - i] == 0 or gcd(ans[i], ans[i - 1]) != p[n - 1 - i]){
				ans[i] += x;
			}
		}
	}
	cout << ans;
	/*
	rep(i, n - 1){
		cout << gcd(ans[i], ans[i + 1]) << ' ';
	}
	*/
	return 0;
}