結果

問題 No.2615 ペアの作り方
ユーザー gucci0512
提出日時 2024-01-26 21:32:57
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 250 ms / 2,000 ms
コード長 4,244 bytes
コンパイル時間 3,748 ms
コンパイル使用メモリ 245,432 KB
実行使用メモリ 32,560 KB
最終ジャッジ日時 2024-09-28 07:43:43
合計ジャッジ時間 6,354 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
other AC * 21
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#include <atcoder/all>
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2")
// url
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=b-1;i>=a;i--)
#define all(x) (x).begin(),(x).end()
#define pb(x) push_back(x);
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; }
typedef long long ll;
typedef long double lld;
using namespace std;
using namespace atcoder;
using mint = static_modint<998244353>;
const ll mod=998244353;
// using mint = static_modint<1000000007>;
//const ll mod=1e9+7;
int dx[4]={1,0,-1,0};
int dy[4]={0,1,0,-1};
const string zton="0123456789";
const string atoz="abcdefghijklmnopqrstuvwxyz";
const string ATOZ="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const ll inf=(1ll<<60);
// const int inf=(1<<30);
lld dist(lld x1,lld x2,lld y1,lld y2){
lld res=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);
res=sqrt(abs(res));
return res;
}
lld arg(lld x,lld y){
const lld eps=1e-8;
lld res=0;
if(abs(x)+abs(y)<=eps)return 0.0;
else if(abs(x)<=eps){
if(y>=0.0)return (M_PI/2);
else return (M_PI/2+M_PI);
}
else if(abs(y)<=eps){
if(x>=0.0)return 0.0;
else return M_PI;
}
res=atan2(abs(y),abs(x));
if(x<=0&&y>=0)res=(M_PI-res);
else if(x<=0&&y<=0)res+=(M_PI);
else if(x>=0&&y<=0)res=(M_PI*2-res);
return res;
}
ll gcd(ll a,ll b){
if(a==0||b==0)return a+b;
ll r;
r=a%b;
if(r==0){
return b;
}
else{
return gcd(b,r);
}
}
std::ostream &operator<<(std::ostream &dest, __int128_t value) {
std::ostream::sentry s(dest);
if (s) {
__uint128_t tmp = value < 0 ? -value : value;
char buffer[128];
char *d = std::end(buffer);
do {
--d;
*d = "0123456789"[tmp % 10];
tmp /= 10;
} while (tmp != 0);
if (value < 0) {
--d;
*d = '-';
}
int len = std::end(buffer) - d;
if (dest.rdbuf()->sputn(d, len) != len) {
dest.setstate(std::ios_base::badbit);
}
}
return dest;
}
__int128 parse128(string &s) {
__int128 ret = 0;
for (int i = 0; i < s.length(); i++){
if ('0' <= s[i] && s[i] <= '9'){
ret = 10 * ret + s[i] - '0';
}
}
return ret;
}
using l3 = __int128;
bool comp_arg(pair<ll,ll> a,pair<ll,ll> b){
if(a.second>=0&&b.second<0)return true;
else if(a.second<0&&b.second>=0)return false;
if(a.second>=0&&b.second>=0){
if(a.first>=0&&b.first<0)return true;
}
else{
if(a.first>=0&&b.first<0)return false;
}
ll det=a.first*b.second-a.second*b.first;
if(det>0)return true;
return false;
}
const int kaijouSize=501010;
ll inv_[kaijouSize];
mint inv[kaijouSize];
mint kaijou[kaijouSize];
mint kaijou_inv[kaijouSize];
void InitKaijou(){
inv_[0]=1;
inv_[1]=1;
inv[0]=1;
inv[1]=1;
rep(i,2,kaijouSize) inv_[i]=inv_[mod%i]*(mod-mod/i)%mod;
rep(i,2,kaijouSize) inv[i]=inv_[i];
kaijou[0]=1;
rep(i,1,kaijouSize){
kaijou[i]=kaijou[i-1]*1ll*i;
}
kaijou_inv[0]=1ll;
rep(i,1,kaijouSize){
kaijou_inv[i]=kaijou_inv[i-1]*1ll*(inv[i]);
}
}
mint nck(int n,int k){
if(n<k)return 0;
else return (((kaijou[n]*kaijou_inv[k]))*kaijou_inv[n-k]);
}
mint npk(int n,int k){
if(n<k)return 0;
return (kaijou[n]*kaijou_inv[n-k]);
}
int N;
vector<int> X,Y;
void push_xy(){
set<int> s;
rep(i,0,N)s.insert(X[i]);
rep(i,0,N)s.insert(Y[i]);
map<int,int> mp;
for(int x:s){
mp[x]=mp.size();
}
rep(i,0,N){
X[i]=mp[X[i]];
Y[i]=mp[Y[i]];
}
return;
}
int main(void){
ios::sync_with_stdio(false);
cin.tie(nullptr);
cin >> N;
X.resize(N);Y.resize(N);
rep(i,0,N)cin >> X[i];
rep(i,0,N)cin >> Y[i];
push_xy();
InitKaijou();
int cnt_x=0,cnt_y=0;
rep(i,0,N){
if(X[i]<N)cnt_x++;
if(Y[i]<N)cnt_y++;
}
mint ans=kaijou[N-cnt_x]*kaijou[N-cnt_y];
cout << ans.val() << endl;
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0