結果

問題 No.2616 中央番目の中央値
ユーザー ゆにぽけ
提出日時 2024-01-26 21:50:14
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 76 ms / 2,000 ms
コード長 4,784 bytes
コンパイル時間 1,329 ms
コンパイル使用メモリ 129,532 KB
最終ジャッジ日時 2025-02-18 23:09:59
ジャッジサーバーID
(参考情報)
judge4 / judge2
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ファイルパターン 結果
other AC * 37
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ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <vector>
#include <algorithm>
#include <array>
#include <iterator>
#include <string>
#include <cctype>
#include <cstring>
#include <cstdlib>
#include <cassert>
#include <cmath>
#include <ctime>
#include <iomanip>
#include <numeric>
#include <stack>
#include <queue>
#include <map>
#include <unordered_map>
#include <set>
#include <unordered_set>
#include <bitset>
#include <random>
#include <utility>
#include <functional>
using namespace std;
template<int m> struct modint
{
private:
unsigned int value;
static constexpr int mod() {return m;}
public:
constexpr modint(const long long x = 0) noexcept
{
long long y = x;
if(y < 0 || y >= mod())
{
y %= mod();
if(y < 0) y += mod();
}
value = (unsigned int)y;
}
constexpr unsigned int val() noexcept {return value;}
constexpr modint &operator+=(const modint &other) noexcept
{
value += other.value;
if(value >= mod()) value -= mod();
return *this;
}
constexpr modint &operator-=(const modint &other) noexcept
{
unsigned int x = value;
if(x < other.value) x += mod();
x -= other.value;
value = x;
return *this;
}
constexpr modint &operator*=(const modint &other) noexcept
{
unsigned long long x = value;
x *= other.value;
value = (unsigned int) (x % mod());
return *this;
}
constexpr modint &operator/=(const modint &other) noexcept
{
return *this *= other.inverse();
}
constexpr modint inverse() const noexcept
{
assert(value);
long long a = value,b = mod(),x = 1,y = 0;
while(b)
{
long long q = a/b;
a -= q*b; swap(a,b);
x -= q*y; swap(x,y);
}
return modint(x);
}
constexpr modint power(long long N) const noexcept
{
assert(N >= 0);
modint p = *this,ret = 1;
while(N)
{
if(N & 1) ret *= p;
p *= p;
N >>= 1;
}
return ret;
}
constexpr modint operator+() {return *this;}
constexpr modint operator-() {return modint() - *this;}
constexpr modint &operator++(int) noexcept {return *this += 1;}
constexpr modint &operator--(int) noexcept {return *this -= 1;}
friend modint operator+(const modint& lhs, const modint& rhs) {return modint(lhs) += rhs;}
friend modint operator-(const modint& lhs, const modint& rhs) {return modint(lhs) -= rhs;}
friend modint operator*(const modint& lhs, const modint& rhs) {return modint(lhs) *= rhs;}
friend modint operator/(const modint& lhs, const modint& rhs) {return modint(lhs) /= rhs;}
friend ostream &operator<<(ostream &os,const modint &x) {return os << x.value;}
};
using mint = modint<998244353>;
/* using mint = modint<1000000007>; */
template<class S>
struct combination
{
private:
vector<S> f,invf;
public:
combination(int N = 0) : f(1,1),invf(1,1)
{
update(N);
}
void update(int N)
{
if((int)f.size() > N) return;
int pi = (int)f.size();
N = max(N,pi*2);
f.resize(N+1),invf.resize(N+1);
for(int i = pi;i <= N;i++) f[i] = f[i-1]*i;
invf[N] = S(1)/f[N];
for(int i = N-1;i >= pi;i--) invf[i] = invf[i+1]*(i+1);
}
S factorial(int N)
{
update(N);
return f[N];
}
S invfactorial(int N)
{
update(N);
return invf[N];
}
S P(int N,int K)
{
assert(0 <= K && K <= N);
update(N);
return f[N]*invf[N-K];
}
S C(int N,int K)
{
assert(0 <= K && K <= N);
update(N);
return f[N]*invf[K]*invf[N-K];
}
};
combination<mint> C;
template<class T> struct BinaryIndexedTree
{
private:
int N;
vector<T> node;
public:
BinaryIndexedTree() : N(0) {}
BinaryIndexedTree(int N) : N(N), node(N) {}
void add(int pos,T x)
{
assert(0 <= pos && pos < N);
pos++;
while(pos <= N)
{
node[pos-1] += x;
pos += pos & -pos;
}
}
T sum(int l,int r)
{
assert(0 <= l && l <= N && r <= N);
return sum(r) - sum(l);
}
T sum(int r)
{
T ret = 0;
while(r > 0)
{
ret += node[r-1];
r -= r & -r;
}
return ret;
}
T sum() {return sum(N);}
};
void Main()
{
int N;
cin >> N;
vector<int> P(N);
for(int i = 0;i < N;i++)
{
cin >> P[i];
P[i]--;
}
BinaryIndexedTree<int> BIT(N);
mint ans = 0;
for(int i = 0;i < N;i++)
{
int ld = BIT.sum(P[i]),lu = i - ld;
int rd = P[i] - ld,ru = N - P[i] - 1 - lu;
//ru = N - P[i] - 1 - i + ld
//lu = i - ld,rd = P[i] - ld
/* for(int i = 0;i <= min(ld,ru);i++) a += C.C(ld,i) * C.C(ru,i); */
/* for(int i = 0;i <= min(lu,rd);i++) b += C.C(lu,i) * C.C(rd,i); */
mint a = C.factorial(ld + ru) * C.invfactorial(ld) * C.invfactorial(ru);
mint b = C.factorial(lu + rd) * C.invfactorial(lu) * C.invfactorial(rd);
ans += a * b;
/* cout << lu << " " << ru << endl; */
/* cout << ld << " " << rd << endl; */
//x + y == z + w
//x + z == y + w
//y == z && x == w
BIT.add(P[i],1);
}
cout << ans << endl;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
int tt = 1;
/* cin >> tt; */
while(tt--) Main();
}
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