結果
問題 | No.2616 中央番目の中央値 |
ユーザー | pitP |
提出日時 | 2024-01-26 23:37:50 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 5,484 bytes |
コンパイル時間 | 4,555 ms |
コンパイル使用メモリ | 279,772 KB |
実行使用メモリ | 188,140 KB |
最終ジャッジ日時 | 2024-09-28 09:09:38 |
合計ジャッジ時間 | 14,504 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 10 ms
16,128 KB |
testcase_01 | AC | 10 ms
10,496 KB |
testcase_02 | AC | 9 ms
10,496 KB |
testcase_03 | AC | 10 ms
10,496 KB |
testcase_04 | AC | 9 ms
10,496 KB |
testcase_05 | AC | 10 ms
10,596 KB |
testcase_06 | AC | 9 ms
10,536 KB |
testcase_07 | AC | 8 ms
10,624 KB |
testcase_08 | AC | 10 ms
10,624 KB |
testcase_09 | AC | 10 ms
10,624 KB |
testcase_10 | AC | 10 ms
10,752 KB |
testcase_11 | AC | 12 ms
10,624 KB |
testcase_12 | AC | 15 ms
11,104 KB |
testcase_13 | AC | 25 ms
11,648 KB |
testcase_14 | AC | 40 ms
12,672 KB |
testcase_15 | AC | 80 ms
15,216 KB |
testcase_16 | AC | 164 ms
20,336 KB |
testcase_17 | AC | 272 ms
24,288 KB |
testcase_18 | AC | 496 ms
34,552 KB |
testcase_19 | AC | 1,123 ms
60,388 KB |
testcase_20 | AC | 1,049 ms
60,388 KB |
testcase_21 | TLE | - |
testcase_22 | TLE | - |
testcase_23 | -- | - |
testcase_24 | -- | - |
testcase_25 | -- | - |
testcase_26 | -- | - |
testcase_27 | -- | - |
testcase_28 | -- | - |
testcase_29 | -- | - |
testcase_30 | -- | - |
testcase_31 | -- | - |
testcase_32 | -- | - |
testcase_33 | -- | - |
testcase_34 | -- | - |
testcase_35 | -- | - |
testcase_36 | -- | - |
ソースコード
// https://judge.yosupo.jp/submission/186019 #include <bits/stdc++.h> #include <atcoder/all> using namespace std; using namespace atcoder; istream &operator>>(istream &is, modint &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint &a) { return os << a.val(); } istream &operator>>(istream &is, modint998244353 &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint998244353 &a) { return os << a.val(); } istream &operator>>(istream &is, modint1000000007 &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint1000000007 &a) { return os << a.val(); } typedef long long ll; typedef vector<vector<int>> Graph; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define FOR(i,l,r) for (int i = l;i < (int)(r); i++) #define rep(i,n) for (int i = 0;i < (int)(n); i++) #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define my_sort(x) sort(x.begin(), x.end()) #define my_max(x) *max_element(all(x)) #define my_min(x) *min_element(all(x)) template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; } template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; } const int INF = (1<<30) - 1; const ll LINF = (1LL<<62) - 1; const int MOD2 = 1e9+7; const double PI = acos(-1); vector<int> di = {1,0,-1,0}; vector<int> dj = {0,1,0,-1}; #ifdef LOCAL # include <debug_print.hpp> # define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__) #else # define debug(...) (static_cast<void>(0)) #endif template <class S, S (*op)(S, S), S (*e)(), class CoordinateType> struct RangeTree { using CT = CoordinateType; using Point = pair<CT, CT>; vector<Point> points; vector<vector<Point>> yx; vector<atcoder::segtree<S,op,e>> seg; int n; void _set(int idx, Point p, S val){ int i = lower_bound(yx[idx].begin(), yx[idx].end(), Point{p.second, p.first}) - yx[idx].begin(); seg[idx].set(i, val); } S _prod(int idx, CT yl, CT yr){ auto comp = [](const Point &lhs, const Point &rhs) {return lhs.first < rhs.first; }; int il = lower_bound(yx[idx].begin(), yx[idx].end(), Point{yl, yl}, comp) - yx[idx].begin(); int ir = lower_bound(yx[idx].begin(), yx[idx].end(), Point{yr, yr}, comp) - yx[idx].begin(); return seg[idx].prod(il, ir); } void add_point(CT x, CT y){ points.push_back(Point{x, y}); } void build(){ sort(points.begin(), points.end()); points.erase(unique(points.begin(), points.end()), points.end()); n = points.size(); yx.resize(2 * n); for(int i = 0; i < n; i++) yx[i + n] = { Point{points[i].second, points[i].first}}; for(int i = n - 1; i > 0; i--){ auto &lc = yx[2 * i]; auto &rc = yx[2 * i + 1]; merge(lc.begin(), lc.end(), rc.begin(), rc.end(), back_inserter(yx[i])); yx[i].erase(unique(yx[i].begin(), yx[i].end()), yx[i].end()); } for(const auto &v : yx) seg.emplace_back(v.size()); } void set(CT x, CT y, S val){ int i = lower_bound(points.begin(), points.end(), Point{x, y}) - points.begin() + n; while(i){ _set(i, Point{x, y}, val); i = i >> 1; } } S prod(CT xl, CT xr, CT yl, CT yr){ auto comp = [](const Point &lhs, const Point &rhs) {return lhs.first < rhs.first; }; int l = lower_bound(points.begin(), points.end(), Point{xl, yr}, comp) - points.begin() + n; int r = lower_bound(points.begin(), points.end(), Point{xr, yr}, comp) - points.begin() + n; S sml = e(), smr = e(); while(l < r){ if(l & 1) sml = op(sml, _prod(l++, yl, yr)); if(r & 1) smr = op(_prod(--r, yl, yr), smr); l >>= 1; r >>= 1; } return op(sml, smr); } S get(CT x, CT y){ return prod(x, x + 1, y, y + 1); } }; using S = int; S op(S a, S b){ return a + b; } S e(){ return 0; } //https://drken1215.hatenablog.com/entry/2018/06/08/210000 //COMinit()を忘れない!!! const ll NMAX = 303030; const ll MOD = 998244353; //const int MOD = 1e9+7; ll fac[NMAX],finv[NMAX],inv[NMAX]; void COMinit(){ fac[0] = fac[1] = 1LL; finv[0] = finv[1] = 1LL; inv[1] = 1LL; for (int i=2;i<NMAX;i++){ fac[i] = fac[i-1] * i % MOD; inv[i] = MOD - inv[MOD%i] * (MOD/i) % MOD; finv[i] = finv[i-1] * inv[i] % MOD; } } ll nCr(int n,int k){ if (n<k) return 0LL; if (n < 0 || k < 0) return 0LL; return fac[n] * (finv[k] * finv[n-k] % MOD) % MOD; } ll nPr(int n,int k){ if (n<k) return 0LL; if (n < 0 || k < 0) return 0LL; return fac[n] * finv[n-k] % MOD; } ll nHr(int n,int r){ return nCr(n+r-1,r); } using mint = modint998244353; int main(){ cin.tie(0); ios_base::sync_with_stdio(false); COMinit(); int N; cin >> N; vector<int> P(N); rep(i,N) cin >> P[i], P[i]--; RangeTree<S,op,e,int> RT; rep(i,N) RT.add_point(i, P[i]); RT.build(); rep(i,N) RT.set(i, P[i], 1); mint ans = 0; for(int c = 0; c < N; c++){ int lu = RT.prod(0, c, P[c] + 1, N); int ld = RT.prod(0, c, 0, P[c]); int ru = RT.prod(c, N, P[c] + 1, N); int rd = RT.prod(c, N, 0, P[c]); ans += nCr(lu + rd, lu) * nCr(ld + ru, ru); } cout << ans << endl; }