結果

問題 No.274 The Wall
ユーザー rlangevin
提出日時 2024-02-04 13:39:32
言語 Python3
(3.13.1 + numpy 2.2.1 + scipy 1.14.1)
結果
TLE  
実行時間 -
コード長 3,992 bytes
コンパイル時間 263 ms
コンパイル使用メモリ 13,056 KB
実行使用メモリ 506,384 KB
最終ジャッジ日時 2024-09-28 11:15:10
合計ジャッジ時間 3,842 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample -- * 4
other AC * 3 TLE * 1 -- * 18
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

class DirectedGraph():
    def __init__(self, N):
        self.N = N
        self.G = [[] for i in range(N)]
        self.rG = [[] for i in range(N)]
        self.order = []
        self.used1 = [0] * N
        self.used2 = [0] * N
        self.group = [-1] * N
        self.label = 0
        self.seen = [0] * N
        self.Edge = set()
    def add_edge(self, u, v):
        #多重辺は排除する
        if (u, v) not in self.Edge:
            self.G[u].append(v)
            self.rG[v].append(u)
            self.Edge.add((u, v))
    def dfs(self, s):
        stack = [~s, s]
        while stack:
            u = stack.pop()
            if u >= 0:
                if self.used1[u]:
                    continue
                self.used1[u] = 1
                for v in self.G[u]:
                    if self.used1[v]:
                        continue
                    stack.append(~v)
                    stack.append(v)
            else:
                u = ~u
                if self.seen[u]:
                    continue
                self.seen[u]= 1
                self.order.append(u)
    def rdfs(self, s, num):
        stack = [s]
        while stack:
            u = stack.pop()
            if u >= 0:
                self.used2[u] = 1
                self.group[u] = num
                for v in self.rG[u]:
                    if self.used2[v]:
                        continue
                    stack.append(v)
    def scc(self):
        for i in range(self.N):
            if self.used1[i]:
                continue
            self.dfs(i)
        for s in reversed(self.order):
            if self.used2[s]:
                continue
            self.rdfs(s, self.label)
            self.label += 1
        return self.label, self.group
    def construct(self):
        nG = [set() for _ in range(self.label)]
        mem = [[] for i in range(self.label)]
        for s in range(self.N):
            now = self.group[s]
            for u in self.G[s]:
                if now == self.group[u]:
                    continue
                nG[now].add(self.group[u])
            mem[now].append(s)
        return nG, mem
class TwoSAT():
    def __init__(self, N):
        self.G = DirectedGraph(2 * N)
        
    def add(self, x1, x2, f1, f2):
        if f1 == True and f2 == True:
            # ￢x1∪￢x2
            # (x1⇒￢x2)∩(x2⇒￢x1)
            self.G.add_edge(x1, x2 + N)
            self.G.add_edge(x2, x1 + N)
            
        if f1 == True and f2 == False:
            # ￢x1∪x2
            # (x1⇒x2)∩(￢x2⇒￢x1)
            self.G.add_edge(x1, x2)
            self.G.add_edge(x2 + N, x1 + N)
        
        if f1 == False and f2 == True:
            # x1∪￢x2
            # (￢x1⇒￢x2)∩(x2⇒x1)
            self.G.add_edge(x1 + N, x2 + N)
            self.G.add_edge(x2, x1)
            
        if f1 == False and f2 == False:
            # x1∪x2
            # (￢x1⇒x2)∩(￢x2⇒x1)
            self.G.add_edge(x1 + N, x2)
            self.G.add_edge(x2 + N, x1)
            
    def check(self):
        _, group = self.G.scc()
        for i in range(N):
            if group[i] == group[i + N]:
                return False
        return True
        
N, M = map(int, input().split())
L, R = [0] * N, [0] * N
for i in range(N):
    L[i], R[i] = map(int, input().split())
    
def check(L1, R1, L2, R2):
    if R1 < L2 or R2 < L1:
        return True
    return False
    
TS = TwoSAT(N)
for i in range(N):
    for j in range(i + 1, N):
        if not check(L[i], R[i], L[j], R[j]):
            TS.add(i, j, True, True)
        if not check(L[i], R[i], M - 1 - R[j], M - 1 - L[j]):
            TS.add(i, j, True, False)
        if not check(M - 1 - R[i], M - 1 - L[i], L[j], R[j]):
            TS.add(i, j, False, True)
        if not check(M - 1 - R[i], M - 1 - L[i], M - 1 - R[j], M - 1 - L[j]):
            TS.add(i, j, False, False)
            
print("YES") if TS.check() else print("NO")
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