結果

問題 No.2630 Colorful Vertices and Cheapest Paths
ユーザー nikoro256
提出日時 2024-02-16 21:58:24
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 2,408 ms / 2,500 ms
コード長 2,147 bytes
コンパイル時間 248 ms
コンパイル使用メモリ 82,384 KB
実行使用メモリ 161,804 KB
最終ジャッジ日時 2024-09-28 20:16:08
合計ジャッジ時間 26,803 ms
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 22
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ソースコード

diff #
プレゼンテーションモードにする

from collections import defaultdict
class UnionFind():
def __init__(self, n):
self.n = n
self.parents = [-1] * n
def find(self, x):
if self.parents[x] < 0:
return x
else:
self.parents[x] = self.find(self.parents[x])
return self.parents[x]
def union(self, x, y):
x = self.find(x)
y = self.find(y)
if x == y:
return
if self.parents[x] > self.parents[y]:
x, y = y, x
self.parents[x] += self.parents[y]
self.parents[y] = x
def size(self, x):
return -self.parents[self.find(x)]
def same(self, x, y):
return self.find(x) == self.find(y)
def members(self, x):
root = self.find(x)
return [i for i in range(self.n) if self.find(i) == root]
def roots(self):
return [i for i, x in enumerate(self.parents) if x < 0]
def group_count(self):
return len(self.roots())
def all_group_members(self):
group_members = defaultdict(list)
for member in range(self.n):
group_members[self.find(member)].append(member)
return group_members
def __str__(self):
return '\n'.join(f'{r}: {m}' for r, m in self.all_group_members().items())
import sys
input=sys.stdin.readline
N,M=map(int,input().split())
uf=[UnionFind(N) for _ in range(2**10)]
exp2=[2**i for i in range(20)]
edges=[]
for _ in range(M):
a,b=map(int,input().split())
a-=1
b-=1
edges.append((a,b))
C=list(map(int,input().split()))
W=list(map(int,input().split()))
for a,b in edges:
ea=exp2[C[a]-1]
eb=exp2[C[b]-1]
for i in range(2**10):
if ea&i and eb&i:
uf[i].union(a,b)
point=[0]*(2**10)
for i in range(2**10):
for j in range(10):
if i&exp2[j]:
point[i]+=W[j]
Q=int(input())
fa=[]
for _ in range(Q):
u,v=map(int,input().split())
u-=1
v-=1
ans=10**11
for i in range(2**10):
if uf[i].same(u,v):
ans=min(ans,point[i])
if ans==10**11:
fa.append(-1)
else:
fa.append(ans)
print(*fa,sep='\n')
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