結果
問題 | No.2630 Colorful Vertices and Cheapest Paths |
ユーザー |
![]() |
提出日時 | 2024-02-16 22:01:01 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 2,702 bytes |
コンパイル時間 | 370 ms |
コンパイル使用メモリ | 82,484 KB |
実行使用メモリ | 162,440 KB |
最終ジャッジ日時 | 2024-09-28 20:19:09 |
合計ジャッジ時間 | 26,539 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
other | AC * 21 TLE * 1 |
ソースコード
import sysinput = sys.stdin.readline#https://github.com/not522/ac-library-python/blob/master/atcoder/dsu.pyimport typingclass DSU:'''Implement (union by size) + (path halving)Reference:Zvi Galil and Giuseppe F. Italiano,Data structures and algorithms for disjoint set union problems'''def __init__(self, n: int = 0) -> None:self._n = nself.parent_or_size = [-1] * ndef merge(self, a: int, b: int) -> int:assert 0 <= a < self._nassert 0 <= b < self._nx = self.leader(a)y = self.leader(b)if x == y:return xif -self.parent_or_size[x] < -self.parent_or_size[y]:x, y = y, xself.parent_or_size[x] += self.parent_or_size[y]self.parent_or_size[y] = xreturn xdef same(self, a: int, b: int) -> bool:assert 0 <= a < self._nassert 0 <= b < self._nreturn self.leader(a) == self.leader(b)def leader(self, a: int) -> int:assert 0 <= a < self._nparent = self.parent_or_size[a]while parent >= 0:if self.parent_or_size[parent] < 0:return parentself.parent_or_size[a], a, parent = (self.parent_or_size[parent],self.parent_or_size[parent],self.parent_or_size[self.parent_or_size[parent]])return adef size(self, a: int) -> int:assert 0 <= a < self._nreturn -self.parent_or_size[self.leader(a)]def groups(self) -> typing.List[typing.List[int]]:leader_buf = [self.leader(i) for i in range(self._n)]result: typing.List[typing.List[int]] = [[] for _ in range(self._n)]for i in range(self._n):result[leader_buf[i]].append(i)return list(filter(lambda r: r, result))N, M = map(int, input().split())A, B = [-1] * M, [-1] * Mfor i in range(M):A[i], B[i] = map(int, input().split())A[i], B[i] = A[i] - 1, B[i] - 1C = list(map(int, input().split()))for i in range(N):C[i] -= 1W = list(map(int, input().split()))K = 1 << 10U = [DSU(N) for _ in range(K)]cost = [0] * Kfor s in range(K):for i in range(M):if ((s >> C[A[i]]) & 1) and ((s >> C[B[i]]) & 1):U[s].merge(A[i], B[i])for i in range(10):if (s >> i) & 1:cost[s] += W[i]Q = int(input())inf = 10 ** 18for _ in range(Q):ans = infu, v = map(int, input().split())u, v = u - 1, v - 1for i in range(K):if U[i].same(u, v):ans = min(ans, cost[i])print(ans) if ans != inf else print(-1)