結果

問題 No.2640 traO Stamps
ユーザー rlangevin
提出日時 2024-02-20 12:05:19
言語 PyPy3
(7.3.15)
結果
RE  
実行時間 -
コード長 2,431 bytes
コンパイル時間 422 ms
コンパイル使用メモリ 82,260 KB
実行使用メモリ 104,684 KB
最終ジャッジ日時 2024-09-29 03:29:41
合計ジャッジ時間 7,753 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 4 RE * 29
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
input = sys.stdin.readline
class SegmentTree:
def __init__(self,
n,
identity_e,
combine_f,
):
self._n = n
self._size = 1
while self._size < self._n:
self._size <<= 1
self._identity_e = identity_e
self._combine_f = combine_f
self._node = [self._identity_e] * (2 * self._size)
def build(self, array):
assert len(array) == self._n
for index, value in enumerate(array, start=self._size):
self._node[index] = value
for index in range(self._size - 1, 0, -1):
self._node[index] = self._combine_f(
self._node[index << 1 | 0],
self._node[index << 1 | 1]
)
def update(self, index, value):
i = self._size + index
self._node[i] = value
while i > 1:
i >>= 1
self._node[i] = self._combine_f(
self._node[i << 1 | 0],
self._node[i << 1 | 1]
)
def fold(self, L, R):
L += self._size
R += self._size
value_L = self._identity_e
value_R = self._identity_e
while L < R:
if L & 1:
value_L = self._combine_f(value_L, self._node[L])
L += 1
if R & 1:
R -= 1
value_R = self._combine_f(self._node[R], value_R)
L >>= 1
R >>= 1
return self._combine_f(value_L, value_R)
N, M, K = map(int, input().split())
S = list(map(int, input().split()))
inf = 10 ** 18
G = [[inf] * N for i in range(N)]
for i in range(K + 1):
S[i] -= 1
for i in range(N):
G[i][i] = 0
for i in range(M):
A, B, C = map(int, input().split())
A, B = A - 1, B - 1
G[A][B] = C
G[B][A] = C
from operator import add
T = SegmentTree(N, 0, add)
for k in range(N):
for i in range(N):
for j in range(N):
G[i][j] = min(G[i][j], G[i][k] + G[k][j])
for i in range(K):
T.update(i, G[S[i]][S[i + 1]])
Q = int(input())
for _ in range(Q):
t, x, y = map(int, input().split())
if t == 1:
S[x] = y - 1
if x:
T.update(x - 1, G[S[x - 1]][S[x]])
if x != K:
T.update(x, G[S[x]][S[x + 1]])
else:
print(T.fold(x, y))
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