結果

問題 No.2649 [Cherry 6th Tune C] Anthem Flower
ユーザー GOTKAKO
提出日時 2024-02-23 21:43:54
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 670 ms / 2,000 ms
コード長 3,221 bytes
コンパイル時間 2,787 ms
コンパイル使用メモリ 202,620 KB
最終ジャッジ日時 2025-02-19 19:38:23
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 35
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
long long mod = 998244353;
//mod使.
struct mint{
long long v = 0;
mint(){} mint(int a){v = a;} mint(long long a){v = a;} mint(unsigned long long a){v = a;}
long long val(){return v;}
void modu(){v %= mod;}
mint repeat2mint(long long a,long long b){
mint ret = 1,p = a; int Log = 60;
if(b <= 2e9) Log = 30;
for(int i=0; i<Log; i++){if(b&(1LL<<i)) ret *= p; p *= p;}
return ret;
};
mint operator+(mint b){return (v+b.v)%mod;}
mint operator-(mint b){return (v-b.v+mod)%mod;}
mint operator*(mint b){return v*b.v%mod;}
mint operator/(mint b){
if(b.v == 0) assert(false);
return v*(repeat2mint(b.v,mod-2)).v%mod;
}
void operator+=(mint b){v = (v+b.v)%mod;}
void operator-=(mint b){v = (v-b.v+mod)%mod;}
void operator*=(mint b){v = v*b.v%mod;}
void operator/=(mint b){
if(b.v == 0) assert(false);
v = v*repeat2mint(b.v,mod-2).v%mod;
}
void operator++(int){v = (v+1)%mod; return;}
void operator--(int){v = (v-1+mod)%mod; return;}
bool operator==(mint b){if(v == b.v) return true; else return false;}
bool operator!=(mint b){if(v != b.v) return true; else return false;}
bool operator>(mint b){if(v > b.v) return true; else return false;}
bool operator>=(mint b){if(v >= b.v) return true; else return false;}
bool operator<(mint b){if(v < b.v) return true; else return false;}
bool operator<=(mint b){if(v <= b.v) return true; else return false;}
mint pow(long long x){return repeat2mint(v,x);}
mint inv(){return mint(1)/v;}
};
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int T; cin >> T;
while(T--){
string s; cin >> s; cin >> mod;
reverse(s.begin(),s.end());
int N = s.size();
vector<long long> A,B;
for(auto c : s) A.push_back((int)(c-'0'));
A.push_back(0);
B = A;
B.at(0)++;
for(int i=0; i<N; i++){
if(B.at(i) == 10) B.at(i) = 0,B.at(i+1)++;
else break;
}
vector<long long> C;
if(A.at(0)%2 == 0){
long long now = 0;
for(int i=N-1; i>=0; i--){
long long c = 0;
if(now) c = 5;
if(A.at(i)%2) now = 1;
else now = 0;
c += A.at(i)/2;
C.push_back(c);
}
reverse(C.begin(),C.end());
A = C;
}
else{
long long now = 0;
for(int i=N; i>=0; i--){
long long c = 0;
if(now) c = 5;
if(B.at(i)%2) now = 1;
else now = 0;
c += B.at(i)/2;
C.push_back(c);
}
reverse(C.begin(),C.end());
B = C;
}
vector<mint> p10(N+1,1);
for(int i=1; i<=N; i++) p10.at(i) = p10.at(i-1)*10;
mint a = 0,b = 0;
for(int i=0; i<A.size(); i++) a += p10.at(i)*A.at(i);
for(int i=0; i<B.size(); i++) b += p10.at(i)*B.at(i);
cout << (a*b).v << endl;
}
}
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