結果

問題 No.2650 [Cherry 6th Tune *] セイジャク
ユーザー Akijin_007
提出日時 2024-02-23 21:58:19
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 1,421 ms / 2,500 ms
コード長 2,647 bytes
コンパイル時間 329 ms
コンパイル使用メモリ 82,048 KB
実行使用メモリ 175,072 KB
最終ジャッジ日時 2024-09-30 13:43:12
合計ジャッジ時間 36,518 ms
ジャッジサーバーID
(参考情報)
judge5 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#int(input())
#map(int, input().split())
#list(map(int, input().split()))
#
def segfunc(x,y):
return max(x,y)
class LazySegTree_RUQ:
def __init__(self,init_val,segfunc,ide_ele):
n = len(init_val)
self.segfunc = segfunc
self.ide_ele = ide_ele
self.num = 1<<(n-1).bit_length()
self.tree = [ide_ele]*2*self.num
self.lazy = [None]*2*self.num
for i in range(n):
self.tree[self.num+i] = init_val[i]
for i in range(self.num-1,0,-1):
self.tree[i] = self.segfunc(self.tree[2*i],self.tree[2*i+1])
def gindex(self,l,r):
l += self.num
r += self.num
lm = l>>(l&-l).bit_length()
rm = r>>(r&-r).bit_length()
while r>l:
if l<=lm:
yield l
if r<=rm:
yield r
r >>= 1
l >>= 1
while l:
yield l
l >>= 1
def propagates(self,*ids):
for i in reversed(ids):
v = self.lazy[i]
if v is None:
continue
self.lazy[i] = None
self.lazy[2*i] = v
self.lazy[2*i+1] = v
self.tree[2*i] = v
self.tree[2*i+1] = v
def update(self,l,r,x):
ids = self.gindex(l,r)
self.propagates(*self.gindex(l,r))
l += self.num
r += self.num
while l<r:
if l&1:
self.lazy[l] = x
self.tree[l] = x
l += 1
if r&1:
self.lazy[r-1] = x
self.tree[r-1] = x
r >>= 1
l >>= 1
for i in ids:
self.tree[i] = self.segfunc(self.tree[2*i], self.tree[2*i+1])
def query(self,l,r):
ids = self.gindex(l,r)
self.propagates(*self.gindex(l,r))
res = self.ide_ele
l += self.num
r += self.num
while l<r:
if l&1:
res = self.segfunc(res,self.tree[l])
l += 1
if r&1:
res = self.segfunc(res,self.tree[r-1])
l >>= 1
r >>= 1
return res
N, A = map(int, input().split())
X = list(map(int, input().split()))
T = int(input())
l = [0] * T
for i in range(T):
l[i] = list(map(int, input().split()))
x = set(X)
for i in range(T):
x.add(l[i][0])
x.add(l[i][1])
x = sorted(x)
ll = len(x)
d = dict()
for i in range(ll):
d[x[i]] = i
s = LazySegTree_RUQ([-1] * ll, segfunc, -1)
for i in range(T):
L, R = l[i]
s.update(d[L], d[R]+1, i+1)
for i in range(N):
print(s.query(d[X[i]], d[X[i]]+1))
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