結果

問題 No.2650 [Cherry 6th Tune *] セイジャク
ユーザー yupooh
提出日時 2024-02-23 21:58:51
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 1,249 ms / 2,500 ms
コード長 2,395 bytes
コンパイル時間 365 ms
コンパイル使用メモリ 82,828 KB
実行使用メモリ 104,400 KB
最終ジャッジ日時 2024-09-29 06:35:28
合計ジャッジ時間 29,971 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
input = sys.stdin.readline
n,a=map(int,input().split())
x=list(map(int,input().split()))
class LazySegTree:
def __init__(self, N, func, intv):
self.intv = intv
self.func = func
self.LV = (N-1).bit_length()
self.N0 = 2**self.LV
self.data = [intv]*(2*self.N0)
self.lazy = [None]*(2*self.N0)
def gindex(self, l, r):
L = (l + self.N0) >> 1; R = (r + self.N0) >> 1
lc = 0 if l & 1 else (L & -L).bit_length()
rc = 0 if r & 1 else (R & -R).bit_length()
v = 2
for i in range(self.LV):
if rc <= i:
yield R
if L < R and lc <= i:
yield L
L >>= 1; R >>= 1; v <<= 1
def propagates(self, *ids):
for i in reversed(ids):
v = self.lazy[i-1]
if v is None:
continue
self.lazy[2*i-1] = self.data[2*i-1] = self.lazy[2*i] = self.data[2*i] = v >> 1
self.lazy[i-1] = None
def update(self, l, r, x):
*ids, = self.gindex(l, r)
self.propagates(*ids)
L = self.N0 + l; R = self.N0 + r
v = x
while L < R:
if R & 1:
R -= 1
self.lazy[R-1] = self.data[R-1] = v
if L & 1:
self.lazy[L-1] = self.data[L-1] = v
L += 1
L >>= 1; R >>= 1; v <<= 1
for i in ids:
self.data[i-1] = self.func(self.data[2*i-1], self.data[2*i])
def query(self, l, r):
self.propagates(*self.gindex(l, r))
L = self.N0 + l; R = self.N0 + r
s = self.intv
while L < R:
if R & 1:
R -= 1
s = self.func(s, self.data[R-1])
if L & 1:
s = self.func(s, self.data[L-1])
L += 1
L >>= 1; R >>= 1
return s
def segfunc(x, y):
return x + y
xx=[]
for i in range(n):
xx.append((x[i],i))
xx.sort()
x.sort()
inv=[0]*n
for i in range(n):
inv[xx[i][1]]=i
st=LazySegTree(n,segfunc,0)
t=int(input())
from bisect import bisect_left, bisect_right, insort
for i in range(t):
l,r=map(int,input().split())
id1=bisect_left(x,l)
if id1==n:
continue
id2=bisect_right(x,r)-1
st.update(id1,id2+1,i+1)
for i in range(n):
ans=st.query(inv[i],inv[i]+1)
if ans==0:
print(-1)
else:
print(ans)
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