結果
問題 | No.2654 [Cherry 6th Tune] Re: start! (Black Sheep) |
ユーザー | TKTYI |
提出日時 | 2024-02-23 23:03:57 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 855 ms / 7,000 ms |
コード長 | 4,061 bytes |
コンパイル時間 | 5,113 ms |
コンパイル使用メモリ | 286,632 KB |
実行使用メモリ | 70,656 KB |
最終ジャッジ日時 | 2024-09-29 08:25:51 |
合計ジャッジ時間 | 24,689 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 40 |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> using namespace std; using namespace atcoder; typedef long long int ll; typedef long double ld; typedef vector<ll> vi; typedef vector<vi> vvi; typedef vector<vvi> vvvi; typedef vector<vvvi> vvvvi; typedef vector<bool> vb; typedef vector<vb> vvb; typedef vector<vvb> vvvb; typedef vector<vvvb> vvvvb; typedef pair<ll,ll> pi; typedef pair<ll,pi> ppi; typedef pair<ll,ppi> pppi; typedef pair<ll,pppi> ppppi; #define FOR(i,l,r) for(ll i=l;i<r;i++) #define REP(i,n) FOR(i,0,n) #define RFOR(i,l,r) for(ll i=r-1;i>=l;i--) #define RREP(i,n) RFOR(i,0,n) #define ALL(x) x.begin(),x.end() #define F first #define S second #define BS(A,x) binary_search(ALL(A),x) #define LB(A,x) (ll)(lower_bound(ALL(A),x)-A.begin()) #define UB(A,x) (ll)(upper_bound(ALL(A),x)-A.begin()) #define COU(A,x) (UB(A,x)-LB(A,x)) #define sz(c) ((ll)(c).size()) /* #include<boost/multiprecision/cpp_int.hpp> namespace mp=boost::multiprecision; using Bint=mp::cpp_int; */ template<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>; template<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.F<<" "<<p.S;return os;} template<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.F>>p.S;return is;} template<typename T>ostream&operator<<(ostream&os,vector<T>&v){REP(i,sz(v))os<<v[i]<<(i+1!=sz(v)?" ":"");return os;} template<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;} template<class T>bool chmax(T&a,T b){if(a<b){a=b;return 1;}return 0;} template<class T>bool chmin(T&a,T b){if(b<a){a=b;return 1;}return 0;} ld dist(ld x1,ld y1,ld x2,ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));} vi fast_mod_convolution(vi&a,vi&b,ll mod){ const ll m1=167772161,m2=469762049,m3=1224736769; const ll m1_inv_m2=inv_mod(m1,m2); const ll m12_inv_m3=inv_mod(m1*m2,m3); const ll m12_mod=m1*m2%mod; auto x=convolution<m1>(a,b); auto y=convolution<m2>(a,b); auto z=convolution<m3>(a,b); vector<ll>ret(sz(a)+sz(b)-1); REP(i,sz(ret)){ ll v1=(y[i]-x[i])*m1_inv_m2%m2;if(v1<0)v1+=m2; ll v2=(z[i]-(x[i]+m1*v1)%m3)*m12_inv_m3%m3;if(v2<0)v2+=m3; ret[i]=(x[i]+m1*v1+m12_mod*v2)%mod; } return ret; } const ld EPS=1e-8; //* using mint=modint998244353; const ll mod=998244353; //*/ /* using mint=modint1000000007; const ll mod=1000000007; //*/ //using mint=modint; //* typedef vector<mint> vm; typedef vector<vm> vvm; typedef vector<vvm> vvvm; typedef vector<vvvm> vvvvm; ostream&operator<<(ostream&os,mint&a){os<<a.val();return os;} //*/ int main(){ ll N;cin>>N; vi A(N+1);cin>>A; vvi E(N+1); REP(i,N){ ll u,v;cin>>u>>v; E[u].emplace_back(v); E[v].emplace_back(u); } vi idx(N+1); REP(i,N+1)idx[i]=i; sort(ALL(idx),[&](ll i,ll j){return A[i]<A[j];}); vi ridx(N+1); REP(i,N+1)ridx[idx[i]]=i; ll d=0; fenwick_tree<ll>F(N+1),G(N+1); vi ans(N+1,-1); multiset<ll>S; auto se=[&](ll n){ ll l=0,r=N+1; while(r-l>1){ ll m=(l+r)/2; if(F.sum(0,m)<=n)l=m; else r=m; } return l; }; vb seen(N+1); function<void(ll)>dfs=[&](ll v){ seen[v]=1; S.insert(A[v]); F.add(ridx[v],1); G.add(ridx[v],A[v]); if(d>=2){ if(*S.begin()==*prev(S.end()))ans[v]=1; else{ ans[v]=1e18; { ll l=se((d-1)/2); ll t=G.sum(l,l+1); chmin(ans[v],(d-1)/2*t-G.sum(0,l)+G.sum(l+1,N+1)-*prev(S.end())-d/2*t); if(d%2==0){ l=se(d/2); t=G.sum(l,l+1); chmin(ans[v],d/2*t-G.sum(0,l)+G.sum(l+1,N+1)-*prev(S.end())-(d/2-1)*t); } } { ll l=se((d+1)/2); ll t=G.sum(l,l+1); chmin(ans[v],(d-1)/2*t-G.sum(0,l)+*S.begin()+G.sum(l+1,N+1)-d/2*t); if(d%2==0){ l=se(d/2+1); t=G.sum(l,l+1); chmin(ans[v],d/2*t-G.sum(0,l)+*S.begin()+G.sum(l+1,N+1)-(d/2-1)*t); } } } } for(auto u:E[v])if(!seen[u]){ d++; dfs(u); d--; } F.add(ridx[v],-1); G.add(ridx[v],-A[v]); S.erase(S.lower_bound(A[v])); }; dfs(0); FOR(i,1,N+1)cout<<ans[i]<<endl; return 0; }