結果

問題 No.2650 [Cherry 6th Tune *] セイジャク
ユーザー miya145592
提出日時 2024-02-23 23:07:15
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 1,394 ms / 2,500 ms
コード長 2,832 bytes
コンパイル時間 557 ms
コンパイル使用メモリ 81,920 KB
実行使用メモリ 101,544 KB
最終ジャッジ日時 2024-09-29 08:32:21
合計ジャッジ時間 31,204 ms
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

# https://qiita.com/ether2420/items/7b67b2b35ad5f441d686
def segfunc(x,y):
return max(x, y)
class LazySegTree_RUQ:
def __init__(self,init_val,segfunc,ide_ele):
n = len(init_val)
self.segfunc = segfunc
self.ide_ele = ide_ele
self.num = 1<<(n-1).bit_length()
self.tree = [ide_ele]*2*self.num
self.lazy = [None]*2*self.num
for i in range(n):
self.tree[self.num+i] = init_val[i]
for i in range(self.num-1,0,-1):
self.tree[i] = self.segfunc(self.tree[2*i],self.tree[2*i+1])
def gindex(self,l,r):
l += self.num
r += self.num
lm = l>>(l&-l).bit_length()
rm = r>>(r&-r).bit_length()
while r>l:
if l<=lm:
yield l
if r<=rm:
yield r
r >>= 1
l >>= 1
while l:
yield l
l >>= 1
def propagates(self,*ids):
for i in reversed(ids):
v = self.lazy[i]
if v is None:
continue
self.lazy[i] = None
self.lazy[2*i] = v
self.lazy[2*i+1] = v
self.tree[2*i] = v
self.tree[2*i+1] = v
def update(self,l,r,x):
ids = self.gindex(l,r)
self.propagates(*self.gindex(l,r))
l += self.num
r += self.num
while l<r:
if l&1:
self.lazy[l] = x
self.tree[l] = x
l += 1
if r&1:
self.lazy[r-1] = x
self.tree[r-1] = x
r >>= 1
l >>= 1
for i in ids:
self.tree[i] = self.segfunc(self.tree[2*i], self.tree[2*i+1])
def query(self,l,r):
ids = self.gindex(l,r)
self.propagates(*self.gindex(l,r))
res = self.ide_ele
l += self.num
r += self.num
while l<r:
if l&1:
res = self.segfunc(res,self.tree[l])
l += 1
if r&1:
res = self.segfunc(res,self.tree[r-1])
l >>= 1
r >>= 1
return res
import bisect
import sys
input = sys.stdin.readline
N, A = map(int, input().split())
X = list(map(int, input().split()))
T = int(input())
LR = [list(map(int, input().split())) for _ in range(T)]
for i in range(N):
x = X[i]
X[i] = (x, i)
X.sort()
ST = LazySegTree_RUQ([0 for _ in range(N)], segfunc, 0)
for t in range(T):
l, r = LR[t]
l_pos = bisect.bisect_left(X, (l, 0))
r_pos = bisect.bisect_left(X, (r, N))
if l_pos==r_pos:
continue
ST.update(l_pos, r_pos, t+1)
ans = [-1 for _ in range(N)]
for i in range(N):
tmp = ST.query(i, i+1)
x, idx = X[i]
if tmp==0:
ans[idx] = -1
else:
ans[idx] = tmp
for a in ans:
print(a)
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0