#954749 (PyPy3) No.2651 [Cherry 6th Tune B] $\mathbb{C}$omplex комбинат

• 問題: No.2651 [Cherry 6th Tune B] $\mathbb{C}$omplex комбинат
• ユーザー: Akijin_007
• 提出日時: 2024-02-23 23:24:33
• 言語: PyPy3 (7.3.15)
• 結果: AC
• 実行時間: 653 ms / 2,500 ms
• コード長: 1,375 bytes
• コンパイル時間: 369 ms
• コンパイル使用メモリ: 82,560 KB
• 実行使用メモリ: 114,504 KB
• 最終ジャッジ日時: 2024-09-29 08:57:40
• 合計ジャッジ時間: 21,375 ms
• ジャッジサーバーID （参考情報）: judge3 / judge4

ファイルパターン	結果
other	AC * 39

ソースコード

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#int(input())
#map(int, input().split())
#list(map(int, input().split()))
T = int(input())
n = [0] * T
X = [0] * T
for i in range(T):
    n[i] = int(input())
    y = [0] * n[i]
    for j in range(n[i]):
        y[j] = list(map(int, input().split()))
    X[i] = y
mod = 998244353
b = []
for k in range(T):
    # k = 1
    N = n[k]
    x = X[k]
    norm = [0] * N
    for i in range(N):
        norm[i] = x[i][0] ** 2 + x[i][1] ** 2
    norminv = [0] * N
    for i in range(N):
        norminv[i] = pow(norm[i], mod-2, mod)
    def f(x, y):
        re = x[0] * y[0] - x[1] * y[1]
        im = x[1] * y[0] + x[0] * y[1]
        return [re%mod, im%mod]
    s0 = [0, 0]
    for i in range(N):
        a = f(x[i], x[i])
        # print(x[i], a)
        for j in range(2):
            s0[j] = (s0[j] + a[j] * norminv[i]) % mod
    s1 = [0, 0]
    for i in range(N):
        y = [x[i][0], -x[i][1]]
        a = f(y, y)
        # print(y, a)
        for j in range(2):
            s1[j] = (s1[j] + a[j] * norminv[i]) % mod
    u0 = 0
    u1 = 0
    for i in range(N):
        u0 = (u0 + norm[i]) % mod
        u1 = (u1 + norminv[i]) % mod
    ans = 0
    ans = (ans + u0*u1) % mod
    ans = (ans - (s0[0]*s1[0] - s0[1]*s1[1])) % mod
    # ans = (ans * pow(2, mod-2, mod)) % mod
    # print(u0, u1)
    # print(s0, s1)
    b.append(ans)
for x in b:
    print(x)
 
 
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