結果

問題 No.5020 Averaging
ユーザー e869120
提出日時 2024-02-24 13:22:10
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 831 ms / 1,000 ms
コード長 4,919 bytes
コンパイル時間 995 ms
コンパイル使用メモリ 85,052 KB
実行使用メモリ 6,676 KB
スコア 90,929,519
最終ジャッジ日時 2024-02-25 13:00:42
合計ジャッジ時間 44,305 ms
ジャッジサーバーID
（参考情報） 		judge13 / judge10
純コード判定しない問題か言語
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
other AC * 50
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <iostream>
#include <cmath>
#include <ctime>
#include <vector>
#include <algorithm>
using namespace std;

const long long MaxVal = 1000000000000000000LL;
const long long MinVal = 100000000000000000LL;
const long long Target = 500000000000000000LL;
long long N;
long long A[59], LA[59];
long long B[59], LB[59];
long long FinalScore = MaxVal;
vector<int> FinalOrder;

// ========================================================================================================== 基本関数
// 予測スコアを計算
long long GetScore(vector<int>& Order) {
	long long TotalScore1 = (A[1] >> (N - 1));
	long long TotalScore2 = (B[1] >> (N - 1));
	for (int i = 0; i < N - 1; i++) TotalScore1 += (A[Order[i]] >> (N - 1 - i));
	for (int i = 0; i < N - 1; i++) TotalScore2 += (B[Order[i]] >> (N - 1 - i));
	return max(abs(Target - TotalScore1), abs(Target - TotalScore2));
}

// 実際のスコアを計算
long long GetActual(vector<int>& Order) {
	for (int i = 1; i <= N; i++) LA[i] = A[i];
	for (int i = 1; i <= N; i++) LB[i] = B[i];
	for (int i = 0; i < Order.size(); i++) {
		long long avgA = (LA[1] + LA[Order[i]]) / 2LL;
		long long avgB = (LB[1] + LB[Order[i]]) / 2LL;
		LA[1] = avgA; LA[Order[i]] = avgA;
		LB[1] = avgB; LB[Order[i]] = avgB;
	}
	return max(abs(Target - LA[1]), abs(Target - LB[1]));
}

// 0 以上 1 未満のランダムな実数
long double Randouble() {
	double s = 0.0, t = 1.0;
	for (int i = 0; i < 3; i++) {
		t /= 1024.0;
		s += 1.0 * (rand() % 1024) * t;
	}
	return s;
}

// ========================================================================================================== 序盤・中盤探索
vector<int> GetBestOrder() {
	vector<int> Order(N - 1, 0);
	vector<int> BestOrder(N - 1, 0);
	for (int i = 0; i < N - 1; i++) Order[i] = i + 2;

	// 準備
	long long CurrentScore = GetScore(Order);
	long long BestScore = CurrentScore;
	int StartTime = clock();

	// 焼きなまし法開始
	while (clock() - StartTime <= 10 * CLOCKS_PER_SEC / 100) {
		int idx1 = rand() % (N - 1);
		int idx2 = rand() % (N - 1);
		swap(Order[idx1], Order[idx2]);
		long long CandScore = GetScore(Order);
		double Diff = log10(CurrentScore) - log10(CandScore);
		if (Randouble() < exp(Diff / 0.17)) {
			if (BestScore > CandScore) {
				BestScore = CandScore;
				BestOrder = Order;
			}
			CurrentScore = CandScore;
		}
		else {
			swap(Order[idx1], Order[idx2]);
		}
	}
	return BestOrder;
}

// ========================================================================================================== 終盤探索
vector<int> CurrentOrder;
int StartTime;
int NumLoops;

void dfs(int mask, long long CurrentA, long long CurrentB, vector<int>& Cand, vector<int>& PostOrder) {
	if ((NumLoops & 1023) == 0) {
		if (clock() - StartTime > 80 * CLOCKS_PER_SEC / 100) return;
	}
	NumLoops += 1;
	if (mask == (1 << Cand.size()) - 1) {
		if (max(abs(Target - CurrentA), abs(Target - CurrentB)) > FinalScore + 100LL) return;
		vector<int> Final;
		for (int i = CurrentOrder.size() - 1; i >= 0; i--) Final.push_back(CurrentOrder[i]);
		for (int i = 0; i < PostOrder.size(); i++) Final.push_back(PostOrder[i]);
		long long Score = GetActual(Final);
		if (FinalScore > Score) {
			FinalScore = Score;
			FinalOrder = Final;
		}
		return;
	}

	// 枝刈り探索
	int dep = PostOrder.size() + CurrentOrder.size() + 1;
	long long Border1 = (MaxVal >> dep) + 10000LL;
	long long Border2 = 10000LL;
	for (int i = 0; i < Cand.size(); i++) {
		if ((mask >> i) & 1) continue;
		long long NextA = CurrentA + (A[Cand[i]] >> dep);
		long long NextB = CurrentB + (B[Cand[i]] >> dep);
		if (NextA < Target - Border1) continue;
		if (NextB < Target - Border1) continue;
		if (NextA > Target + Border2) continue;
		if (NextB > Target + Border2) continue;
		CurrentOrder.push_back(Cand[i]);
		dfs(mask + (1 << i), NextA, NextB, Cand, PostOrder);
		CurrentOrder.pop_back();
	}
}

int main() {
	// Step 1. 入力
	cin >> N;
	for (int i = 1; i <= N; i++) cin >> A[i] >> B[i];

	// Step 2. 焼きなまし法
	StartTime = clock();
	vector<int> BestOrder = GetBestOrder();

	// Step 3. 終盤探索
	for (int depth = 0; depth <= 20; depth++) {
		long long SumA = (A[1] >> (N - 1));
		long long SumB = (B[1] >> (N - 1));
		for (int i = depth; i < N - 1; i++) SumA += (A[BestOrder[i]] >> (N - 1 - i));
		for (int i = depth; i < N - 1; i++) SumB += (B[BestOrder[i]] >> (N - 1 - i));
		vector<int> Vec1;
		vector<int> Vec2;
		for (int i = 0; i < depth; i++) Vec1.push_back(BestOrder[i]);
		for (int i = depth; i < N - 1; i++) Vec2.push_back(BestOrder[i]);
		dfs(0, SumA, SumB, Vec1, Vec2);
		if (clock() - StartTime > 80 * CLOCKS_PER_SEC / 100) break;
	}

	// Step 4. 出力
	vector<pair<int, int>> Answer;
	for (int i = 0; i < FinalOrder.size(); i++) Answer.push_back(make_pair(1, FinalOrder[i]));
	cout << Answer.size() << endl;
	for (pair<int, int> ans : Answer) cout << ans.first << " " << ans.second << endl;
	return 0;
}
0