結果

問題 No.42 貯金箱の溜息
ユーザー Mao-beta
提出日時 2024-03-01 10:38:09
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 2,271 bytes
コンパイル時間 273 ms
コンパイル使用メモリ 82,392 KB
実行使用メモリ 83,356 KB
最終ジャッジ日時 2024-09-29 13:10:03
合計ジャッジ時間 12,965 ms
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
other TLE * 1 -- * 2
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
import math
import bisect
from heapq import heapify, heappop, heappush
from collections import deque, defaultdict, Counter
from functools import lru_cache
from itertools import accumulate, combinations, permutations, product
sys.setrecursionlimit(1000000)
MOD = 10 ** 9 + 9
MOD99 = 998244353
input = lambda: sys.stdin.readline().strip()
NI = lambda: int(input())
NMI = lambda: map(int, input().split())
NLI = lambda: list(NMI())
SI = lambda: input()
SMI = lambda: input().split()
SLI = lambda: list(SMI())
EI = lambda m: [NLI() for _ in range(m)]
def mul(f, g, mod=998244353):
""""""
fn = len(f)
gn = len(g)
res = [0] * (fn + gn - 1)
for fi in range(fn):
for gi in range(gn):
res[fi+gi] += f[fi] * g[gi] % mod
res[fi+gi] %= mod
return res
def bostan_mori(P: list, Q: list, n: int, mod=998244353):
"""
d+1Qn mod
A = P / Q
O(M(d)logN) M(d)d(O(d^2 logN))
http://q.c.titech.ac.jp/docs/progs/polynomial_division.html
:param P: dlist
:param Q: d+1list
( An - An-1 - An-2 = 0 Q=[1, -1, -1])
:param n: n(0-index)
:return: A[n]
"""
while n > 0:
Qm = [-q if i % 2 else q for i, q in enumerate(Q)]
V = mul(Q, Qm, mod)
Q = V[::2]
PQm = mul(P, Qm, mod)
if n % 2 == 0:
P = PQm[::2]
n >>= 1
else:
P = PQm[1::2]
n >>= 1
return P[0]
def mul_sparse(f: list, a, b, k, M):
"""(a + b * x^k) x^M"""
res = f.copy()
for i in range(M+1):
res[i] += f[i] * (a-1)
if i+k <= M:
res[i+k] += f[i] * b
res[i] %= MOD
return res
def main():
C = [1, 5, 10, 50, 100, 500]
D = sum(C)
Q = [0] * (D+1)
Q[0] = 1
for c in C:
Q = mul_sparse(Q, 1, -1, c, D)
T = NI()
for _ in range(T):
M = NI()
P = [0] * D
P[0] = 1
X = bostan_mori(P, Q, M, MOD)
print(X)
if __name__ == "__main__":
main()
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0