結果
| 問題 | 
                            No.2665 Minimize Inversions of Deque
                             | 
                    
| コンテスト | |
| ユーザー | 
                             tenten
                         | 
                    
| 提出日時 | 2024-03-12 11:29:28 | 
| 言語 | Java  (openjdk 23)  | 
                    
| 結果 | 
                             
                                AC
                                 
                             
                            
                         | 
                    
| 実行時間 | 564 ms / 2,000 ms | 
| コード長 | 2,924 bytes | 
| コンパイル時間 | 2,518 ms | 
| コンパイル使用メモリ | 93,416 KB | 
| 実行使用メモリ | 67,212 KB | 
| 最終ジャッジ日時 | 2024-09-29 22:15:08 | 
| 合計ジャッジ時間 | 20,261 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge1 / judge5 | 
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| ファイルパターン | 結果 | 
|---|---|
| other | AC * 40 | 
ソースコード
import java.io.*;
import java.util.*;
import java.util.function.*;
import java.util.stream.*;
public class Main {
    public static void main(String[] args) throws Exception {
        Scanner sc = new Scanner();
        int t = sc.nextInt();
        String result = IntStream.range(0, t).mapToObj(p -> {
            int n = sc.nextInt();
            BinaryIndexedTree bit = new BinaryIndexedTree(n + 1);
            Deque<Integer> current = new ArrayDeque<>();
            int tmp = sc.nextInt();
            current.addLast(tmp);
            bit.add(tmp, 1);
            long count = 0;
            for (int i = 1; i < n; i++) {
                int x = sc.nextInt();
                int left = bit.getSum(x);
                int right = i - left;
                if (left < right || (left == right && current.peek() > x)) {
                    current.addFirst(x);
                    count += left;
                } else {
                    current.addLast(x);
                    count += right;
                }
                bit.add(x, 1);
            }
            return count + "\n" + current.stream().map(x -> x.toString())
                .collect(Collectors.joining(" "));
        }).collect(Collectors.joining("\n"));
        System.out.println(result);
    }
}
class BinaryIndexedTree {
    int size;
    int[] tree;
    
    public BinaryIndexedTree(int size) {
        this.size = size;
        tree = new int[size];
    }
    
    public void add(int idx, int value) {
        int mask = 1;
        while (idx < size) {
            if ((idx & mask) != 0) {
                tree[idx] += value;
                idx += mask;
            }
            mask <<= 1;
        }
    }
    
    public int getSum(int from, int to) {
        return getSum(to) - getSum(from - 1);
    }
    
    public int getSum(int x) {
        int mask = 1;
        int ans = 0;
        while (x > 0) {
            if ((x & mask) != 0) {
                ans += tree[x];
                x -= mask;
            }
            mask <<= 1;
        }
        return ans;
    }
}
class Scanner {
    BufferedReader br;
    StringTokenizer st = new StringTokenizer("");
    StringBuilder sb = new StringBuilder();
    
    public Scanner() {
        try {
            br = new BufferedReader(new InputStreamReader(System.in));
        } catch (Exception e) {
            
        }
    }
    
    public int nextInt() {
        return Integer.parseInt(next());
    }
    
    public long nextLong() {
        return Long.parseLong(next());
    }
    
    public double nextDouble() {
        return Double.parseDouble(next());
    }
    
    public String next() {
        try {
            while (!st.hasMoreTokens()) {
                st = new StringTokenizer(br.readLine());
            }
        } catch (Exception e) {
            e.printStackTrace();
        } finally {
            return st.nextToken();
        }
    }
    
}
            
            
            
        
            
tenten