結果
問題 |
No.2665 Minimize Inversions of Deque
|
ユーザー |
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提出日時 | 2024-03-12 11:29:28 |
言語 | Java (openjdk 23) |
結果 |
AC
|
実行時間 | 564 ms / 2,000 ms |
コード長 | 2,924 bytes |
コンパイル時間 | 2,518 ms |
コンパイル使用メモリ | 93,416 KB |
実行使用メモリ | 67,212 KB |
最終ジャッジ日時 | 2024-09-29 22:15:08 |
合計ジャッジ時間 | 20,261 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
other | AC * 40 |
ソースコード
import java.io.*; import java.util.*; import java.util.function.*; import java.util.stream.*; public class Main { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(); int t = sc.nextInt(); String result = IntStream.range(0, t).mapToObj(p -> { int n = sc.nextInt(); BinaryIndexedTree bit = new BinaryIndexedTree(n + 1); Deque<Integer> current = new ArrayDeque<>(); int tmp = sc.nextInt(); current.addLast(tmp); bit.add(tmp, 1); long count = 0; for (int i = 1; i < n; i++) { int x = sc.nextInt(); int left = bit.getSum(x); int right = i - left; if (left < right || (left == right && current.peek() > x)) { current.addFirst(x); count += left; } else { current.addLast(x); count += right; } bit.add(x, 1); } return count + "\n" + current.stream().map(x -> x.toString()) .collect(Collectors.joining(" ")); }).collect(Collectors.joining("\n")); System.out.println(result); } } class BinaryIndexedTree { int size; int[] tree; public BinaryIndexedTree(int size) { this.size = size; tree = new int[size]; } public void add(int idx, int value) { int mask = 1; while (idx < size) { if ((idx & mask) != 0) { tree[idx] += value; idx += mask; } mask <<= 1; } } public int getSum(int from, int to) { return getSum(to) - getSum(from - 1); } public int getSum(int x) { int mask = 1; int ans = 0; while (x > 0) { if ((x & mask) != 0) { ans += tree[x]; x -= mask; } mask <<= 1; } return ans; } } class Scanner { BufferedReader br; StringTokenizer st = new StringTokenizer(""); StringBuilder sb = new StringBuilder(); public Scanner() { try { br = new BufferedReader(new InputStreamReader(System.in)); } catch (Exception e) { } } public int nextInt() { return Integer.parseInt(next()); } public long nextLong() { return Long.parseLong(next()); } public double nextDouble() { return Double.parseDouble(next()); } public String next() { try { while (!st.hasMoreTokens()) { st = new StringTokenizer(br.readLine()); } } catch (Exception e) { e.printStackTrace(); } finally { return st.nextToken(); } } }