結果

問題 No.2676 A Tourist
コンテスト
ユーザー 2qbingxuan
提出日時 2024-03-15 23:02:20
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 392 ms / 5,000 ms
コード長 6,439 bytes
コンパイル時間 3,078 ms
コンパイル使用メモリ 264,520 KB
実行使用メモリ 105,600 KB
最終ジャッジ日時 2024-09-30 02:36:49
合計ジャッジ時間 12,987 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff # 

// An AC a day keeps the doctor away.
#include <bits/stdc++.h>
using namespace std;

/*{{{*/
#define all(x) begin(x), end(x)
#ifdef CKISEKI
#include <experimental/iterator>
#define safe cerr<<__PRETTY_FUNCTION__<<" line "<<__LINE__<<" safe\n"
#define debug(a...) debug_(#a, a)
#define orange(a...) orange_(#a, a)
void debug_(auto s, auto ...a) {
  cerr << "\e[1;32m(" << s << ") = (";
  int f = 0;
  (..., (cerr << (f++ ? ", " : "") << a));
  cerr << ")\e[0m\n";
}
void orange_(auto s, auto L, auto R) {
  cerr << "\e[1;33m[ " << s << " ] = [ ";
  using namespace experimental;
  copy(L, R, make_ostream_joiner(cerr, ", "));
  cerr << " ]\e[0m\n";
}
#else
#define safe ((void)0)
#define debug(...) safe
#define orange(...) safe
#endif

template <typename T, T MOD> class Modular {
  public:
    constexpr Modular() : v() {}
    template <typename U> Modular(const U &u) { v = (0 <= u && u < MOD ? u : (u%MOD+MOD)%MOD); }
    template <typename U> explicit operator U() const { return U(v); }
    T operator()() const { return v; }
#define REFOP(type, expr...) Modular &operator type (const Modular &rhs) { return expr, *this; }
    REFOP(+=, v += rhs.v - MOD, v += MOD & (v >> width)) ; REFOP(-=, v -= rhs.v, v += MOD & (v >> width))
    // fits for MOD^2 <= 9e18
    REFOP(*=, v = static_cast<T>(1LL * v * rhs.v % MOD)) ; REFOP(/=, *this *= inverse(rhs.v))
#define VALOP(op) friend Modular operator op (Modular a, const Modular &b) { return a op##= b; }
    VALOP(+) ; VALOP(-) ; VALOP(*) ; VALOP(/)
    Modular operator-() const { return 0 - *this; }
    friend bool operator == (const Modular &lhs, const Modular &rhs) { return lhs.v == rhs.v; }
    friend bool operator != (const Modular &lhs, const Modular &rhs) { return lhs.v != rhs.v; }
    friend std::istream & operator>>(std::istream &I, Modular &m) { T x; I >> x, m = x; return I; }
    friend std::ostream & operator<<(std::ostream &O, const Modular &m) { return O << m.v; }
  private:
    constexpr static int width = sizeof(T) * 8 - 1;
    T v;
    static T inverse(T a) {
      // copy from tourist's template
      T u = 0, v = 1, m = MOD;
      while (a != 0) {
        T t = m / a;
        m -= t * a; std::swap(a, m);
        u -= t * v; std::swap(u, v);
      }
      assert(m == 1);
      return u;
    }
};

using lld = int64_t;
using llf = long double;
template <typename T> using max_heap = std::priority_queue<T,vector<T>,less<T> >;
template <typename T> using min_heap = std::priority_queue<T,vector<T>,greater<T> >;
template <typename V, typename T> int get_pos(const V &v, T x) { return lower_bound(all(v),x) - begin(v); }
template <typename V> void sort_uni(V &v) { sort(all(v)), v.erase(unique(all(v)),end(v)); }
template <typename T> bool chmin(T &x, const T &v) { return v < x ? (x=v, true) : false; }
template <typename T> bool chmax(T &x, const T &v) { return x < v ? (x=v, true) : false; }
constexpr inline lld cdiv(lld x, lld m) { return x/m + (x%m ? (x<0) ^ (m>0) : 0); } // ceiling divide
constexpr inline lld modpow(lld e,lld p,lld m) { lld r=1; for(e%=m;p;p>>=1,e=e*e%m) if(p&1) r=r*e%m; return r; }/*}}}*/

constexpr llf eps = 1e-9;
constexpr lld maxn = 200025, INF = 1e18, mod = 998244353, K = 14699, inf = 1e9;
using Mint = Modular<int, mod>;
Mint modpow(Mint e, uint64_t p) { Mint r = 1; while (p) (p&1) && (r *= e), e *= e, p >>= 1; return r; } // 0^0 = 1

const auto dummy = [] { return cin.tie(nullptr)->sync_with_stdio(false); }();

using PII = pair<int,int>;

int lowbit(int x) {
  return x & -x;
}

struct LBD {
  int n, timer, chains;
  vector<vector<int>> G;
  vector<int> tl, tr, ord, chain, top, dep, pa;
  // chains : number of chain
  // tl, tr[u] : subtree interval in the seq. of u
  // top[i] : top of the chain of vertex i
  // chian[u] : chain id of the chain u is on
  void predfs(int u, int f) {
    dep[u] = dep[pa[u] = f] + 1;
    for (int v : G[u]) if (v != f) {
      predfs(v, u);
      if (lowbit(chain[u]) < lowbit(chain[v]))
        chain[u] = chain[v];
    }
    if (chain[u] == 0) chain[u] = ++chains;
  }
  void dfschain(int u, int f, int t) {
    ord[timer] = u;
    tl[u] = timer++; top[u] = t;
    for (int v : G[u])
      if (v != f and chain[v] == chain[u])
        dfschain(v, u, t);
    for (int v : G[u])
      if (v != f and chain[v] != chain[u])
        dfschain(v, u, v);
    tr[u] = timer;
  }
public:
  LBD(auto &&G_) : n((int)size(G_)),
    timer(0), chains(0), G(G_), tl(n), tr(n),
      ord(n),
      chain(n), top(n + 1, -1), dep(n), pa(n)
    { predfs(0, 0); dfschain(0, 0, 0); }
  PII get_subtree(int u) { return {tl[u], tr[u]}; }
  vector<PII> get_path(int u, int v) {
    vector<PII> res;
    while (top[u] != top[v]) {
      if (dep[top[u]] < dep[top[v]]) swap(u, v);
      int s = top[u];
      res.emplace_back(tl[s], tl[u] + 1);
      u = pa[s];
    }
    if (dep[u] < dep[v]) swap(u, v);
    res.emplace_back(tl[v], tl[u] + 1);
    return res;
  }
}; // 記得在資結上對點的修改要改成對其 dfs 序的修改

struct Segtree {
  int n;
  vector<lld> sum;
  Segtree(int n_) : n(n_), sum(n * 2) {}
  void edit(int p, lld x) {
    p += n;
    sum[p] = x;
    while (p >>= 1)
      sum[p] = sum[p << 1] + sum[p << 1 | 1];
  }
  lld query(int l, int r) {
    lld res = 0;
    for (l += n, r += n; l < r; l >>= 1, r >>= 1) {
      if (l & 1) res = res + sum[l++];
      if (r & 1) res = res + sum[--r];
    }
    return res;
  }
};

signed main() {
  int N, Q;
  cin >> N >> Q;

  vector<lld> a(N), cha(N);
  for (auto &x : a) cin >> x;

  vector<vector<int>> g(N);
  for (int i = 1; i < N; i++) {
    int u, v;
    cin >> u >> v;
    --u, --v;
    g[u].emplace_back(v);
    g[v].emplace_back(u);
  }

  LBD lbd(g);
  Segtree sgt(N);

  for (int i = 1; i < N; i++) {
    cha[lbd.pa[i]] += a[i];
  }
  for (int i = 0; i < N; i++)
    sgt.edit(lbd.tl[i], cha[i]);

  while (Q--) {
    int t;
    cin >> t;
    if (t == 0) {
      int v, x;
      cin >> v >> x;
      --v;

      a[v] += x;
      if (v != 0) {
        cha[lbd.pa[v]] += x;
        sgt.edit(lbd.tl[lbd.pa[v]], cha[lbd.pa[v]]);
      }
    } else {
      int u, v;
      cin >> u >> v;
      --u, --v;

      auto path = lbd.get_path(u, v);

      lld ans = 0;
      for (auto [l, r] : path) {
        ans += sgt.query(l, r);
      }
      int w = lbd.ord[path.back().first];

      debug(u, v, w);

      ans += a[w]; // w
      if (w != 0)
        ans += a[lbd.pa[w]]; // pa[w]

      cout << ans << '\n';
    }
  }

}
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