結果
問題 | No.2376 障害物競プロ |
ユーザー |
|
提出日時 | 2024-03-19 21:48:19 |
言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,009 ms / 4,000 ms |
コード長 | 2,452 bytes |
コンパイル時間 | 4,436 ms |
コンパイル使用メモリ | 328,064 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-09-30 05:45:39 |
合計ジャッジ時間 | 63,822 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 40 |
ソースコード
#include <bits/extc++.h>template <class S, class T>std::ostream &operator<<(std::ostream &os, const std::pair<S, T> &p) {os << "[" << p.first << " " << p.second << "]";return os;}int main() {using namespace std;unsigned N, M;cin >> N >> M;using point = pair<unsigned long, unsigned long>;vector<pair<point, point>> segments(N);for (auto &&[p1, p2] : segments) {auto &&[x1, y1]{p1};auto &&[x2, y2]{p2};long a, b, c, d;cin >> a >> b >> c >> d;x1 = a + 10000;y1 = b + 10000;x2 = c + 10000;y2 = d + 10000;}vector distances(2 * N, vector<long double>(2 * N, sqrt(numeric_limits<long double>::max())));const auto side{[](const auto &p, const auto &segment) {const auto &[x, y]{p};const auto &[p1, p2]{segment};const auto &[x1, y1]{p1};const auto &[x2, y2]{p2};const auto positive_part{x1 * y2 + x2 * y + x * y1};const auto negative_part{x2 * y1 + x * y2 + x1 * y};return (positive_part > negative_part) - (positive_part < negative_part);}};for (unsigned i{}; i < 2 * N; ++i) {const auto &p1{i & 1 ? segments[i / 2].second : segments[i / 2].first};for (unsigned j{}; j < 2 * N; ++j) {const auto &p2{j & 1 ? segments[j / 2].second : segments[j / 2].first};if (ranges::all_of(segments, [&side, &p1, &p2](const auto &s) {auto x{side(p1, s)}, y{side(p2, s)};auto t{side(s.first, make_pair(p1, p2))}, u{side(s.second, make_pair(p1, p2))};if (x * y + 1 == 0 && t * u + 1 == 0)return false;return true;}))distances[i][j] = hypot(static_cast<long double>(p1.first) - p2.first, static_cast<long double>(p1.second) - p2.second);}}for (unsigned _{}; _ < 3; ++_)for (unsigned k{}; k < 2 * N; ++k)for (unsigned i{}; i < 2 * N; ++i)for (unsigned j{}; j < 2 * N; ++j)distances[i][j] = min(distances[i][j], distances[i][k] + distances[k][j]);cout << fixed << setprecision(15);for (unsigned i{}, a, b, c, d; i < M; ++i) {cin >> a >> b >> c >> d;--a;--b;--c;--d;cout << distances[a * 2 + b][c * 2 + d] << endl;}return 0;}