結果

問題 No.2674 k-Walk on Bipartite
ユーザー srjywrdnprkt
提出日時 2024-03-20 01:34:17
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 87 ms / 2,000 ms
コード長 2,716 bytes
コンパイル時間 2,046 ms
コンパイル使用メモリ 205,128 KB
最終ジャッジ日時 2025-02-20 07:57:22
ジャッジサーバーID
(参考情報)
judge4 / judge1
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ファイルパターン 結果
sample AC * 3
other AC * 36
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ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
struct UnionFind {
int ngroup, N;
vector<int> par, siz;
UnionFind(int _N) : N(_N), par(_N), siz(_N){
ngroup = _N;
for(int i = 0; i < N; i++) par[i] = i, siz[i] = 1;
}
int root(int x) {
if (par[x] == x) return x;
return par[x] = root(par[x]);
}
int unite(int x, int y) {
int rx = root(x), ry = root(y);
if (rx == ry) return rx;
ngroup--;
if (siz[rx] > siz[ry]) swap(rx, ry);
par[rx] = ry; siz[ry] += siz[rx];
return ry;
}
bool same(int x, int y) {
int rx = root(x), ry = root(y);
return rx == ry;
}
int size(int x) {return siz[root(x)];}
int group_count() {return ngroup;}
vector<vector<int>> groups(){
vector<int> rev(N); int nrt=0;
for (int i=0; i<N; i++) if (root(i) == i) rev[i] = nrt, nrt++;
vector<vector<int>> res(nrt);
for (int i=0; i<N; i++) res[rev[root(i)]].push_back(i);
return res;
}
};
vector<int> bfs(vector<vector<int>> &E, int start){
int N = E.size();
int from, to;
queue<int> que;
vector<int> dist(N, 1e9);
dist[start] = 0;
que.push(start);
while(!que.empty()){
from = que.front();
que.pop();
for (auto to : E[from]){
if (dist[to] != 1e9) continue;
dist[to] = dist[from] + 1;
que.push(to);
}
}
return dist;
}
int main(){
cin.tie(nullptr);
ios_base::sync_with_stdio(false);
int N, M, s, t, k, a, b;
cin >> N >> M >> s >> t >> k;
auto YES = [](){cout << "Yes" << endl; exit(0);};
auto NO = [](){cout << "No" << endl; exit(0);};
auto UNKNOWN = [](){cout << "Unknown" << endl; exit(0);};
vector<vector<int>> E(N+1);
UnionFind uf(N+1);
for (int i=1; i<=M; i++){
cin >> a >> b;
E[a].push_back(b);
E[b].push_back(a);
uf.unite(a, b);
}
if (!uf.same(s, t)){
if (k % 2 == 1) UNKNOWN();
if (uf.size(s) >= 2 || uf.size(t) >= 2) UNKNOWN();
if (N > 2) UNKNOWN();
NO();
}
if (s == t && M == 0){
if (N == 1) NO();
if (k % 2 == 1) NO();
UNKNOWN();
}
vector<int> color(N+1, -1);
auto dfs=[&](auto self, int from)->void{
for (auto to : E[from]){
if (color[to] != -1) continue;
color[to] = 1 - color[from];
self(self, to);
}
};
color[s] = 0;
dfs(dfs, s);
if (abs(color[s]-color[t]) % 2 != k % 2) NO();
vector<int> dist = bfs(E, s);
if (dist[t] <= k) YES();
else UNKNOWN();
return 0;
}
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