結果

問題 No.2686 商品券の使い道
ユーザー shinchan
提出日時 2024-03-20 23:29:55
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 3,796 bytes
コンパイル時間 2,292 ms
コンパイル使用メモリ 210,304 KB
最終ジャッジ日時 2025-02-20 10:10:11
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 3 WA * 6 TLE * 1 -- * 38
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
#define aint(v) (v).begin(),(v).end()
#define pb(a) push_back(a)
#define rep(i, n) for(int i=0;i<n;i++)
#define foa(e, v) for(auto&& e : v)
#define dout(a) cout<<fixed<<setprecision(10)<<a<<endl;
using ll = long long;
const ll MOD7 = 1000000007, MOD998 = 998244353, INF = (1LL << 60);
int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    int n, m, q;
    cin >> n >> m >> q;
    vector<int> a(n), b(n);
    rep(i, n) cin >> a[i] >> b[i];
    int N = 14;
    if(n <= N) {
        ll ans = 0;
        int mask = 1;
        rep(i, n) mask *= 3;
        rep(bit, mask) {
            ll sum = 0;
            int summ = 0, sumq = 0;
            int num = bit;
            bool ng = false;
            rep(i, n) {
                if(num % 3 == 1) {
                    sum += b[i];
                    summ += a[i];
                    if(summ > m) {
                        ng = true;
                        break;
                    }
                } else if(num % 3 == 2) {
                    sum += b[i];
                    sumq += a[i];
                    if(sumq > q) {
                        ng = true;
                        break;
                    }
                }
                num /= 3;
            }
            if(ng) continue;
            if(summ <= m and sumq <= q) {
                ans = max(ans, sum);
            }
        }
        cout << ans << endl;
        return 0;
    }
    
    ll ans = 0;
    int mask = 1;
    rep(i, N) mask *= 3;

    map<int, set<pair<int, ll>>> dp;
    rep(bit, mask) {
        ll sum = 0;
        int summ = 0, sumq = 0;
        int num = bit;
        bool ng = false;
        rep(i, N) {
            if(num % 3 == 1) {
                sum += b[i];
                summ += a[i];
                if(summ > m) {
                    ng = true;
                    break;
                }
            } else if(num % 3 == 2) {
                sum += b[i];
                sumq += a[i];
                if(sumq > q) {
                    ng = true;
                    break;
                }
            }
            num /= 3;
        }
        if(ng) continue;
        if(summ <= m and sumq <= q) {
            ans = max(ans, sum);
            if(dp.count(summ)) {
                auto itr = dp[summ].lower_bound({sumq, sum});
                while(itr != dp[summ].end()) {
                    if(itr->second < sum) itr = dp[summ].erase(itr);
                    else break;
                }
                if(itr != dp[summ].begin()) {
                    itr --;
                    if(itr->second >= sum) continue;
                } 
            } 
            dp[summ].insert({sumq, sum});
        }
    }
    rep(i, n - N) mask *= 3;
    rep(bit, mask) {
        ll sum = 0;
        int summ = 0, sumq = 0;
        int num = bit;
        bool ng = false;
        for(int i = N; i < n; i ++) {
            if(num % 3 == 1) {
                sum += b[i];
                summ += a[i];
                if(summ > m) {
                    ng = true;
                    break;
                }
            } else if(num % 3 == 2) {
                sum += b[i];
                sumq += a[i];
                if(sumq > q) {
                    ng = true;
                    break;
                }
            }
            num /= 3;
        }
        if(ng) break;
        if(summ <= m and sumq <= q) {
            ans = max(ans, sum);
            for(auto [s1, st]: dp) {
                if(s1 + summ > m) continue;
                auto itr = st.upper_bound({q - sumq, INF});
                if(itr == st.begin()) continue;
                itr --;
                ans = max(ans, sum + itr->second);
            }
        }
    }
    cout << ans << endl;

    return 0;
}
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