結果
問題 | No.168 ものさし |
ユーザー |
|
提出日時 | 2024-03-22 11:45:31 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 1,008 ms / 2,000 ms |
コード長 | 3,033 bytes |
コンパイル時間 | 422 ms |
コンパイル使用メモリ | 82,040 KB |
実行使用メモリ | 86,960 KB |
最終ジャッジ日時 | 2024-09-30 10:33:59 |
合計ジャッジ時間 | 9,518 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 19 |
ソースコード
import sysimport mathimport bisectfrom heapq import heapify, heappop, heappushfrom collections import deque, defaultdict, Counterfrom functools import lru_cachefrom itertools import accumulate, combinations, permutations, productsys.setrecursionlimit(1000000)MOD = 10 ** 9 + 7MOD99 = 998244353input = lambda: sys.stdin.readline().strip()NI = lambda: int(input())NMI = lambda: map(int, input().split())NLI = lambda: list(NMI())SI = lambda: input()SMI = lambda: input().split()SLI = lambda: list(SMI())EI = lambda m: [NLI() for _ in range(m)]from collections import defaultdictclass UnionFind:def __init__(self, n):# 親要素のノード番号を格納 xが根のとき-(サイズ)を格納self.par = [-1 for i in range(n)]self.n = nself.roots = set(range(n))self.group_num = nself.members = defaultdict(set)for i in range(n):self.members[i].add(i)def find(self, x):# 根ならその番号を返すif self.par[x] < 0:return xelse:# 親の親は親self.par[x] = self.find(self.par[x])return self.par[x]def is_same(self, x, y):# 根が同じならTruereturn self.find(x) == self.find(y)def unite(self, x, y):x = self.find(x)y = self.find(y)if x == y: return# 木のサイズを比較し、小さいほうから大きいほうへつなぐif self.par[x] > self.par[y]:x, y = y, xself.group_num -= 1self.roots.discard(y)assert self.group_num == len(self.roots)self.members[x] |= self.members[y]self.members[y] = set()self.par[x] += self.par[y]self.par[y] = xdef size(self, x):return -self.par[self.find(x)]def get_members(self, x):root = self.find(x)return self.members[root]def get_roots(self):return self.rootsdef group_count(self):return len(self.roots)def all_group_members(self):return self.membersdef __repr__(self):return '\n'.join('{}: {}'.format(r, self.members[r]) for r in self.roots)def main():N = NI()XY = EI(N)D = [[0]*N for _ in range(N)]for i in range(N):for j in range(N):xi, yi = XY[i]xj, yj = XY[j]d2 = (xi-xj)**2 + (yi-yj)**2if d2 == 0:D[i][j] = 0else:d = math.isqrt(d2-1) + 1D[i][j] = (d+9) // 10def judge(X):uf = UnionFind(N)for i in range(N):for j in range(i+1, N):if D[i][j] <= X:uf.unite(i, j)return uf.is_same(0, N-1)ok = 10**20ng = 0while abs(ok - ng) > 1:X = (ok + ng) // 2if judge(X):ok = Xelse:ng = Xprint(ok * 10)if __name__ == "__main__":main()