結果

問題 No.2697 Range LIS Query
ユーザー mymelochan
提出日時 2024-03-22 22:37:35
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 5,248 bytes
コンパイル時間 359 ms
コンパイル使用メモリ 81,776 KB
実行使用メモリ 274,860 KB
最終ジャッジ日時 2024-09-30 12:03:04
合計ジャッジ時間 14,519 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1 WA * 2
other WA * 3 TLE * 1 -- * 11
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

class lazy_segtree():
def update(self,k):self.d[k]=self.op(self.d[2*k],self.d[2*k+1])
def all_apply(self,k,f):
self.d[k]=self.mapping(f,self.d[k])
if (k<self.size):self.lz[k]=self.composition(f,self.lz[k])
def push(self,k):
self.all_apply(2*k,self.lz[k])
self.all_apply(2*k+1,self.lz[k])
self.lz[k]=self.identity
def __init__(self,V,OP,E,MAPPING,COMPOSITION,ID):
self.n=len(V)
self.log=(self.n-1).bit_length()
self.size=1<<self.log
self.d=[E for i in range(2*self.size)]
self.lz=[ID for i in range(self.size)]
self.e=E
self.op=OP
self.mapping=MAPPING
self.composition=COMPOSITION
self.identity=ID
for i in range(self.n):self.d[self.size+i]=V[i]
for i in range(self.size-1,0,-1):self.update(i)
def set(self,p,x):
assert 0<=p and p<self.n
p+=self.size
for i in range(self.log,0,-1):self.push(p>>i)
self.d[p]=x
for i in range(1,self.log+1):self.update(p>>i)
def get(self,p):
assert 0<=p and p<self.n
p+=self.size
for i in range(self.log,0,-1):self.push(p>>i)
return self.d[p]
def prod(self,l,r):
assert 0<=l and l<=r and r<=self.n
if l==r:return self.e
l+=self.size
r+=self.size
for i in range(self.log,0,-1):
if (((l>>i)<<i)!=l):self.push(l>>i)
if (((r>>i)<<i)!=r):self.push(r>>i)
sml,smr=self.e,self.e
while(l<r):
if l&1:
sml=self.op(sml,self.d[l])
l+=1
if r&1:
r-=1
smr=self.op(self.d[r],smr)
l>>=1
r>>=1
return self.op(sml,smr)
def all_prod(self):return self.d[1]
def apply_point(self,p,f):
assert 0<=p and p<self.n
p+=self.size
for i in range(self.log,0,-1):self.push(p>>i)
self.d[p]=self.mapping(f,self.d[p])
for i in range(1,self.log+1):self.update(p>>i)
def apply(self,l,r,f):
assert 0<=l and l<=r and r<=self.n
if l==r:return
l+=self.size
r+=self.size
for i in range(self.log,0,-1):
if (((l>>i)<<i)!=l):self.push(l>>i)
if (((r>>i)<<i)!=r):self.push((r-1)>>i)
l2,r2=l,r
while(l<r):
if (l&1):
self.all_apply(l,f)
l+=1
if (r&1):
r-=1
self.all_apply(r,f)
l>>=1
r>>=1
l,r=l2,r2
for i in range(1,self.log+1):
if (((l>>i)<<i)!=l):self.update(l>>i)
if (((r>>i)<<i)!=r):self.update((r-1)>>i)
def max_right(self,l,g):
assert 0<=l and l<=self.n
assert g(self.e)
if l==self.n:return self.n
l+=self.size
for i in range(self.log,0,-1):self.push(l>>i)
sm=self.e
while(1):
while(l%2==0):l>>=1
if not(g(self.op(sm,self.d[l]))):
while(l<self.size):
self.push(l)
l=(2*l)
if (g(self.op(sm,self.d[l]))):
sm=self.op(sm,self.d[l])
l+=1
return l-self.size
sm=self.op(sm,self.d[l])
l+=1
if (l&-l)==l:break
return self.n
def min_left(self,r,g):
assert (0<=r and r<=self.n)
assert g(self.e)
if r==0:return 0
r+=self.size
for i in range(self.log,0,-1):self.push((r-1)>>i)
sm=self.e
while(1):
r-=1
while(r>1 and (r%2)):r>>=1
if not(g(self.op(self.d[r],sm))):
while(r<self.size):
self.push(r)
r=(2*r+1)
if g(self.op(self.d[r],sm)):
sm=self.op(self.d[r],sm)
r-=1
return r+1-self.size
sm=self.op(self.d[r],sm)
if (r&-r)==r:break
return 0
import sys
from collections import defaultdict
input = sys.stdin.readline
inf = 1<<30
N = int(input())
A = list(map(int,input().split()))
A = [a-1 for a in A]
Q = int(input())
query = [list(map(int,input().split())) for _ in range(Q)]
T = [(0,0),(0,1),(0,2),(0,3),(1,1),(1,2),(1,3),(2,2),(2,3),(3,3)]
LT = len(T)
R = {t:i for i,t in enumerate(T)}
def operate(a,b):
ret = [0]*(LT+1)
ret[-1] = a[-1]+b[-1]
for i in range(4):
for j in range(i,4):
for k in range(j,4):
ret[R[(i,k)]] = max(ret[R[(i,k)]],a[R[(i,j)]] + b[R[(j,k)]])
return ret
def mapping(f,x):
if f == -1:
return x
ret = [0]*(LT+1)
ret[-1] = x[-1]
ret[R[(f,f)]] = ret[-1]
return ret
def composition(f,g):
if f == -1:
return g
return f
init = [[0]*(LT+1) for _ in range(N)]
for i in range(N):
init[i][R[(A[i],A[i])]] = 1
init[i][-1] = 1
sgt = lazy_segtree(
init,
operate,
[0 for _ in range(LT+1)],
mapping,
composition,
-1
)
for q in query:
if q[0] == 1:
l,r = q[1:]
print(max(sgt.prod(l-1,r)))
else:
l,r,x = q[1:]
sgt.apply(l-1,r,x-1)
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