#965804 (PyPy3) No.2702 Nand Nor Matrix

• 問題: No.2702 Nand Nor Matrix
• ユーザー: sotanishy
• 提出日時: 2024-03-29 22:58:37
• 言語: PyPy3 (7.3.15)
• 結果: AC
• 実行時間: 285 ms / 2,000 ms
• コード長: 1,780 bytes
• コンパイル時間: 302 ms
• コンパイル使用メモリ: 82,048 KB
• 実行使用メモリ: 132,356 KB
• 最終ジャッジ日時: 2024-09-30 16:43:45
• 合計ジャッジ時間: 16,895 ms
• ジャッジサーバーID （参考情報）: judge3 / judge4

ファイルパターン	結果
sample	AC * 1
other	AC * 51

ソースコード

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import sys
input = sys.stdin.readline
T = 20
def naive(N, A, B, qs):
    X = [[[0] * N for _ in range(N)] for _ in range(T)]
    for i in range(N):
        X[0][0][i] = A[i]
    for i in range(1, N):
        X[0][i][0] = B[i]
    # print(*["".join(map(str, row)) for row in X], sep="\n")
    # print()
    for t in range(1, T):
        for i in range(N):
            for j in range(N):
                if i == 0 or j == 0:
                    X[t][i][j] = X[t - 1][i][j]
                else:
                    X[t][i][j] = (
                        0
                        if X[t - 1][i][j] + X[t - 1][i - 1][j] + X[t - 1][i][j - 1] >= 2
                        else 1
                    )
        # print(*["".join(map(str, row)) for row in X], sep="\n")
        # print()
    return [X[t][r][c] for t, r, c in qs]
def solve(N, A, B, qs):
    if N == 1:
        return [A[0]] * len(qs)
    row = [-1] * N
    row[0] = B[1]
    for i in range(1, N):
        if row[i - 1] == A[i]:
            row[i] = A[i] ^ 1
        else:
            break
    col = [-1] * N
    col[0] = A[1]
    for i in range(1, N):
        if col[i - 1] == B[i]:
            col[i] = B[i] ^ 1
        else:
            break
    ans = []
    for t, r, c in qs:
        x = -1
        if r == 0:
            x = A[c]
        elif c == 0:
            x = B[r]
        elif col[r] == -1 or row[c] == -1 or r + c > t + 1:
            x = t % 2
        else:
            x = A[c] ^ B[r] ^ A[1] ^ 1
        ans.append(x)
    return ans
N = int(input())
A = list(map(int, input().split()))
B = [A[0]] + [int(input()) for _ in range(N - 1)]
Q = int(input())
qs = []
for _ in range(Q):
    t, r, c = map(int, input().split())
    qs.append((t, r - 1, c - 1))
print(*solve(N, A, B, qs), sep="\n")
 
 
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