結果
問題 | No.8113 How Many Liars Are There? |
ユーザー | 👑 amentorimaru |
提出日時 | 2024-04-02 01:37:37 |
言語 | C++23 (gcc 12.3.0 + boost 1.83.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 5,007 bytes |
コンパイル時間 | 5,102 ms |
コンパイル使用メモリ | 248,268 KB |
実行使用メモリ | 14,024 KB |
最終ジャッジ日時 | 2024-09-30 23:01:03 |
合計ジャッジ時間 | 7,516 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
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testcase_00 | AC | 3 ms
10,144 KB |
testcase_01 | AC | 3 ms
6,812 KB |
testcase_02 | AC | 9 ms
6,816 KB |
testcase_03 | AC | 9 ms
6,824 KB |
testcase_04 | TLE | - |
testcase_05 | -- | - |
testcase_06 | -- | - |
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testcase_63 | -- | - |
ソースコード
#define ATCODER #define _USE_MATH_DEFINES #include<stdio.h> #include<iostream> #include<fstream> #include<algorithm> #include<vector> #include<string> #include <cassert> #include <numeric> #include <unordered_map> #include <unordered_set> #include <queue> #include <math.h> #include <climits> #include <set> #include <map> #include <list> #include <random> #include <iterator> #include <bitset> #include <chrono> #include <type_traits> using namespace std; using ll = long long; using ld = long double; using pll = pair<ll, ll>; using pdd = pair<ld, ld>; //template<claLR T> using pq = priority_queue<T, vector<T>, greater<T>>; #define FOR(i, a, b) for(ll i=(a); i<(b);i++) #define REP(i, n) for(ll i=0; i<(n);i++) #define ROF(i, a, b) for(ll i=(b-1); i>=(a);i--) #define PER(i, n) for(ll i=n-1; i>=0;i--) #define REPREP(i,j,a,b) for(ll i=0;i<a;i++)for(ll j=0;j<b;j++) #define VV(type) vector< vector<type> > #define VV2(type,n,m,val) vector< vector<type> > val;val.resize(n);for(ll i;i<n;i++)val[i].resize(m) #define vec(type) vector<type> #define VEC(type,n,val) vector<type> val;val.resize(n) #define VL vector<ll> #define VVL vector< vector<ll> > #define VP vector< pair<ll,ll> > #define SZ size() #define all(i) begin(i),end(i) #define SORT(i) sort(all(i)) #define BITI(i) (1<<i) #define BITSET(x,i) x | (ll(1)<<i) #define BITCUT(x,i) x & ~(ll(1)<<i) #define EXISTBIT(x,i) (((x>>i) & 1) != 0) #define ALLBIT(n) (ll(1)<<n-1) #define CHMAX(n,v) n=n<v?v:n #define CHMIN(n,v) n=n>v?v:n #define MP(a,b) make_pair(a,b) #define DET2(x1,y1,x2,y2) x1*y2-x2*y1 #define DET3(x1,y1,z1,x2,y2,z2,x3,y3,z3) x1*y2*z3+x2*y3*z1+x3*y1*z2-z1*y2*x3-z2*y3*x1-z3*y1*x2 #define INC(a) for(auto& v:a)v++; #define DEC(a) for(auto& v:a)v--; #define SQU(x) (x)*(x) #define L0 ll(0) #ifdef ATCODER #include <atcoder/all> using namespace atcoder; using mint = modint1000000007; using mint2 = modint998244353; #endif template<typename T = ll> vector<T> read(size_t n) { vector<T> ts(n); for (size_t i = 0; i < n; i++) cin >> ts[i]; return ts; } template<typename TV, const ll N> void read_tuple_impl(TV&) {} template<typename TV, const ll N, typename Head, typename... Tail> void read_tuple_impl(TV& ts) { get<N>(ts).emplace_back(*(istream_iterator<Head>(cin))); read_tuple_impl<TV, N + 1, Tail...>(ts); } template<typename... Ts> decltype(auto) read_tuple(size_t n) { tuple<vector<Ts>...> ts; for (size_t i = 0; i < n; i++) read_tuple_impl<decltype(ts), 0, Ts...>(ts); return ts; } using val = ll; using func = ll; val op(val a, val b) { return max(a, b); } val e() { return -1e18; } //val mp(func f, val a) { // return MP(a.first + f, a.second); //} //func comp(func f, func g) { // return f + g; //} //func id() { return 0; } ll di[4] = { 1,0,-1,0 }; ll dj[4] = { 0,1,0,-1 }; ll si[4] = { 0,3,3,0 }; ll sj[4] = { 0,0,3,3 }; //ll di[4] = { -1,-1,1,1 }; //ll dj[4] = { -1,1,-1,1 }; ll di8[8] = { 0,-1,-1,-1,0,1,1,1 }; ll dj8[8] = { -1,-1,0,1,1,1,0,-1 }; vector<VP> g; ll n, k; vector<bool> vis; pair<bitset<2001>, bitset<2001>> dfs(ll now, ll c, ll root) { vis[now] = true; bitset<2001> res0, res1; res0.set(0); res1.set(1); bool loop = false; for (auto& [v, a] : g[now]) { if (v == root) { loop = true; continue; } auto [r0, r1] = dfs(v, c, root); REP(i, 1000) { ll t = r0[i]; r0[i] = r0[2000 - i]; r0[2000 - i] = t; t = r1[i]; r1[i] = r1[2000 - i]; r1[2000 - i] = t; } bitset<2001> nres0, nres1; REP(i, 2001) { nres0[i] = (res0 & (r1 >> (2000 - i + 1 - a))).any() || (res0 & (r0 >> (2000 - i + a))).any();; nres1[i] = (res1 & (r0 >> (2000 - i + 1 - a))).any() || (res1 & (r1 >> (2000 - i + a))).any(); } res0 = nres0; res1 = nres1; } if (loop) { if (c) { res0 = bitset<2001>(); } else { res1 = bitset<2001>(); } } return make_pair(res0, res1); } ll getroot(VL& p, ll v) { unordered_set<ll> s; s.insert(v); while (1) { v = p[v]; if (s.find(v) != s.end()) return v; } return -1; } void solve() { cin >> n >> k; VL p = read(n); VL a = read(n); vis.resize(n); g.resize(n); DEC(p); REP(i, n) g[p[i]].emplace_back(i, a[i]); bitset<2001> ans; ans.set(0); REP(i, n) { if (vis[i])continue; ll v = getroot(p, i); auto [r00, r01] = dfs(v, 0, v); auto [r10, r11] = dfs(v, 1, v); bitset<2001> res; if (a[v]) { res = r01; res |= r10; res |= r00 << 1; res |= r11 << 1; } else { res = r00; res |= r11; res |= r01 << 1; res |= r10 << 1; } bitset<2001> nans; REP(i, 1000) { ll t = res[i]; res[i] = res[2000 - i]; res[2000 - i] = t; } REP(i, 2001) { nans[i] = (ans & (res >> (2000 - i))).any(); } ans = nans; } if (ans[k]) { cout << "Yes"; } else { cout << "No"; } return; } int main() { ll t = 1; //cin >> t; while (t--) { solve(); } return 0; }