結果

問題 No.2733 Just K-times TSP
ユーザー Today03
提出日時 2024-04-19 22:53:24
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
TLE  
実行時間 -
コード長 3,283 bytes
コンパイル時間 2,348 ms
コンパイル使用メモリ 208,052 KB
最終ジャッジ日時 2025-02-21 05:07:48
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 22 TLE * 1 -- * 9
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int INF = 1e9 + 10;
const ll INFL = 4e18;
template <ll MOD>
struct modint {
ll value;
modint(ll x = 0) {
if (x >= 0) {
value = x % MOD;
} else {
value = MOD - (-x) % MOD;
}
}
modint operator-() const {
return modint(-value);
}
modint operator+() const {
return modint(*this);
}
modint &operator+=(const modint &other) {
value += other.value;
if (value >= MOD) {
value -= MOD;
}
return *this;
}
modint &operator-=(const modint &other) {
value += MOD - other.value;
if (value >= MOD) {
value -= MOD;
}
return *this;
}
modint &operator*=(const modint other) {
value = value * other.value % MOD;
return *this;
}
modint &operator/=(modint other) {
(*this) *= other.inv();
return *this;
}
modint operator+(const modint &other) const {
return modint(*this) += other;
}
modint operator-(const modint &other) const {
return modint(*this) -= other;
}
modint operator*(const modint &other) const {
return modint(*this) *= other;
}
modint operator/(const modint &other) const {
return modint(*this) /= other;
}
modint pow(ll x) const {
modint ret(1), mul(value);
while (x) {
if (x & 1) {
ret *= mul;
}
mul *= mul;
x >>= 1;
}
return ret;
}
modint inv() const {
return pow(MOD - 2);
}
bool operator==(const modint &other) const {
return value == other.value;
}
bool operator!=(const modint &other) const {
return value != other.value;
}
friend ostream &operator<<(ostream &os, const modint &x) {
return os << x.value;
}
friend istream &operator>>(istream &is, modint &x) {
ll v;
is >> v;
x = modint<MOD>(v);
return is;
}
};
using mod998 = modint<998244353>;
using mod107 = modint<1000000007>;
using mint = mod998;
int main() {
int N, M, K;
cin >> N >> M >> K;
vector<vector<int>> G(N);
for (int i = 0; i < M; i++) {
int u, v;
cin >> u >> v;
u--;
v--;
G[u].push_back(v);
G[v].push_back(u);
}
map<pair<int, vector<int>>, mint> dp;
auto F = [&](auto &&F, int now, vector<int> &v) -> mint {
if (dp.count({now, v})) {
return dp[{now, v}];
}
bool ok = true;
for (int i = 0; i < N; i++) {
if (v[i] != K) {
ok = false;
break;
}
}
if (ok) {
return dp[{now, v}] = 1;
}
mint ret = 0;
for (int nxt : G[now]) {
if (v[nxt] == K) {
continue;
}
v[nxt]++;
ret += F(F, nxt, v);
v[nxt]--;
}
return dp[{now, v}] = ret;
};
vector<int> v(N, 0);
mint ans = 0;
for (int i = 0; i < N; i++) {
v[i]++;
ans += F(F, i, v);
v[i]--;
}
cout << ans << endl;
}
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