結果

問題 No.2732 Similar Permutations
ユーザー kaikeykaikey
提出日時 2024-04-19 22:55:19
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 61 ms / 2,000 ms
コード長 4,588 bytes
コンパイル時間 2,337 ms
コンパイル使用メモリ 210,236 KB
実行使用メモリ 9,472 KB
最終ジャッジ日時 2024-10-11 16:53:33
合計ジャッジ時間 17,009 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 101
権限があれば一括ダウンロードができます

ソースコード

diff #

#include "bits/stdc++.h"
#include <random>
#include <chrono>
#define ALL(x) (x).begin(), (x).end()
#define RALL(x) (x).rbegin(), (x).rend()
#define SZ(x) ((lint)(x).size())
#define FOR(i, begin, end) for(lint i=(begin),i##_end_=(end);i<i##_end_;++i)
#define IFOR(i, begin, end) for(lint i=(end)-1,i##_begin_=(begin);i>=i##_begin_;--i)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
#define endk '\n'
using namespace std; typedef unsigned long long _ulong; typedef long long int lint; typedef long double ld; typedef pair<lint, lint> plint; typedef pair<ld, ld> pld;
struct fast_ios { fast_ios() { cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(30); }; } fast_ios_;
template<class T> auto add = [](T a, T b) -> T { return a + b; };
template<class T> auto mul = [](T a, T b) -> T { return a * b; };
template<class T> auto f_max = [](T a, T b) -> T { return max(a, b); };
template<class T> auto f_min = [](T a, T b) -> T { return min(a, b); };
template<class T> using V = vector<T>;
using Vl = V<lint>; using VVl = V<Vl>; using VVVl = V<V<Vl>>; using VVVVl = V<V<V<Vl>>>;
template< typename T > ostream& operator<<(ostream& os, const vector< T >& v) {
	for (int i = 0; i < (int)v.size(); i++) os << v[i] << (i + 1 != v.size() ? " " : "");
	return os;
}
template< typename T >istream& operator>>(istream& is, vector< T >& v) {
	for (T& in : v) is >> in;
	return is;
}
template<class T> bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }
template <class T>
T div_floor(T a, T b) {
	if (b < 0) a *= -1, b *= -1;
	return a >= 0 ? a / b : (a + 1) / b - 1;
}
template <class T>
T div_ceil(T a, T b) {
	if (b < 0) a *= -1, b *= -1;
	return a > 0 ? (a - 1) / b + 1 : a / b;
}
template <class F> struct rec {
	F f;
	rec(F&& f_) : f(std::forward<F>(f_)) {}
	template <class... Args> auto operator()(Args &&... args) const {
		return f(*this, std::forward<Args>(args)...);
	}
};
lint gcd(lint a, lint b) { if (b == 0) return a; else return gcd(b, a % b); }
lint digit(lint a) { return (lint)log10(a); }
lint e_dist(plint a, plint b) { return abs(a.first - b.first) * abs(a.first - b.first) + abs(a.second - b.second) * abs(a.second - b.second); }
lint m_dist(plint a, plint b) { return abs(a.first - b.first) + abs(a.second - b.second); }
bool check_overflow(lint a, lint b, lint limit) { if (b == 0) return false; return a > limit / b; } // a * b > c => true
void Worshall_Floyd(VVl& g) { REP(k, SZ(g)) REP(i, SZ(g)) REP(j, SZ(g)) chmin(g[i][j], g[i][k] + g[k][j]); }
const lint MOD1000000007 = 1000000007, MOD998244353 = 998244353, INF = 2e18;
lint dx[8] = { 0, 1, 0, -1, 1, -1, 1, -1 }, dy[8] = { 1, 0, -1, 0, -1, -1, 1, 1 };
bool YN(bool flag) { cout << (flag ? "YES" : "NO") << endk; return flag; } bool yn(bool flag) { cout << (flag ? "Yes" : "No") << endk; return flag; }
struct Edge {
	lint from, to;
	lint cost;
	Edge() {

	}
	Edge(lint u, lint v, lint c) {
		cost = c;
		from = u;
		to = v;
	}
	bool operator<(const Edge& e) const {
		return cost < e.cost;
	}
};
struct WeightedEdge {
	lint to;
	lint cost;
	WeightedEdge(lint v, lint c) {
		to = v;
		cost = c;
	}
	bool operator<(const WeightedEdge& e) const {
		return cost < e.cost;
	}
};
using WeightedGraph = V<V<WeightedEdge>>;
typedef pair<lint, plint> tlint;
typedef pair<lint, V<tlint>> state;
typedef pair<ld, ld> pld;
typedef pair<lint, tlint> qlint;
typedef pair<lint, qlint> vlint;
typedef pair<Edge, lint> pEd;
typedef pair<plint, V<plint>> vVl;
typedef pair<string, string> pstr;
typedef pair<ld, lint> pint;
typedef pair<lint, set<pint>> pset;

void solve() {
	lint N;
	cin >> N;
	Vl arr(N);
	cin >> arr;

	if (N == 1) {
		cout << -1 << endk;
		return;
	}
	if (N == 2) {
		lint v1 = (arr[0] + 1) ^ (arr[1] + 2);
		lint v2 = (arr[1] + 1) ^ (arr[0] + 2);
		if (v1 == v2) {
			cout << "1 2" << endk;
			cout << "2 1" << endk;
		}
		else {
			cout << -1 << endk;
		}
		return;
	}
	Vl per = { 1, 2, 3 };
	do {
		VVl ans(2, Vl(N));
		REP(i, 3) ans[0][i] = per[i], ans[1][i] = per[i];
		FOR(i, 3, N) ans[0][i] = i + 1, ans[1][i] = i + 1;
		REP(i, 3) {
			FOR(j, i + 1, 3) {
				swap(ans[1][i], ans[1][j]);
				lint v1 = 0, v2 = 0;
				REP(i, N) {
					v1 ^= arr[i] + ans[0][i];
					v2 ^= arr[i] + ans[1][i];
				}
				if (v1 == v2) {
					cout << ans[0] << endk;
					cout << ans[1] << endk;
					return;
				}
				swap(ans[1][i], ans[1][j]);
			}
		}
	} while (next_permutation(ALL(per)));
	assert(false);
}

int main() {
	lint T = 1;
	//cin >> T;
	while (T--) solve();
}
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