結果

問題 No.2742 Car Flow
ユーザー GOTKAKO
提出日時 2024-04-20 11:03:51
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 64 ms / 2,000 ms
コード長 2,178 bytes
コンパイル時間 2,029 ms
コンパイル使用メモリ 198,688 KB
最終ジャッジ日時 2025-02-21 06:13:38
ジャッジサーバーID
（参考情報） 		judge2 / judge5
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 1
other AC * 50
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
long long mod = 998244353;
//入力が必ずmod未満の時に使う.
struct mint{
    long long v = 0;
    mint(){} mint(int a){v = a;} mint(long long a){v = a;} mint(unsigned long long a){v = a;}
    long long val(){return v;}
    void modu(){v %= mod;}
 
    mint repeat2mint(long long a,long long b){
        mint ret = 1,p = a;
        while(b){if(b&1) ret *= p; p *= p; b >>= 1;}
        return ret;
    };
 
    mint operator-(){return mint(0)-mint(v);}
    mint operator+(mint b){return (v+b.v)%mod;}
    mint operator-(mint b){return (v-b.v+mod)%mod;}
    mint operator*(mint b){return v*b.v%mod;}
    mint operator/(mint b){
        if(b.v == 0) assert(false);
        return v*(repeat2mint(b.v,mod-2)).v%mod;
    }
 
    void operator+=(mint b){v = (v+b.v)%mod;}
    void operator-=(mint b){v = (v-b.v+mod)%mod;}
    void operator*=(mint b){v = v*b.v%mod;}
    void operator/=(mint b){
    if(b.v == 0) assert(false);
        v = v*repeat2mint(b.v,mod-2).v%mod;
    }
 
    void operator++(int){v = (v+1)%mod; return;}
    void operator--(int){v = (v-1+mod)%mod; return;}
    bool operator==(mint b){return v == b.v;}
    bool operator!=(mint b){return v != b.v;}
    bool operator>(mint b) {return v >  b.v;}
    bool operator>=(mint b){return v >= b.v;}
    bool operator<(mint b) {return v <  b.v;}
    bool operator<=(mint b){return v <= b.v;}
 
    mint pow(long long x){return repeat2mint(v,x);}
    mint inv(){return mint(1)/v;}
};          
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    
    int N; cin >> N;
    vector B(50,vector<int>(N));
    int one = 0;
    for(auto &b : B.at(0)) cin >> b,one += b;
    one = min(N-one,one);
    cout << (mint(one)/N).v << endl;
return 0;
    for(int i=1; i<50; i++){
        for(int k=0; k<N; k++){
            int pos1 = (k-1+N)%N,pos2 = k,pos3 = (k+1)%N;
            if(B.at(i-1).at(pos1) == 1 && B.at(i-1).at(pos2) == 0) B.at(i).at(k) = 1;
            if(B.at(i-1).at(pos2) == 1 && B.at(i-1).at(pos3) == 1) B.at(i).at(k) = 1; 
        }
    }
    for(int i=0; i<50; i++){
        for(auto b : B.at(i)) cout << b << " "; cout << endl;
    }
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0