結果

問題 No.2731 Two Colors
ユーザー Theta
提出日時 2024-04-23 19:37:32
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 2,147 bytes
コンパイル時間 246 ms
コンパイル使用メモリ 82,072 KB
実行使用メモリ 253,444 KB
最終ジャッジ日時 2024-11-06 01:49:08
合計ジャッジ時間 11,392 ms
ジャッジサーバーID
(参考情報)
judge2 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample -- * 3
other TLE * 1 -- * 32
権限があれば一括ダウンロードができます

ソースコード

diff #

from heapq import heappop, heappush
from itertools import count

DIJ = ((0, 1), (1, 0), (0, -1), (-1, 0))


def main():
    H, W = map(int, input().split())
    board = [list(map(int, input().split())) for _ in range(H)]

    color_0 = set(((H - 1, W - 1),))
    color_1 = set(((0, 0),))

    color_0_neighbors = []
    color_1_neighbors = []
    heappush(color_0_neighbors, (board[H - 2][W - 1], H - 2, W - 1))
    heappush(color_0_neighbors, (board[H - 1][W - 2], H - 1, W - 2))
    heappush(color_1_neighbors, (board[1][0], 1, 0))
    heappush(color_1_neighbors, (board[0][1], 0, 1))

    for idx in count(1):

        if idx % 2 == 1:
            h, w = 0, 0
            while (h, w) in color_1:
                num, h, w = heappop(color_1_neighbors)

            color_1.add((h, w))
            for dij in DIJ:
                neighbor = (h + dij[0], w + dij[1])
                if not (0 <= neighbor[0] < H) or not (0 <= neighbor[1] < W):
                    continue
                if neighbor in color_0:
                    break
                if neighbor in color_1:
                    continue
                heappush(color_1_neighbors,
                         (board[neighbor[0]][neighbor[1]],
                          neighbor[0],
                             neighbor[1]))
            else:
                continue
            break
        else:
            h, w = H - 1, W - 1
            while (h, w) in color_0:
                num, h, w = heappop(color_0_neighbors)
            color_0.add((h, w))
            for dij in DIJ:
                neighbor = (h + dij[0], w + dij[1])
                if not (0 <= neighbor[0] < H) or not (0 <= neighbor[1] < W):
                    continue
                if neighbor in color_1:
                    break
                if neighbor in color_0:
                    continue
                heappush(color_0_neighbors,
                         (board[neighbor[0]][neighbor[1]],
                          neighbor[0],
                             neighbor[1]))
            else:
                continue
            break
    print(idx)


if __name__ == "__main__":
    main()
0