結果
問題 | No.2739 Time is money |
ユーザー |
|
提出日時 | 2024-04-23 20:14:25 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 1,801 ms / 2,000 ms |
コード長 | 2,213 bytes |
コンパイル時間 | 370 ms |
コンパイル使用メモリ | 82,456 KB |
実行使用メモリ | 203,276 KB |
最終ジャッジ日時 | 2024-11-06 02:30:48 |
合計ジャッジ時間 | 24,889 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 18 |
ソースコード
# https://note.nkmk.me/python-union-find/from collections import defaultdictclass UnionFind():def __init__(self, n):self.n = nself.parents = [-1] * ndef find(self, x):if self.parents[x] < 0:return xelse:self.parents[x] = self.find(self.parents[x])return self.parents[x]def union(self, x, y):x = self.find(x)y = self.find(y)if x == y:returnif self.parents[x] > self.parents[y]:x, y = y, xself.parents[x] += self.parents[y]self.parents[y] = xdef size(self, x):return -self.parents[self.find(x)]def same(self, x, y):return self.find(x) == self.find(y)def members(self, x):root = self.find(x)return [i for i in range(self.n) if self.find(i) == root]def roots(self):return [i for i, x in enumerate(self.parents) if x < 0]def group_count(self):return len(self.roots())def all_group_members(self):group_members = defaultdict(list)for member in range(self.n):group_members[self.find(member)].append(member)return group_membersdef __str__(self):return '\n'.join(f'{r}: {m}' for r, m in self.all_group_members().items())N, M, X=map(int, input().split())INPUT=tuple(tuple(map(int, input().split())) for i in range(M))uf=UnionFind(N)for elm in INPUT:u, v, _, __=elmu-=1; v-=1uf.union(u, v)if uf.same(0, N-1)==False: print(-1); exit()del ufedge=[[] for i in range(N)]for elm in INPUT:u, v, C, T=elmu-=1; v-=1edge[u].append((v, C, T))edge[v].append((u, C, T))# 連結 ⇒ 移動可能import heapqd=[]timeMIN=[None for i in range(N)]heapq.heapify(d)# 各タプルは (時間, - 残りのお金, 頂点) で入れるheapq.heappush(d, (0, 0, 0))while len(d)>0:t, mon, v=heapq.heappop(d)mon*=(-1)if timeMIN[v]==None: timeMIN[v]=telse: continuefor nv, C, T in edge[v]:if timeMIN[nv]!=None: continuent=t+Tnmon=mon-Cif nmon<0:nt+=(abs(nmon)+X-1)//Xnmon%=Xheapq.heappush(d, (nt, -nmon, nv))print(timeMIN[N-1])