結果

問題 No.2739 Time is money
ユーザー Butterflv
提出日時 2024-04-23 20:14:25
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 1,801 ms / 2,000 ms
コード長 2,213 bytes
コンパイル時間 370 ms
コンパイル使用メモリ 82,456 KB
実行使用メモリ 203,276 KB
最終ジャッジ日時 2024-11-06 02:30:48
合計ジャッジ時間 24,889 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 18
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

# https://note.nkmk.me/python-union-find/
from collections import defaultdict
class UnionFind():
def __init__(self, n):
self.n = n
self.parents = [-1] * n
def find(self, x):
if self.parents[x] < 0:
return x
else:
self.parents[x] = self.find(self.parents[x])
return self.parents[x]
def union(self, x, y):
x = self.find(x)
y = self.find(y)
if x == y:
return
if self.parents[x] > self.parents[y]:
x, y = y, x
self.parents[x] += self.parents[y]
self.parents[y] = x
def size(self, x):
return -self.parents[self.find(x)]
def same(self, x, y):
return self.find(x) == self.find(y)
def members(self, x):
root = self.find(x)
return [i for i in range(self.n) if self.find(i) == root]
def roots(self):
return [i for i, x in enumerate(self.parents) if x < 0]
def group_count(self):
return len(self.roots())
def all_group_members(self):
group_members = defaultdict(list)
for member in range(self.n):
group_members[self.find(member)].append(member)
return group_members
def __str__(self):
return '\n'.join(f'{r}: {m}' for r, m in self.all_group_members().items())
N, M, X=map(int, input().split())
INPUT=tuple(tuple(map(int, input().split())) for i in range(M))
uf=UnionFind(N)
for elm in INPUT:
u, v, _, __=elm
u-=1; v-=1
uf.union(u, v)
if uf.same(0, N-1)==False: print(-1); exit()
del uf
edge=[[] for i in range(N)]
for elm in INPUT:
u, v, C, T=elm
u-=1; v-=1
edge[u].append((v, C, T))
edge[v].append((u, C, T))
#
import heapq
d=[]
timeMIN=[None for i in range(N)]
heapq.heapify(d)
# (, - , )
heapq.heappush(d, (0, 0, 0))
while len(d)>0:
t, mon, v=heapq.heappop(d)
mon*=(-1)
if timeMIN[v]==None: timeMIN[v]=t
else: continue
for nv, C, T in edge[v]:
if timeMIN[nv]!=None: continue
nt=t+T
nmon=mon-C
if nmon<0:
nt+=(abs(nmon)+X-1)//X
nmon%=X
heapq.heappush(d, (nt, -nmon, nv))
print(timeMIN[N-1])
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