結果
問題 | No.1332 Range Nearest Query |
ユーザー |
|
提出日時 | 2024-04-24 19:31:45 |
言語 | Go (1.23.4) |
結果 |
AC
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実行時間 | 1,251 ms / 2,500 ms |
コード長 | 14,093 bytes |
コンパイル時間 | 15,635 ms |
コンパイル使用メモリ | 235,140 KB |
実行使用メモリ | 91,136 KB |
最終ジャッジ日時 | 2024-11-07 04:24:13 |
合計ジャッジ時間 | 58,466 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 48 |
ソースコード
// !deprecated//// 维护区间贡献的 Wavelet Matrix// !注意查询区间贡献时, 异或无效// CountRange(start, end, a, b, xor) - 区间 [start, end) 中值在 [a, b) 之间的数的个数和这些数的和.// CountPrefix(start, end, x, xor) - 区间 [start, end) 中值在 [0, x) 之间的数的个数和这些数的和.// Kth(start, end, k, xor) - 区间 [start, end) 中第 k 小的数(0-indexed) 和前 k 小的数的和(不包括这个数).// Floor(start, end, x, xor) - 区间 [start, end) 中值小于等于 x 的最大值// Ceiling(start, end, x, xor) - 区间 [start, end) 中值大于等于 x 的最小值// MaxRightValue(start, end, xor, check) - 返回使得 check(prefixSum) 为 true 的最大value, 其中prefixSum为[0,val)内的数的和.// MaxRightCount(start, end, xor, check) - 返回使得 check(prefixSum) 为 true 的区间前缀个数的最大值.package mainimport ("bufio""fmt""math""math/bits""os""sort""time")func main() {区间前驱后继()// demo()// CF1771F()// 区间最短距离和()}// https://yukicoder.me/problems/no/1332func 区间前驱后继() {in := bufio.NewReader(os.Stdin)out := bufio.NewWriter(os.Stdout)defer out.Flush()var n int32fmt.Fscan(in, &n)nums := make([]int, n)for i := int32(0); i < n; i++ {fmt.Fscan(in, &nums[i])}wm := NewWaveletMatrixSum(nums, -1, func() int { return 0 }, func(a, b int) int { return a + b }, func(a int) int { return -a }, nil)var q int32fmt.Fscan(in, &q)for i := int32(0); i < q; i++ {var start, end, x intfmt.Fscan(in, &start, &end, &x)start--res := math.MaxIntfloor := wm.Floor(start, end, x, 0)if floor != -INF {res = min(res, abs(x-floor))}ceil := wm.Ceiling(start, end, x, 0)if ceil != INF {res = min(res, abs(x-ceil))}fmt.Fprintln(out, res)}}// Hossam and Range Minimum Query// https://www.luogu.com.cn/problem/CF1771F// 在线查询区间出现次数为奇数的数的最小值.//// 异或哈希+Wavelet Matrix二分: 最大值<x时,区间内的异或和是否为0(出现次数全是偶数次).func CF1771F() {in := bufio.NewReader(os.Stdin)out := bufio.NewWriter(os.Stdout)defer out.Flush()var n intfmt.Fscan(in, &n)nums := make([]int, n)for i := 0; i < n; i++ {fmt.Fscan(in, &nums[i])}getRank, getValue, size := DiscretizeCompressed(nums, 0)for i := 0; i < n; i++ {nums[i] = getRank(nums[i])}R := NewRandom()xorHash := make([]int, size)for i := 0; i < size; i++ {xorHash[i] = int(uint32(R.Rng()))}wm := NewWaveletMatrixSum(nums, -1,func() E { return 0 },func(a, b E) E { return a ^ b },func(a E) E { return a },func(v int) E { return xorHash[v] },)preRes := 0normalize := func(v int) int {return v ^ preRes}var q intfmt.Fscan(in, &q)for i := 0; i < q; i++ {var left, right intfmt.Fscan(in, &left, &right)left = normalize(left)right = normalize(right)left--res := wm.MaxRightValue(left, right, 0, func(preSum E) bool { return preSum == 0 })if res == INF {res = 0} else {res = getValue(res)}preRes = resfmt.Fprintln(out, res)}}func 区间最短距离和() {// https://yukicoder.me/problems/no/924// n,q<=2e5// -1e9 <= nums[i] <= 1e9// 给定n个查询[l,r]// !求区间[l,r]中位数到区间[l,r]中每个数的距离之和// !也就求函数 f(x)= ∑|nums[i]-x| (l<=i<=right) 的最小值// !区间中位数in := bufio.NewReader(os.Stdin)out := bufio.NewWriter(os.Stdout)defer out.Flush()var n, q intfmt.Fscan(in, &n, &q)OFFSET := int(1e9 + 10)nums := make([]int, n)for i := range nums {fmt.Fscan(in, &nums[i])nums[i] += OFFSET}preSum := make([]int, n+1)for i := range nums {preSum[i+1] = preSum[i] + nums[i]}wm := NewWaveletMatrixSum(nums, -1, func() int { return 0 }, func(a, b int) int { return a + b }, func(a int) int { return -a }, nil)for i := 0; i < q; i++ {var left, right intfmt.Fscan(in, &left, &right)left--n := right - leftlowerCount := n / 2ceilCount := n - lowerCountmid, lowerSum := wm.Kth(left, right, lowerCount, 0)_, allSum := wm.Kth(left, right, n, 0)ceilSum := allSum - lowerSumres := 0res += mid*lowerCount - lowerSumres += ceilSum - mid*ceilCountfmt.Fprintln(out, res)}}func abc281_e() {in := bufio.NewReader(os.Stdin)out := bufio.NewWriter(os.Stdout)defer out.Flush()var n, m, k intfmt.Fscan(in, &n, &m, &k)nums := make([]int, n)for i := range nums {fmt.Fscan(in, &nums[i])}wm := NewWaveletMatrixSum(nums, -1, func() int { return 0 }, func(a, b int) int { return a + b }, func(a int) int { return -a }, nil)for i := 0; i < n-m+1; i++ {_, res := wm.Kth(i, i+m, k, 0)fmt.Fprintln(out, res)}}func demo() {nums := []int{3, 1, 2, 4, 5, 6, 7, 8, 9, 10}wm := NewWaveletMatrixSum(nums, -1, func() int { return 0 }, func(a, b int) int { return a + b }, func(a int) int { return -a }, nil)fmt.Println(wm.CountRange(0, 10, 3, 7, 0))fmt.Println(wm.Kth(0, 10, 3, 0)) // 3fmt.Println(wm.MaxRightValue(0, 10, 0, func(preSum E) bool { return preSum < 11 })) // 5 即值域在 [0,5) 中的数的和小于 11fmt.Println(wm.MaxRightCount(0, 10, 0, func(preSum E) bool { return preSum < 11 })) // 4 即排序后前 4 个数的和小于 11fmt.Println(wm.Ceiling(0, 10, 3, 0))fmt.Println(wm.Floor(0, 10, 3, 0))}const INF int = 1e18type E = inttype WaveletMatrixSum struct {n, log intmid []intbv []*BitVectorpreSum [][]Eunit Ee func() Eop func(a, b E) Einv func(a E) E}// log:如果要支持异或,则需要按照异或的值来决定值域//// 设为-1时表示不使用异或func NewWaveletMatrixSum(nums []E, log int,e func() E, op func(a, b E) E, inv func(a E) E,// f: 求和的变换函数.nil表示不变换,即v.f func(v E) E,) *WaveletMatrixSum {numsCopy := make([]E, len(nums))max_ := 1for i, v := range nums {numsCopy[i] = vif v > max_ {max_ = v}}if log == -1 {log = bits.Len(uint(max_))}res := &WaveletMatrixSum{e: e, op: op, inv: inv}res.unit = res.e()n := len(numsCopy)mid := make([]int, log)bv := make([]*BitVector, log)for i := 0; i < log; i++ {bv[i] = NewBitVector(n)}preSum := make([][]E, log+1)for i := range preSum {preSum[i] = make([]E, n+1)for j := range preSum[i] {preSum[i][j] = res.unit}}a0, a1 := make([]E, n), make([]E, n)for d := log - 1; d >= -1; d-- {p0, p1 := 0, 0for i := 0; i < n; i++ {tmp := numsCopy[i]if f != nil {tmp = f(tmp)}preSum[d+1][i+1] = res.op(preSum[d+1][i], tmp)}if d == -1 {break}for i := 0; i < n; i++ {f := (numsCopy[i] >> d) & 1if f == 0 {a0[p0] = numsCopy[i]p0++} else {bv[d].Set(i)a1[p1] = numsCopy[i]p1++}}mid[d] = p0bv[d].Build()numsCopy, a0 = a0, numsCopyfor i := 0; i < p1; i++ {numsCopy[p0+i] = a1[i]}}res.n, res.log = n, logres.mid, res.bv, res.preSum = mid, bv, preSumreturn res}// 返回区间 [left, right) 中 范围在 [a, b) 中的 (元素的个数, op 的结果)func (wm *WaveletMatrixSum) CountRange(left, right, a, b, xor int) (int, E) {c1, s1 := wm.CountPrefix(left, right, a, xor)c2, s2 := wm.CountPrefix(left, right, b, xor)return c2 - c1, wm.op(wm.inv(s1), s2)}// 返回区间 [left, right) 中 范围在 [0, x) 中的 (元素的个数, op 的结果)func (wm *WaveletMatrixSum) CountPrefix(left, right, x, xor int) (int, E) {if x >= 1<<wm.log {return right - left, wm.get(wm.log, left, right)}count := 0sum := wm.unitfor d := wm.log - 1; d >= 0; d-- {add := (x >> d) & 1f := (xor >> d) & 1l0, r0 := wm.bv[d].Rank(left, 0), wm.bv[d].Rank(right, 0)kf := f*(right-left-r0+l0) + (f^1)*(r0-l0)if add == 1 {count += kfif f == 1 {sum = wm.op(sum, wm.get(d, left+wm.mid[d]-l0, right+wm.mid[d]-r0))left, right = l0, r0} else {sum = wm.op(sum, wm.get(d, l0, r0))left, right = left+wm.mid[d]-l0, right+wm.mid[d]-r0}} else if f == 0 {left, right = l0, r0} else {left, right = left+wm.mid[d]-l0, right+wm.mid[d]-r0}}return count, sum}// 返回区间 [left, right) 中的 (第k小的元素, 前k个元素(不包括第k小的元素) 的 op 的结果)//// 如果k < 0, 返回 (-1, 0); 如果k >= right-left, 返回 (-1, 区间 op 的结果)func (wm *WaveletMatrixSum) Kth(left, right, k, xor int) (int, E) {if k < 0 {return -1, 0}if right-left <= k {return -1, wm.get(wm.log, left, right)}res, sum := 0, wm.unitfor d := wm.log - 1; d >= 0; d-- {f := (xor >> d) & 1l0, r0 := wm.bv[d].Rank(left, 0), wm.bv[d].Rank(right, 0)kf := f*(right-left-r0+l0) + (f^1)*(r0-l0)if k < kf {if f == 0 {left, right = l0, r0} else {left, right = left+wm.mid[d]-l0, right+wm.mid[d]-r0}} else {k -= kfres |= 1 << dif f == 1 {sum = wm.op(sum, wm.get(d, left+wm.mid[d]-l0, right+wm.mid[d]-r0))left, right = l0, r0} else {sum = wm.op(sum, wm.get(d, l0, r0))left, right = left+wm.mid[d]-l0, right+wm.mid[d]-r0}}}if k != 0 {sum = wm.op(sum, wm.get(0, left, left+k))}return res, sum}// 返回使得 check(prefixSum) 为 true 的最大值 val.//// !(即区间内小于 val 的数的聚合值 prefixSum 满足 check函数, 找到这样的最大的 val)// 如果整个区间都满足, 返回 INF.// eg: val = 5 => 即区间内值域在 [0,5) 中的数的聚合值满足 check 函数.func (wm *WaveletMatrixSum) MaxRightValue(left, right, xor int, check func(preSum E) bool) E {if check(wm.get(wm.log, left, right)) {return INF}res := 0sum := wm.unitfor d := wm.log - 1; d >= 0; d-- {f := (xor >> d) & 1l0, r0 := wm.bv[d].Rank(left, 0), wm.bv[d].Rank(right, 0)var loSum Eif f == 0 {loSum = wm.get(d, l0, r0)} else {loSum = wm.get(d, left+wm.mid[d]-l0, right+wm.mid[d]-r0)}if check(wm.op(sum, loSum)) {sum = wm.op(sum, loSum)res |= 1 << dif f == 1 {left, right = l0, r0} else {left, right = left+wm.mid[d]-l0, right+wm.mid[d]-r0}} else if f == 0 {left, right = l0, r0} else {left, right = left+wm.mid[d]-l0, right+wm.mid[d]-r0}}return res}// 返回使得 check(prefixSum) 为 true 的区间前缀个数的最大值.//// eg: count = 4 => 即区间内的数排序后, 前4个数的和满足 check 函数.func (wm *WaveletMatrixSum) MaxRightCount(left, right, xor int, check func(preSum E) bool) int {if check(wm.get(wm.log, left, right)) {return right - left}res := 0sum := wm.unitfor d := wm.log - 1; d >= 0; d-- {f := (xor >> d) & 1l0, r0 := wm.bv[d].Rank(left, 0), wm.bv[d].Rank(right, 0)var kf intvar loSum Eif f == 0 {kf = r0 - l0loSum = wm.get(d, l0, r0)} else {kf = (right - left) - (r0 - l0)loSum = wm.get(d, left+wm.mid[d]-l0, right+wm.mid[d]-r0)}if check(wm.op(sum, loSum)) {sum = wm.op(sum, loSum)res += kfif f == 1 {left, right = l0, r0} else {left, right = left+wm.mid[d]-l0, right+wm.mid[d]-r0}} else if f == 0 {left, right = l0, r0} else {left, right = left+wm.mid[d]-l0, right+wm.mid[d]-r0}}res += wm.binarySearch(func(k int) bool {return check(wm.op(sum, wm.get(0, left, left+k)))}, 0, right-left)return res}// [left, right) 中小于等于 x 的数中最大的数//// 如果不存在则返回-INFfunc (w *WaveletMatrixSum) Floor(start, end, value, xor int) int {less, _ := w.CountPrefix(start, end, value, xor)if less == 0 {return -INF}res, _ := w.Kth(start, end, less-1, xor)return res}// [left, right) 中大于等于 x 的数中最小的数//// 如果不存在则返回INFfunc (w *WaveletMatrixSum) Ceiling(start, end, value, xor int) int {less, _ := w.CountPrefix(start, end, value, xor)if less == end-start {return INF}res, _ := w.Kth(start, end, less, xor)return res}func (wm *WaveletMatrixSum) binarySearch(f func(E) bool, ok, ng int) int {for abs(ok-ng) > 1 {x := (ok + ng) >> 1if f(x) {ok = x} else {ng = x}}return ok}func (wm *WaveletMatrixSum) get(d, l, r int) E {return wm.op(wm.inv(wm.preSum[d][l]), wm.preSum[d][r])}func abs(a int) int {if a < 0 {return -a}return a}type BitVector struct {bits []uint64preSum []int32}func NewBitVector(n int) *BitVector {return &BitVector{bits: make([]uint64, n>>6+1), preSum: make([]int32, n>>6+1)}}func (bv *BitVector) Set(i int) {bv.bits[i>>6] |= 1 << (i & 63)}func (bv *BitVector) Build() {for i := 0; i < len(bv.bits)-1; i++ {bv.preSum[i+1] = bv.preSum[i] + int32(bits.OnesCount64(bv.bits[i]))}}func (bv *BitVector) Rank(k int, f int) int {m, s := bv.bits[k>>6], bv.preSum[k>>6]res := int(s) + bits.OnesCount64(m&((1<<(k&63))-1))if f == 1 {return res}return k - res}// (紧)离散化.//// offset: 离散化的起始值偏移量.//// getRank: 给定一个数,返回它的排名`(offset ~ offset + count)`.// count: 离散化(去重)后的元素个数.func DiscretizeCompressed(nums []int, offset int) (getRank func(value int) int, getValue func(rank int) int, count int) {set := make(map[int]struct{}, len(nums))for _, v := range nums {set[v] = struct{}{}}count = len(set)rank := make([]int, 0, count)for v := range set {rank = append(rank, v)}sort.Ints(rank)mp := make(map[int]int, count)for i, v := range rank {mp[v] = i + offset}getRank = func(v int) int { return mp[v] }getValue = func(r int) int { return rank[r-offset] }count = len(nums)return}type Random struct {seed uint64hashBase uint64}func NewRandom() *Random { return &Random{seed: uint64(time.Now().UnixNano()/2 + 1)} }func NewRandomWithSeed(seed int) *Random { return &Random{seed: uint64(seed)} }func (r *Random) Rng() uint64 {r.seed ^= r.seed << 7r.seed ^= r.seed >> 9return r.seed}