結果
| 問題 | No.2694 The Early Bird Catches The Worm | 
| コンテスト | |
| ユーザー |  tnakao0123 | 
| 提出日時 | 2024-04-26 19:45:13 | 
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 59 ms / 2,000 ms | 
| コード長 | 982 bytes | 
| コンパイル時間 | 279 ms | 
| コンパイル使用メモリ | 41,340 KB | 
| 最終ジャッジ日時 | 2025-02-21 09:10:34 | 
| ジャッジサーバーID (参考情報) | judge3 / judge2 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 4 | 
| other | AC * 72 | 
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:30:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   30 |   scanf("%d%d", &n, &h);
      |   ~~~~~^~~~~~~~~~~~~~~~
main.cpp:31:36: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   31 |   for (int i = 0; i < n; i++) scanf("%d", as + i);
      |                               ~~~~~^~~~~~~~~~~~~~
main.cpp:32:36: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   32 |   for (int i = 0; i < n; i++) scanf("%d", bs + i);
      |                               ~~~~~^~~~~~~~~~~~~~
            
            ソースコード
/* -*- coding: utf-8 -*-
 *
 * 2694.cc:  No.2694 The Early Bird Catches The Worm - yukicoder
 */
#include<cstdio>
#include<algorithm>
 
using namespace std;
/* constant */
const int MAX_N = 200000;
/* typedef */
typedef long long ll;
/* global variables */
int as[MAX_N], bs[MAX_N];
ll ass[MAX_N + 1], bss[MAX_N + 1];
/* subroutines */
/* main */
int main() {
  int n, h;
  scanf("%d%d", &n, &h);
  for (int i = 0; i < n; i++) scanf("%d", as + i);
  for (int i = 0; i < n; i++) scanf("%d", bs + i);
  for (int i = 0; i < n; i++) ass[i + 1] = ass[i] + as[i];
  for (int i = 0; i < n; i++) bss[i + 1] = bss[i] + bs[i];
  ll maxx = 0, y = 0;
  for (int i = 0, j = 0; j < n; i++) {
    while (j < n && y + (ll)bs[j] * (j + 1 - i) <= h) {
      y += (ll)bs[j] * (j + 1 - i);
      j++;
    }
    maxx = max(maxx, ass[j] - ass[i]);
    //printf(" %d,%d: x=%lld, y=%lld\n", i, j, ass[j] - ass[i], y);
    y -= bss[j] - bss[i];
  }
  printf("%lld\n", maxx);
  
  return 0;
}
            
            
            
        