結果
問題 | No.2761 Substitute and Search |
ユーザー |
👑 |
提出日時 | 2024-04-30 19:45:21 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
TLE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 4,216 bytes |
コンパイル時間 | 4,729 ms |
コンパイル使用メモリ | 262,996 KB |
最終ジャッジ日時 | 2025-02-21 09:55:43 |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 12 TLE * 1 |
ソースコード
#include<bits/stdc++.h>#include<atcoder/all>#define rep(i,n) for(int i=0;i<n;i++)using namespace std;using namespace atcoder;typedef long long ll;typedef vector<int> vi;typedef vector<long long> vl;typedef vector<vector<int>> vvi;typedef vector<vector<long long>> vvl;typedef long double ld;typedef pair<int, int> P;ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); returnos;}template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : "");return os;}template<typename T> void chmin(T& a, T b){a = min(a, b);}template<typename T> void chmax(T& a, T b){a = max(a, b);}random_device rd;mt19937 mt(rd());int random_prime(){while (true){int pr = mt() % 100000000 + 900000000;if (atcoder::internal::is_prime_constexpr(pr)){return pr;}}}using ull = unsigned long long;using mint1 = atcoder::dynamic_modint<1>;using mint2 = atcoder::dynamic_modint<2>;struct mints{mint1 d1;mint2 d2;mints(long long val = 0) : d1(val), d2(val) {}mints(mint1 d1, mint2 d2) : d1(d1), d2(d2) {}mints& operator++() {d1++; d2++;return *this;}mints& operator--() {d1--; d2--;return *this;}mints& operator+=(const mints& a) {d1 += a.d1; d2 += a.d2;return *this;}mints& operator-=(const mints& a) {d1 -= a.d1; d2 -= a.d2;return *this;}mints& operator*=(const mints& a) {d1 *= a.d1; d2 *= a.d2;return *this;}mints& operator/=(const mints& a) { return *this = *this * a.inv(); }mints operator+() const { return *this; }mints operator-() const { return mints(0) - *this; }mints pow(long long n) const {return mints(d1.pow(n), d2.pow(n));}mints inv() const {return mints(d1.inv(), d2.inv());}mints operator+(const mints& a) const {return mints(d1 + a.d1, d2 + a.d2);}mints operator-(const mints& a) const {return mints(d1 - a.d1, d2 - a.d2);}mints operator*(const mints& a) const {return mints(d1 * a.d1, d2 * a.d2);}mints operator/(const mints& a) const {return mints(d1 / a.d1, d2 / a.d2);}bool operator==(const mints& a) const {return d1 == a.d1 and d2 == a.d2;}bool operator!=(const mints& a) const {return d1 != a.d1 or d2 != a.d2;}ull get_hash(){return (ull(d1.val()) << 32) + ull(d2.val());};};ostream& operator<<(ostream& os, const mints& a) {os << a.d1 << '&' << a.d2; return os;}const int base = 334;struct S{mints val, c;S(mints val, mints c) : val(val), c(c) {}};S op(S a, S b){S res(a.val * b.c + b.val, a.c * b.c);return res;}S e(){S e(mints(0), mints(1));return e;}int main(){{const int p1 = random_prime();const int p2 = random_prime();mint1::set_mod(p1);mint2::set_mod(p2);}int n, l, q;cin >> n >> l >> q;vector<string> s(n);cin >> s;vector<segtree<S, op, e>> seg;rep(i, n){vector<S> init(l, S(mints(0), base));rep(j, l) init[j] = S(mints(s[i][j] - 'a'), base);segtree<S, op, e> seg_sub(init);seg.push_back(seg_sub);}rep(_, q){int t;cin >> t;if(t == 1){int k;char c, d;cin >> k >> c >> d;k--;rep(i, n){if(s[i][k] == c){s[i][k] = d;seg[i].set(k, S(mints(d - 'a'), base));}}}if(t == 2){string t;cin >> t;int m = t.size();mints rh(0);int ans = 0;rep(j, m){rh *= base;rh += t[j] - 'a';}rep(i, n){auto [val, c] = seg[i].prod(0, m);if(val == rh) ans++;}cout << ans << "\n";}}return 0;}