結果
問題 | No.2408 Lakes and Fish |
ユーザー | vjudge1 |
提出日時 | 2024-05-01 11:27:03 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 57 ms / 2,000 ms |
コード長 | 3,590 bytes |
コンパイル時間 | 2,360 ms |
コンパイル使用メモリ | 206,344 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-05-01 11:27:19 |
合計ジャッジ時間 | 4,433 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
6,812 KB |
testcase_01 | AC | 2 ms
6,944 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,940 KB |
testcase_04 | AC | 44 ms
6,944 KB |
testcase_05 | AC | 44 ms
6,940 KB |
testcase_06 | AC | 44 ms
6,940 KB |
testcase_07 | AC | 56 ms
6,940 KB |
testcase_08 | AC | 57 ms
6,940 KB |
testcase_09 | AC | 57 ms
6,940 KB |
testcase_10 | AC | 57 ms
6,940 KB |
testcase_11 | AC | 30 ms
6,944 KB |
testcase_12 | AC | 41 ms
6,944 KB |
testcase_13 | AC | 12 ms
6,940 KB |
testcase_14 | AC | 24 ms
6,940 KB |
testcase_15 | AC | 46 ms
6,940 KB |
testcase_16 | AC | 17 ms
6,944 KB |
testcase_17 | AC | 14 ms
6,944 KB |
testcase_18 | AC | 27 ms
6,944 KB |
testcase_19 | AC | 45 ms
6,940 KB |
testcase_20 | AC | 41 ms
6,944 KB |
testcase_21 | AC | 46 ms
6,944 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #define int long long #define ll long long #define ld long double #define pb push_back #define endl '\n' #define all(v) v.begin(), v.end() #define all1(v) v.begin() + 1, v.end() #define rall(v) v.rbegin(), v.rend() #define rall1(v) v.rbegin(), v.rend()-1 #define fr(m,n,k) for(int m=n;m<=k;m++) #define frr(m,n,k) for(int m=n;m>=k;m--) #define yes cout << "YES" #define no cout << "NO" #define yesm cout << "Yes" #define nom cout << "No" #define inf 1e18 #define ext {cout << -1; return;} #define zxt {cout << 0; return;} #define noxt {no;return;} #define yesxt {yes;return;} #define gcd(a,b) __gcd(a,b) #define lcm(a,b) (a*(b/gcd(a,b))) #define fill(x,s) memset(x, s, sizeof(x)); #define lb lower_bound #define ub upper_bound #define pi pair<int,int> #define vi vector<int> #define vvi vector<vi> #define vs vector<string> #define vpi vector<pi> #define mii map<int,int> #define si set<int> #define fi first #define se second #define sz size() #define el cout<<endl int mod = 1e9 + 7; // int mod = 998244353; int ft(int n) {int ans = 1; for (int i = 1; i <= n; ++i) {ans = ans * i;} return ans;} int binpow(int x, int y) {if (y == 0) return 1; int z = 1; while (y) { if (y & 1) z = z * x % mod; x = x * x % mod; y >>= 1;} return z;} int inv(int x) {return binpow(x, mod - 2);} int bintoint(string s) {reverse(all(s)); int xx = 0; int m = 1; int z = s.sz; fr(j, 0, z) {xx += (s[j] == '1' ? m : 0); m <<= 1;} return xx;} string inttobin(int x) {if (x == 0) return "0"; string s; while (x) {s += (x & 1) + '0'; x >>= 1;} reverse(all(s)); return s;} string ads(string s, string p) {if (s.sz > p.sz) swap(s, p); int n = s.sz, m = p.sz; reverse(all(s)); reverse(all(p)); int tm = 0; string st; fr(i, 0, n - 1) {tm = s[i] - '0' + p[i] - '0' + tm; st += '0' + tm % 10; tm /= 10;} fr(i, n, m - 1) {tm = p[i] - '0' + tm; st += '0' + tm % 10; tm /= 10;} if (tm != 0) {st += '0' + tm % 10;} reverse(all(st)); return st;} bool id, id1, id2; int n, m, k, l, r, a, b, c, d, e, x, y, z, i, j, q, t, o; int mi = inf, ma, sum, ans, num, cnt; string s, p; const int N = 5e3 + 5; void solve() { cin >> n >> m; vi v(n + 1); fr(i, 1, n) { cin >> v[i]; } ans = 0; fr(i, 1, m) { int f, b, w; cin >> f >> b >> w; auto x = lb(all(v), f) - v.begin(); if (v[x] == f) { ans += w; } else { // cout << v[x] << " "; l = inf; if (x <= n) l = v[x] - f; if (x > 1) l = min(l, f - v[x - 1]); ans += max(b, w - l); } // cout << ans << " "; } cout << ans; } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(0); int T = 1; // cin >> T; for (; T--;) { cout << fixed << setprecision(12); solve(); if (T) cout << endl; } return 0; } // Tc, angka kecil), No Overthink(trivial tp modified), // Check Kasus Khusus(1,2,1e18), ganti jd bentuk lain (2 case or etc) // bedah 1 1 variable yg bisa dicari, cari dari jwbn ke ques // Sorting : Iterate Greedy (pake data struct) / dp / binser // Graphs / Tree : DFS / adj / dis[a][b] != dis[a][c] + dis[c][b] / indegree // Yang keliatan kyk dp : bisa jd brute force doang // Data Structure : BIT / DSU / Segtree, SparseT / dequeue // Compression, Line Sweep // Parity (2 or 3, mod 4..) klo dilakuin 2 kali jadi sama aja -> parity mod 2 /* brute force, greedy, pref sum, 2pointer, gcd/lcm, even/odd min/max, binser, bfs/dfs, iterate, multiple/divisor bipartite graph,bitmasking, sliding window, konstanta divconquer, djikstra, stack(prev and next smaller) prefix difference */ // tools : //__lg(x),__builtinpopcount,nextpermutation(), is_sorted / alpha / digit,