結果
| 問題 |
No.2308 [Cherry 5th Tune B] もしかして、真?
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2024-05-04 16:17:25 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,694 bytes |
| コンパイル時間 | 380 ms |
| コンパイル使用メモリ | 82,304 KB |
| 実行使用メモリ | 398,784 KB |
| 最終ジャッジ日時 | 2024-11-26 04:51:58 |
| 合計ジャッジ時間 | 97,144 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 2 TLE * 37 |
ソースコード
class UnionFind:
def __init__(self, n):
self.n = n
self.par = [-1] * n
self.group_ = n
self.R = [i for i in range(n)]
def find(self, x):
if self.par[x] < 0:
return x
lst = []
while self.par[x] >= 0:
lst.append(x)
x = self.par[x]
for y in lst:
self.par[y] = x
return x
def unite(self, x, y):
x = self.find(x)
y = self.find(y)
if x == y:
return False
if self.par[x] > self.par[y]:
x, y = y, x
self.par[x] += self.par[y]
self.par[y] = x
self.group_ -= 1
self.R[x] = max(self.R[x], self.R[y])
return True
def size(self, x):
return -self.par[self.find(x)]
def same(self, x, y):
return self.find(x) == self.find(y)
@property
def group(self):
return self.group_
class BIT:
def __init__(self, n):
self.n = n
self.data = [0] * (n + 1)
if n == 0:
self.n0 = 0
else:
self.n0 = 1 << (n.bit_length() - 1)
def sum_(self, i):
s = 0
while i > 0:
s += self.data[i]
i -= i & -i
return s
def sum(self, l, r=-1):
if r == -1:
return self.sum_(l)
else:
return self.sum_(r) - self.sum_(l)
def get(self, i):
return self.sum(i, i + 1)
def add(self, i, x):
i += 1
while i <= self.n:
self.data[i] += x
i += i & -i
def lower_bound(self, x):
if x <= 0:
return 0
i = 0
k = self.n0
while k > 0:
if i + k <= self.n and self.data[i + k] < x:
x -= self.data[i + k]
i += k
k //= 2
return i + 1
def solve():
n = int(input())
X = list(map(eval, input().split()))
Y = input().split()
S = list(map(int, input().split()))
bit = BIT(n)
for i in range(n):
bit.add(i, 1)
for i, s in enumerate(S):
p = bit.lower_bound(s)
bit.add(p - 1, -1)
S[i] = p - 1
UF = UnionFind(n)
for s in S:
y = Y[s]
u = UF.find(s)
v = UF.find(UF.R[u] + 1)
UF.unite(u, v)
p = UF.find(u)
if y == "and":
nex = X[u] & X[v]
elif y == "or":
nex = X[u] | X[v]
elif y == "xor":
nex = X[u] ^ X[v]
else:
if X[u]:
nex = X[v]
else:
nex = True
X[p] = nex
print(X[UF.find(0)])
for _ in range(int(input())):
solve()