結果

問題 No.2732 Similar Permutations
ユーザー au7777
提出日時 2024-05-07 00:16:21
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 102 ms / 2,000 ms
コード長 4,982 bytes
コンパイル時間 4,333 ms
コンパイル使用メモリ 249,496 KB
実行使用メモリ 6,000 KB
最終ジャッジ日時 2024-11-29 11:28:04
合計ジャッジ時間 21,541 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 101
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#include <atcoder/all>
typedef long long int ll;
using namespace std;
typedef pair<ll, ll> P;
using namespace atcoder;
template<typename T> using min_priority_queue = priority_queue<T, vector<T>, greater<T>>;
#define USE998244353
#ifdef USE998244353
const ll MOD = 998244353;
using mint = modint998244353;
#else
const ll MOD = 1000000007;
using mint = modint1000000007;
#endif
#pragma region //使
const int MAX = 2000001;
long long fac[MAX], finv[MAX], inv[MAX];
void COMinit() {
fac[0] = fac[1] = 1;
finv[0] = finv[1] = 1;
inv[1] = 1;
for (int i = 2; i < MAX; i++){
fac[i] = fac[i - 1] * i % MOD;
inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
finv[i] = finv[i - 1] * inv[i] % MOD;
}
}
long long COM(int n, int k){
if (n < k) return 0;
if (n < 0 || k < 0) return 0;
return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}
ll gcd(ll x, ll y) {
if (y == 0) return x;
else if (y > x) {
return gcd (y, x);
}
else return gcd(x % y, y);
}
ll lcm(ll x, ll y) {
return x / gcd(x, y) * y;
}
ll my_sqrt(ll x) {
//
ll m = 0;
ll M = 3000000001;
while (M - m > 1) {
ll now = (M + m) / 2;
if (now * now <= x) {
m = now;
}
else {
M = now;
}
}
return m;
}
ll keta(ll num, ll arity) {
ll ret = 0;
while (num) {
num /= arity;
ret++;
}
return ret;
}
ll ceil(ll n, ll m) {
// n > 0, m > 0
ll ret = n / m;
if (n % m) ret++;
return ret;
}
ll pow_ll(ll x, ll n) {
if (n == 0) return 1;
if (n % 2) {
return pow_ll(x, n - 1) * x;
}
else {
ll tmp = pow_ll(x, n / 2);
return tmp * tmp;
}
}
void compress(vector<ll>& v) {
// [3 5 5 6 1 1 10 1] -> [1 2 2 3 0 0 4 0]
vector<ll> u = v;
sort(u.begin(), u.end());
u.erase(unique(u.begin(),u.end()),u.end());
map<ll, ll> mp;
for (int i = 0; i < u.size(); i++) {
mp[u[i]] = i;
}
for (int i = 0; i < v.size(); i++) {
v[i] = mp[v[i]];
}
}
// N
vector<ll> Eratosthenes( const ll N )
{
vector<bool> is_prime( N + 1 );
for( ll i = 0; i <= N; i++ )
{
is_prime[ i ] = true;
}
vector<ll> P;
for( ll i = 2; i <= N; i++ )
{
if( is_prime[ i ] )
{
for( ll j = 2 * i; j <= N; j += i )
{
is_prime[ j ] = false;
}
P.emplace_back( i );
}
}
return P;
}
vector<pair<ll, ll> > prime_factorize(ll N) {
vector<pair<ll, ll> > res;
for (ll a = 2; a * a <= N; ++a) {
if (N % a != 0) continue;
ll ex = 0; //
//
while (N % a == 0) {
++ex;
N /= a;
}
// push
res.push_back({a, ex});
}
//
if (N != 1) res.push_back({N, 1});
return res;
}
#pragma endregion
int xor_sum = 0;
// next_permutation
// axor
void next_permutation(vector<int>& v, vector<int>& a) {
int n = v.size();
int i = n - 1;
while (i > 0 && v[i - 1] >= v[i]) {
i--;
}
if (i == 0) {
for (int j = 0; j < n; j++) {
v[j] = j + 1;
}
return ;
}
int j = n - 1;
while (v[j] <= v[i - 1]) {
j--;
}
xor_sum ^= (a[i - 1] + v[i - 1]);
xor_sum ^= (a[j] + v[j]);
xor_sum ^= (a[i - 1] + v[j]);
xor_sum ^= (a[j] + v[i - 1]);
swap(v[i - 1], v[j]);
j = n - 1;
while (i < j) {
xor_sum ^= (a[i] + v[i]);
xor_sum ^= (a[j] + v[j]);
xor_sum ^= (a[i] + v[j]);
xor_sum ^= (a[j] + v[i]);
swap(v[i], v[j]);
i++;
j--;
}
}
// ipermutation
void output(int i, int n, vector<int>& a) {
vector<int> v(n);
for (int j = 0; j < n; j++) {
v[j] = j + 1;
}
for (int j = 0; j < i; j++) {
next_permutation(v, a);
}
for (int j = 0; j < n; j++) {
cout << v[j] << " ";
}
cout << '\n';
}
int main() {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
vector<int> v(n);
for (int i = 0; i < n; i++) {
v[i] = i + 1;
xor_sum ^= (a[i] + v[i]);
}
map<int, int> mp;
int M = 800000;
int xx = 1;
for (int i = 1; i <= n; i++) {
if (xx * i >= M) break;
xx *= i;
}
M = min(M, xx);
for (int i = 0; i < xx; i++) {
if (mp.find(xor_sum) != mp.end()) {
int id1 = i;
int id2 = mp[xor_sum];
cerr << id1 << " " << id2 << '\n';
output(id1, n, a);
output(id2, n, a);
exit(0);
}
mp[xor_sum] = i;
next_permutation(v, a);
}
cout << -1 << '\n';
return 0;
}
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