結果

問題 No.363 門松サイクル
ユーザー paruki
提出日時 2016-06-17 02:19:13
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 159 ms / 4,000 ms
コード長 3,607 bytes
コンパイル時間 1,883 ms
コンパイル使用メモリ 176,504 KB
実行使用メモリ 22,144 KB
最終ジャッジ日時 2024-10-11 05:16:04
合計ジャッジ時間 5,636 ms
ジャッジサーバーID
(参考情報)
judge2 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 27
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include "bits/stdc++.h"
using namespace std;
#define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i))
#define rep(i,j) FOR(i,0,j)
#define each(x,y) for(auto &(x):(y))
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define debug(x) cout<<#x<<": "<<(x)<<endl
#define smax(x,y) (x)=max((x),(y))
#define smin(x,y) (x)=min((x),(y))
#define MEM(x,y) memset((x),(y),sizeof (x))
#define sz(x) (int)(x).size()
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<ll> vll;
class LCA{
public:
LCA(){ }
LCA(const vector<vector<int>> &G, int root = 0):V((int)G.size()), depth(V), parent(V){
rep(i, LG)ancestor[i] = vector<int>(V);
dfs(root, 0, 0, G);
rep(i, V)
ancestor[0][i] = parent[i];
rep(i,LG-1)rep(v,V)
ancestor[i + 1][v] = ancestor[i][ancestor[i][v]];
}
int get(int u, int v){
if(depth[u] < depth[v]) swap(u, v);
int dist = depth[u] - depth[v];
for(int i = 0; i < LG; ++i)
if((dist >> i) & 1)
u = ancestor[i][u];
if(u == v) return u;
for(int i = LG - 1; i >= 0; --i){
if(ancestor[i][u] != ancestor[i][v]){
u = ancestor[i][u];
v = ancestor[i][v];
}
}
return ancestor[0][u];
}
int getDepth(int u){
return depth[u];
}
int goUp(int u, int len){
for(int i = 0; i < LG; ++i)
if(len >> i & 1)u = ancestor[i][u];
return u;
}
int distance(int u, int v){
return depth[u] + depth[v] - 2 * depth[get(u, v)];
}
int getParent(int u){
return parent[u];
}
private:
static const int LG = 18;
int V;
vector<int> depth, parent, ancestor[LG];
void dfs(int v, int p, int d, const vector<vector<int>> &G){
depth[v] = d;
parent[v] = p;
for(int to : G[v]){
if(to != p){
dfs(to, v, d + 1, G);
}
}
}
};
const int N_MAX = (int)1e5 + 9;
int N, A[N_MAX], kad[N_MAX];
vector<vector<int>> G;
LCA lca;
bool isK(int a, int b, int c){
return (a!=b&&b!=c&&c!=a)&&((a<b&&b>c)||(a>b&&b<c));
}
void dfs(int u, int v, int w){
if(w != -1 && isK(A[u], A[v], A[w]))kad[u] = kad[v] + 1;
each(to, G[u])if(to != v)dfs(to, u, v);
}
void init(){
cin >> N;
G.resize(N);
rep(i, N)scanf("%d", &A[i]);
rep(i, N - 1){
int u, v;
scanf("%d%d", &u, &v);
G[--u].push_back(--v);
G[v].push_back(u);
}
lca = LCA(G);
dfs(0, -1, -1);
}
int solve(int u, int v){
int duv = lca.distance(u, v);
if(duv < 2)return 0;
int w = lca.get(u, v);
if(w != u&&w != v){
int dwu = lca.getDepth(u) - lca.getDepth(w);
int dwv = lca.getDepth(v) - lca.getDepth(w);
if(kad[u] < dwu - 1 || kad[v] < dwv - 1)return 0;
int uu = lca.goUp(u, dwu - 1);
int vv = lca.goUp(v, dwv - 1);
if(!isK(A[uu], A[w], A[vv]))return 0;
int pu = lca.getParent(u);
int pv = lca.getParent(v);
if(!isK(A[pu], A[u], A[v]))return 0;
if(!isK(A[u], A[v], A[pv]))return 0;
} else{
if(u == w)swap(u, v);
if(kad[u] < duv - 1)return 0;
int pu = lca.getParent(u);
if(!isK(A[pu], A[u], A[v]))return 0;
int vc = lca.goUp(u, duv - 1);
if(!isK(A[u], A[v], A[vc]))return 0;
}
return 1;
}
int main(){
init();
int Q;
cin >> Q;
while(Q--){
int u, v;
scanf("%d%d", &u, &v);
puts(solve(--u, --v) ? "YES" : "NO");
}
}
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