結果

問題 No.2753 鳩の巣原理
コンテスト
ユーザー GOTKAKO
提出日時 2024-05-10 21:53:22
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 2,335 bytes
コンパイル時間 2,119 ms
コンパイル使用メモリ 194,348 KB
最終ジャッジ日時 2025-02-21 12:40:24
ジャッジサーバーID
（参考情報） 		judge3 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 18 WA * 12
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:76:39: warning: ‘ans1’ may be used uninitialized [-Wmaybe-uninitialized]
   76 |     cout << "Yes" << " " << ans1+1 << " " << ans2+1 << endl;
      |                                       ^~~
main.cpp:61:24: note: ‘ans1’ was declared here
   61 |     int turn = 0,L = 0,ans1,ans2;
      |                        ^~~~
main.cpp:76:51: warning: ‘ans2’ may be used uninitialized [-Wmaybe-uninitialized]
   76 |     cout << "Yes" << " " << ans1+1 << " " << ans2+1 << endl;
      |                                                   ^
main.cpp:61:29: note: ‘ans2’ was declared here
   61 |     int turn = 0,L = 0,ans1,ans2;
      |                             ^~~~

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;

long long mod = 998244353;
//入力が必ずmod未満の時に使う.
struct mint{
    long long v = 0;
    mint(){} mint(int a){v = a;} mint(long long a){v = a;} mint(unsigned long long a){v = a;}
    long long val(){return v;}
    void modu(){v %= mod;}
 
    mint repeat2mint(const long long a,long long b){
        mint ret = 1,p = a;
        while(b){
            if(b&1) ret *= p;
            p *= p; b >>= 1;
        }
        return ret;
    };
 
    mint operator+(const mint b){return mint(v)+=b;}
    mint operator-(const mint b){return mint(v)-=b;}
    mint operator*(const mint b){return mint(v)*=b;}
    mint operator/(const mint b){return mint(v)/=b;}
 
    mint operator+=(const mint b){
        v += b.v; if(v >= mod) v -= mod;
        return *this;
    }
    mint operator-=(const mint b){
        v -= b.v; if(v < 0) v += mod; 
        return *this;
    }   
    mint operator*=(const mint b){v = v*b.v%mod; return *this;}
    mint operator/=(mint b){
        if(b == 0) assert(false);
        int left = mod-2;
        while(left){if(left&1) *this *= b; b *= b; left >>= 1;}
        return *this;
    }
 
    mint operator++(int){*this += 1; return *this;}
    mint operator--(int){*this -= 1; return *this;}
    bool operator==(const mint b){return v == b.v;}
    bool operator!=(const mint b){return v != b.v;}
    bool operator>(const mint b){return v > b.v;}
    bool operator>=(const mint b){return v >= b.v;}
    bool operator<(const mint b){return v < b.v;}
    bool operator<=(const mint b){return v <= b.v;}
    
    mint pow(const long long x){return repeat2mint(v,x);}
    mint inv(){return mint(1)/v;}
};

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);

    int N; cin >> N;
    int low = 0,high = N;
    int turn = 0,L = 0,ans1,ans2;
    while(high-low > 1){
        int mid = (low+high)/2; turn++;
        cout << "? " << mid+1 << endl;
        int now; cin >> now;
        if(mid-low > now-L){
            if(mid-low == 1){ans1 = low,ans2 = mid;}
            high = mid;
        }
        else{
            if(high-mid == 1){ans1 = mid,ans2 = high;}
            low = mid,L = now; 
        }
    }
    while(turn < 10){cout << "? 1" << endl; cin >> high; turn++;}
    cout << "Yes" << " " << ans1+1 << " " << ans2+1 << endl; 
}
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